Table of Contents
Exercise Ex. 6.1
Solution 1
Solution 2
Solution 3
Solution 4
Solution 5
Solution 6
Solution 7
Solution 8
Solution 9
Solution 10
Solution 11
Solution 12
Solution 13
Solution 14
Solution 15
Solution 16
Solution 17
Solution 18
Solution 19
Solution 20
Solution 21
Solution 22
Solution 23
Solution 24
Solution 25
Solution 26
Exercise Ex. 6.2
Solution 1
Solution 2
Solution 3
Solution 4
Solution 5
Solution 6
Solution 7
Solution 8
Solution 9
Solution 10
Exercise Ex. 6.3
Solution 1
Solution 2
Solution 3
Solution 4
x + y ≥ 4 … (1)
2x – y < 0 … (2)
The graph of the lines, x + y = 4 and 2x – y = 0 are drawn in the figure below.
Inequality (1) represents the region above the line x + y = 4. (including the line x + y = 4)
It is observed that (–1, 0) satisfies the inequality, 2x – y < 0.
[2(-1) – 0 = -2< 0]
Therefore, inequality (2) represents the half plane corresponding to the line, 2x – y = 0 containing the point (-1, 0). [excluding the line 2x – y < 0]
Hence, the solution of the given system of linear inequalities is represented by the common shaded region including the points on the line x + y = 4 and excluding the points on line 2x – y = 0 as follows:
Solution 5
Solution 6
Solution 7
Solution 8
Solution 9
Solution 10
Solution 11
Solution 12
Solution 13
Solution 14
Solution 15
Exercise Misc. Ex.
Solution 1
Solution 2
Solution 3
Solution 4
Solution 5
Solution 6
Solution 7
Solution 8
Solution 9
Solution 10
Solution 11
Solution 12
Solution 13
Solution 14
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