Table of Contents
Exercise Ex. 6D
Question 1
Points A(-1, y) and B(5, 7) lie on a circle with centre O(2, -3y). Find the values of y.Solution 1
Question 2
If the point A(0, 2) is equidistant from the points B(3, p) and C(p, 5), find p.Solution 2
Question 3
ABCD is a rectangle whose three vertices are B(4, 0), C(4, 3) and D(0, 3). Find the length of one of its diagonal.Solution 3
Question 4
If the point P(k – 1, 2) is equidistant from the points A(3, k) and B(k, 5), find the values of k.Solution 4
Question 5
Find the ratio in which the point P(x, 2) divides the join of A(12, 5) and B(4, -3).Solution 5
Question 6
Prove that the diagonals of a rectangle ABCD with vertices A(2, -1), B(5, -1), C(5, 6) and D(2, 6) are equal and bisect each other.Solution 6
Question 7
Find the lengths of the medians AD and BE of ∆ABC whose vertices are A(7, -3), B(5, 3) and C(3, -1).Solution 7
Question 8
If the point C(k, 4) divides the join of A(2, 6) and B(5, 1) in the ratio 2 : 3 then find the value of k.Solution 8
Question 9
Find the point on x-axis which is equidistant from points A(-1, 0) and B(5, 0).Solution 9
Question 10
Find the distance between the points .Solution 10
Distance between the points
Question 11
Find the value of a, so that the point (3, a) lies on the line represented by 2x – 3y = 5.Solution 11
Question 12
If the points A(4, 3) and B(x, 5) lie on the circle with centre O(2, 3), find the value of x.Solution 12
The points A(4,3) and B(x, 5) lie on the circle with center O(2,3)
OA and OB are radius of the circle.
Question 13
If P(x, y) is equidistant from the points A(7, 1) and B(3, 5), find the relation between x and y.Solution 13
The point P(x, y) is equidistant from the point A(7, 1) and B(3, 5)
Question 14
If the centroid of ABC having vertices A(a, b), B(b, c) and C(c, a) is the origin, then find the value of (a + b + c).Solution 14
The vertices of ABC are (a, b), (b, c) and (c, a)
Centroid is
But centroid is (0, 0)
a + b + c = 0Question 15
Find the centroid of ABC whose vertices are A(2, 2), B(-4, -4) and C(5, -8).Solution 15
The vertices of ABC are A(2, 2), B(-4, -4) and C(5, -8)
Centroid of ABC is given by
Question 16
In what ratio does the point C(4, 5) divide the join of A(2, 3) and B(7 , 8)?Solution 16
Let the point C(4, 5) divides the join of A(2, 3) and B(7, 8) in the ratio k : 1
The point C is
But C is (4, 5)
Thus, C divides AB in the ratio 2 : 3Question 17
If the points A(2, 3), B(4, k)and C(6, -3) are collinear, find the value of k.Solution 17
The points A(2, 3), B(4, k) and C(6, -3) are collinear if area of ABC is zero
But area of ABC = 0,
k = 0
Exercise Ex. 6C
Question 9
A(6, 1), B(8, 2) and C(9, 4) are the vertices of a parallelogram ABCD. If E is the midpoint of DC, find the area of ∆ADE.Solution 9
Question 1
Find the area of ABC, whose vertices are:
(i)A(1, 2), B(-2, 3) and C(-3, -4)
(ii)A(-5, 7), B(-4, -5) and C(4, 5)
(iii)A(3, 8), B(-4, 2) and C(5, -1)
(iv)A(10, -6), B(2, 5) and C(-1, 3)Solution 1
(i)Let A(1, 2), B(-2, 3) and C(-3, -4) be the vertices ofthe given ABC, then
(ii)The coordinates of vertices of ABC are A(-5, 7), B(-4, -5) and C(4, 5)
Here,
(iii)The coordinates of ABC are A(3, 8), B(-4, 2) and C(5, -1)
(iv)Let P(10, -6), Q(2, 5) and R(-1, 3) be the vertices of the given PQR. Then,
Question 2
Find the area of quadrilateral ABCD whose vertices are A(3, -1), B(9, -5), C(14, 0) and D(9, 19).Solution 2
Question 3
Find the area of quadrilateral PQRS whose vertices are P(-5, -3), Q(-4, -6), R(2, -3) and S(1, 2).Solution 3
Question 4
Find the area of quadrilateral ABCD whose vertices are A(-3, -1), B(-2, -4), C(4, -1) and D(3, 4).Solution 4
Question 5
Find the area of quadrilateral ABCD whose vertices are A(-5, 7), B(-4, -5), C(-1, -6) and D(4, 5).Solution 5
Question 6
Find the area of the triangle formed by joining the midpoints of the sides of the triangle whose vertices are A(2, 1), B(4, 3) and C(2, 5).Solution 6
Question 7
A(7, -3), B(5, 3) and C(3, -1) are the vertices of a ∆ABC and AD is its median. Prove that the median AD divides ∆ABC into two triangles of equal areas.Solution 7
Question 8
Find the area of ∆ABC with A(1, -4) and midpoints of sides through A being (2, -1) and (0, -1).Solution 8
Question 10(i)
If the vertices of ∆ABC be A(1, -3), B(4, p) and C(-9, 7) 15 square units, find the values of p.Solution 10(i)
Question 11
Find the value of k so that the area of the triangle with vertices A(k + 1, 1), B(4, -3) and C(7, -k) is 6 square units.Solution 11
Question 12
For what value of k(k > 0) is the area of the triangle with vertices (-2, 5), (k, -4) and (2k + 1, 10) equal to 53 square units?Solution 12
Question 13(i)
Show that the following points are collinear.
A(2, -2), B(-3, 8) and C(-1, 4)Solution 13(i)
Question 13(ii)
Show that the following points are collinear.
A(-5, 1), B(5, 5) and C(10, 7)Solution 13(ii)
Question 13(iii)
Show that the following points are collinear.
A(5, 1), B(1, -1) and C(11, 4)Solution 13(iii)
Question 13(iv)
Show that the following points are collinear.
A(8, 1), B(3, -4) and C(2, -5)Solution 13(iv)
Question 14
Find the value of x for which the points A(x, 2), B(-3, -4) and C(7, -5) are collinear.Solution 14
Question 15
For what value of x are the points A(-3, 12), B(7, 6) and C(x, 9) collinear?Solution 15
The given points are A(-3, 12), B(7, 6) and C(x, 9)
Question 16
For what value of y are the points P(1, 4), Q(3, y) and R(-3, 16) collinear?Solution 16
Let P(1, 4), Q(3, y) and R(-3, 16)
Question 17
Find the value of y for which the points A(-3, 9), B(2, y) and C(4, -5) are collinear.Solution 17
Question 18
For what values of k are the points A(8, 1), B(3, -2k) and C(k, -5) collinear.Solution 18
Question 19
Find a relation between x and y, if the points A(2, 1), B(x, y) and C(7, 5) are collinear.Solution 19
Vertices of ABC are A(2, 1), B(x, y) and C(7, 5)
The points A, B and C are collinear
area of ABC =0
Or 4x – 5y – 3 = 0Question 20
Find a relation between x and y, if the points A(x, y), B(-5,7) and C(-4, 5) are collinear.Solution 20
Question 21
Prove that the points A(a, 0), B(0, b) and C(1, 1) are collinear, if .Solution 21
The vertices of ABC are (a, 0), (0, b), C(1, 1)
The points A, B, C are collinear
Area of ABC = 0
ab – a – b = 0 a + b = ab
Dividing by ab
Question 22
If the points P(-3, 9), Q(a, b) and R(4, -5) are collinear and a + b = 1. find the values of a and b.Solution 22
Question 23
Find the area of ∆ABC with vertices A(0, -1), B(2, 1) and C(0, 3). Also, find the area of the triangle formed by joining the midpoints of its sides. Show that the ratio of the areas of two triangles is 4 :1.Solution 23
Exercise Ex. 6A
Question 12
If P(x, y) is a point equidistant from the points A(6, -1) and B(2, 3). Show that x – y = 3Solution 12
Let A(6, -1) and B(2,3) be the given point and P(x,y) be the required point, we get
Question 1
Find the distance between the points:
(i)A(9,3) and B(15, 11)
(ii)A(7, -4) and B(-5, 1)
(iii)A(-6, -4) and B(9, -12)
(iv)A(1, -3) and B(4, -6)
(v)P(a + b, a – b) and Q(a – b, a + b)
(vi)P(a sin a, a cos a) and Q(a cos a, -a sin a)Solution 1
(i)The given points are A(9,3) and B(15,11)
(ii)The given points are A(7,4) and B(-5,1)
(iii)The given points are A(-6, -4) and B(9,-12)
(iv)The given points are A(1, -3) and B(4, -6)
(v)The given points are P(a + b, a – b) and Q(a – b, a + b)
(vi)The given points are P(a sin a, a cos a) and Q(a cos a, – a sina)
Question 2
Find the distance of each of the following points from the origin:
(i)A(5, -12)
(ii)B(-5, 5)
(iii)C(-4, -6)Solution 2
(i)The given point is A(5, -12) and let O(0,0) be the origin
(ii)The given point is B(-5, 5) and let O(0,0) be the origin
(iii)The given point is C(-4, -6) and let O(0,0) be the origin
Question 3
Find all possible values of a for which the distance between the points A(a, -1) and B(5, 3) is 5 units.Solution 3
The given points are A(a, -1) and B(5,3)
Question 4
Find all possible values of y for which the distance between the points A(2, -3) and B(10, y) is 10 units.Solution 4
Question 5
Find the values of x for which the distance between the points P(x, 4) and Q(9, 10) is 10 units.Solution 5
Question 6
If the point A(x, 2) is equidistant from the points B(8, -2) and C(2, -2), find the value of x. Also, find the length of AB.Solution 6
Question 7
If the point A(0, 2) is equidistant from the points B(3, p) and C(p,5), find the value of p. Also, find the length of AB. Solution 7
Question 8
Find the point on the x-axis which is equidistant from the points (-2, 5) and (-2, 9).Solution 8
Let any point P on x – axis is (x,0) which is equidistant from A(-2, 5) and B(-2, 9)
This is not admissible
Hence, there is no point on x – axis which is equidistant from A(-2, 5) and B(-2, 9)Question 9
Find points on the x – axis, each o f which is at a distance of 10 units from the point A(11, -8).Solution 9
Let A(11, -8) be the given point and let P(x,0) be the required point on x – axis
Then,
Hence, the required points are (17,0) and (5,0)Question 10
Find the point on the y-axis which is equidistant from the points A(6, 5) and B(-4, 3).Solution 10
Question 11
If the point P(x, y) is equidistant from the points A(5, 1) and B(-1, 5), prove that 3x = 2y.Solution 11
Question 13
Find the coordinates of the point equidistant from three given points A(5, 3), B(5, -5) and C(1, -5).Solution 13
Let the required points be P(x,y), then
PA = PB = PC. The points A, B, C are (5,3), (5, -5) and (1, -5) respectively
Hence, the point P is (3, -1)Question 14
If the points A(4, 3) and B(x, 5) lie on a circle with the centre O(2, 3), find the value of x.Solution 14
Question 15
If the point C(-2, 3) is equidistant from the points A(3, -1) and B(x, 8), find the values of x. Also, find the distance BC.Solution 15
Question 16
If the point P(2, 2) is equidistant from the points A(-2, k) and B(-2k, – 3), find k. Also, find the length of AP.Solution 16
6A Question 17
If the point (x, y) is equidistant from the points (a + b, b – a) and (a – b, a + b), prove that bx = ay.Solution 17
Question 18(i)
Using the distance formula, show that the given points are collinear.
(1, -1), (5, 2) and (9, 5)Solution 18(i)
Question 18(ii)
Using the distance formula, show that the given points are collinear.
(6, 9), (0, 1) and (-6, -7)Solution 18(ii)
Question 18(iii)
Using the distance formula, show that the given points are collinear
(-1, -1), (2, 3) and (8, 11)Solution 18(iii)
Question 18(iv)
Using the distance formula, show that the given points are collinear.
(-2, 5), (0, 1) and (2, -3).Solution 18(iv)
Question 19
Show that the points A(7, 10), B(-2, 5) and C(3, -4) are the vertices of an isosceles right triangle.Solution 19
Question 20
Show that the points A(3, 0), B(6, 4) and C(-1, 3) are the vertices of an isosceles right triangle.Solution 20
Question 21
If A(5, 2), B(2, -2) and C(-2, t) are the vertices of a right triangle with ∠B = 90°, then find the value of t.Solution 21
Question 22
Prove that the points A(2, 4), B(2, 6) and C(2 +, 5) are the vertices of an equilateral triangle.Solution 22
Question 23
Show that the points (-3, -3), (3, 3) and (-3, 3) are the vertices of an equilateral triangle.Solution 23
Question 24
Show that the points A(-5, 6), B(3, 0) and C(9, 8) are the vertices of isosceles triangle. Calculate its area.Solution 24
Let A(-5,6), B(3,0) and C(9,8) be the given points. Then
Question 25
Show that the points O(0, 0), A(3, ) and B(3, –) are the vertices of an equilateral triangle. Find the area of this triangle.Solution 25
are the given points
Hence, DABC is equilateral and each of its sides being
Question 26
Show that the following points are the vertices of a square:
(i)A(3, 2), B(0, 5), C(-3, 2) and D(0, -1)
(ii)A(6, 2), B(2, 1), C(1, 5) and D(5, 6)
(iii)P(0, -2), Q(3, 1), R(0, 4) and S(-3, 1)Solution 26
(i)The angular points of quadrilateral ABCD are A(3,2), B(0,5), C(-3,2) and D(0,-1)
Thus, all sides of quad. ABCD are equal and diagonals are also equal
Quad. ABCD is a square
(ii)Let A(6,2), B(2,1), C(1,5) and D(5,6) be the angular points of quad. ABCD. Join AC and BD
Thus, ABCD is a quadrilateral in which all sides are equal and the diagonals are equal.
Hence, quad ABCD is a square.
(iii)Let P(0, -2), Q(3,1), R(0,4) and S(-3,1) be the angular points of quad. ABCD
Join PR and QSD
Thus, PQRS is a quadrilateral in which all sides are equal and the diagonals are equal
Hence, quad. PQRS is a squareQuestion 27
Show that the points A(-3, 2), B(-5, -5), C(2, -3) and D(4, 4) are the vertices of a rhombus. Find the area of this rhombus.Solution 27
Let A(-3,2), B(-5, -5), C(2, -3) and D(4,4) be the angular point of quad ABCD. Join AC and BD.
Thus, ABCD is a quadrilateral having all sides equal but diagonals are unequal.
Hence, ABCD is a rhombus
Question 28
Show that the points A(3, 0), B(4, 5), C(-1, 4) and D(-2, -1) are the vertices of a rhombus. Find its area.Solution 28
Question 29
Show that the points A(6, 1), B(8, 2), C(9, 4) and D(7, 3) are the vertices of a rhombus. Find its area.Solution 29
Question 30
Show that the points A(2, 1), B(5, 2), C(6, 4) and D(3, 3) are the angular points of a parallelogram. Is this figure a rectangle?Solution 30
Let A(2,1), B(5,2), C(6,4) and D(3,3) are the angular points of a parallelogram ABCD. Then
Diagonal AC Diagonal BD
Thus ABCD is not a rectangle but it is a parallelogram because its opposite sides are equal and diagonals are not equalQuestion 31
Show that A(1, 2), B(4, 3), C(6, 6) and D(3, 5) are the vertices of a parallelogram. Show that ABCD is not a rectangle.Solution 31
Question 32
Show that the following points are the vertices of a rectangle:
(i)A(-4, -1), B(-2, -4), C(4, 0) and D(2, 3)
(ii)A(2, -2), B(14, 10), C(11, 13) and D(-1, 1)
(i)A(0, -4), B(6, 2), C(3, 5) and D(-3, -1)Solution 32
(i) Let A(-4, -1), B(-2, -4), C(4, 0) and D(2, 3) are the vertices of quad. ABCD. Then
Thus, ABCD is a quadrilateral whose opposite sides are equal and the diagonals are equal
Hence, quad. ABCD is a rectangle.
(ii)Let A(2, -2), B(14, 10), C(11, 13) and D(-1, 1) be the angular points of quad. ABCD, then
Thus, ABCD is a quadrilateral whose opposite sides are equal and diagonals are equal.
Hence, quad. ABCD is rectangle.
(iii)Let A(0, -4), B(6,2), C(3,5) and D(-3,-1) are the vertices of quad. ABCD. Then
Thus, ABCD is a quadrilateral whose opposite sides are equal and the diagonals are equal
Hence, quad. ABCD is a rectangle
Exercise MCQ
Question 1
The distance of the point P(-6,8) from the origin is
Solution 1
Question 2
The distance of the point (-3, 4) from x-axis is
(a) 3
(b) -3
(c) 4
(d) 5Solution 2
Question 3
The point on x-axis which is equidistant from points
A(-1, 0) and B(5, 0) is
(a) (0, 2)
(b) (2, 0)
(c) (3, 0)
(d) (0, 3)Solution 3
Question 4
If R(5, 6) is the midpoint of the line segment AB joining the points A(6, 5) and B(4, y) they y equals
(a) 5
(b) 7
(c) 12
(d) 6Solution 4
Question 5
If the point C(k, 4) divides the join of the points A(2, 6) and B(5,1) in the ratio 2:3 then the value of k is
Solution 5
Question 6
The perimeter of the triangle with vertices (0, 4), (0, 0) and (3, 0) is
Solution 6
Correct option: (d)
Question 7
If A(1, 3), B(-1, 2), C(2, 5) and D(x, 4) are the vertices of a ‖gm ABCD then the value of x is
Solution 7
Correct option: (b)
Question 8
If the points A(x, 2), B(-3, -4) and C(7, -5) are collinear then the value of x is
(a) -63
(b) 63
(c) 60
(d) -60Solution 8
Question 9
The area of a triangle with vertices A(5, 0), B(8, 0) and C(8,4) in square units is
(a) 20
(b) 12
(c) 6
(d) 16Solution 9
Question 10
The area of ABC with vertices A(a, 0), O(0, 0) and
B(0, b) in square units is
Solution 10
Question 11
(a) -8
(b) 3
(c) -4
(d) 4Solution 11
Question 12
ABCD is a rectangle whose three vertices are B(4, 0), C(4, 3) and D(0, 3). The length of one of its diagonals is
(a) 5
(b) 4
(c) 3
(d) 25Solution 12
Correct option: (a)
Question 13
The coordinates of the point P dividing the line segment joining the points A(1, 3) and B(4, 6) in the ratio 2:1 is
(a) (2, 4)
(b) (3, 5)
(c) (4, 2)
(d) (5, 3)Solution 13
Question 14
If the coordinates of one end of a diameter of a circle are (2, 3) and the coordinates of its centre are (-2, 5), then the coordinates of the other end of the diameter are
(a) (-6, 7)
(b) (6, -7)
(c) (4, 2)
(d) (5, 3)Solution 14
Question 15
In the given figure P(5, -3) and Q(3, y) are the points of trisection of the line segment joining A(7, -2) and
B(1, -5). Then y equals
Solution 15
Question 16
The midpoint of segment AB is P(0, 4). If the coordinates of B are (-2, 3), then the coordinates of A are
(a) (2, 5)
(b) (-2, -5)
(c) (2, 9)
(d) (-2, 11)Solution 16
Question 17
The point P which divides the line segment joining the points A(2, -5) and B(5, 2) in the ratio 2:3 lies in the quadrant
(a) I
(b) II
(c) III
(d) IV Solution 17
Question 18
If A(6, -7) and B(-1, -5) are two given points then the distance 2AB is
(a) 13
(b) 26
(c) 169
(d) 238Solution 18
Question 19
Which point on x-axis is equidistant from the points
A(7, 6) and B(-3, 4)?
(a) (0, 4)
(b) (-4, 0)
(c) (3, 0)
(d) (0, 3)Solution 19
Question 20
The distance of P(3, 4) from the x-axis is
(a) 3 units
(b) 4 units
(c) 5 units
(d) 1 unitsSolution 20
Question 21
In what ratio does the x-axis divide the join of A(2, -3) and B(5, 6)?
(a) 2:3
(b) 3:5
(c) 1:2
(d) 2:1Solution 21
Question 22
In what ratio does the y-axis divide the join of P(-4, 2) and Q(8, 3)?
(a) 3:1
(b) 1:3
(c) 2:1
(d) 1:2Solution 22
Question 23
If P(-1, 1) is the midpoint of the line segment joining
A(-3, b) and B(1, b + 4) then b =?
(a) 1
(b) -1
(c) 2
(d) 0Solution 23
Question 24
The line 2x + y – 4 = 0 divides the line segment joining A(2, -2) and (3, 7) in the ratio
(a) 2:5
(b) 2:9
(c) 2:7
(d) 2:3Solution 24
Question 25
If A(4, 2), B(6, 5) and C(1,4) be the vertices of ∆ABC and AD is a median, then the coordinates of D are
Solution 25
Question 26
If A(-1, 0), B(5, -2) and C(8,2) are the vertices of a ∆ABC then its centroid is
(a) (12, 0)
(b) (6, 0)
(c) (0, 6)
(d) (4, 0)Solution 26
Question 27
Two vertices of ∆ABC are A (-1, 4) and B(5, 2) and its centroid is G(0, -3). Then, the coordinates of are
(a) (4, 3)
(b) (4, 15)
(c) (-4, -15)
(d) (-15, -4)Solution 27
Question 28
The points A(-4, 0), B(4, 0) and C(0,3) are the vertices of a triangle, which is
(a) isosceles
(b) equilateral
(c) scalene
(d) right-angledSolution 28
Question 29
The point P(0, 6), Q(-5, 3) and R(3, 1)are the vertices of a triangle, which is
(a) equilateral
(b) isosceles
(c) scalene
(d) right-angledSolution 29
Question 30
If the points A(2, 3), B(5, k) and C(6, 7) are collinear then
Solution 30
Question 31
If the point A (1, 2), O(0, 0) and C(a, b) are collinear then
(a) a = b
(b) a = 2b
(c) 2a = b
(d) a + b = 0Solution 31
Question 32
The area of ∆ABC with vertices A(3, 0), B(7, 0) and
C(8, 4) is
(a) 14 sq units
(b) 28 sq units
(c) 8 sq units
(d) 6 sq unitsSolution 32
Question 33
AOBC is a rectangle whose three vertices are A(0, 3), O(0, 0) and B(5, 0). The length of each of its diagonals is
Solution 33
Question 34
If the distance between the points A(4, p) and B(1, 0) is 5 then
(a) p = 4 only
(b) p = -4 only
(c) p = ± 4
(d) p = 0Solution 34
Exercise Ex. 6B
Question 1
Find the coordinates of the point which divides the join of A(-1, 7) and B(4, -3) in the ratio 2 : 3.Solution 1
The end points of AB are A(-1,7) and B(4, -3)
Let the required point be P(x, y)
By section formula, we have
Hence the required point is P(1, 3)Question 2
Find the coordinates of the points which divides the join of A(-5, 11) and B(4, -7) in the ratio 7 : 2.Solution 2
The end points of PQ are P(-5, 11) and Q(4, -7_
By section formula, we have
Hence the required point is (2, -3)Question 3
Solution 3
Question 4
Solution 4
Question 5
Points P, Q, R and S divide the line segment joining the points A(1, 2) and R(6, 7) in five equal parts. Find the coordinates of P, Q and R.Solution 5
Question 6
Points P, Q and R in that order are dividing a line segment joining A(1, 6) and B(5, -2) in four equal parts, find the coordinates of P, Q and R.Solution 6
Points P, Q, R divide the line segment joining the points A(1,6) and B(5, -2) into four equal parts
Point P divide AB in the ratio 1 : 3 where A(1, 6), B(5, -2)
Therefore, the point P is
Also, R is the midpoint of the line segment joining Q(3, 2) and B(5, -2)
Question 7
The line segment joining the points A(3, -4) and B(1, 2) is trisected at the points P(p, -2) and . Find the values of p and q.Solution 7
Point P divides the join of A(3, -4) and B(1,2) in the ratio 1 : 2.
Coordinates of P are:
Question 8
Find the coordinates of the midpoint of the line segment joining:
(i)A(3, 0) and B(-5, 4)
(ii)P(-11, -8) and Q(8, -2)Solution 8
(i)The coordinates of mid – points of the line segment joining A(3, 0) and B(-5, 4) are
(ii)Let M(x, y) be the mid – point of AB, where A is (-11, -8) and B is (8, -2). Then,
Question 9
If (2, p) is the midpoint of the line segment joining the points A(6, -5) and B(-2, 11), find the value of p.Solution 9
The midpoint of line segment joining the points A(6, -5) and B(-2, 11) is
Also, given the midpoint of AB is (2, p)
p = 3Question 10
The midpoint of the line segment A(2a, 4) and B(-2, 3b) is C(1, 2a + 1). Find the value of a and b.Solution 10
C(1, 2a + 1) is the midpoint of A(2a, 4) and B(-2, 3b)
Question 11
The line segment joining A(-2, 9) and B(6, 3) is a diameter of a circle with centre C. Find the coordinates of C.Solution 11
Let A(-2, 9) and B(6, 3) be the two points of the given diameter AB and let C(a, b) be the center of the circle
Then, clearly C is the midpoint of AB
By the midpoint formula of the co-ordinates,
Hence, the required point C(2, 6)Question 12
Find the coordinates of a point A, where AB is a diameter of a circle with centre C(2, -3) and the other end of the diameter is B(1, 4).Solution 12
A, B are the end points of a diameter. Let the coordinates of A be (x, y)
The point B is (1, 4)
The center C(2, -3) is the midpoint of AB
The point A is (3, -10)Question 13
In what ratio does the point P(2, 5) divide the join of A(8, 2) and B(-6, 9)?Solution 13
Let P divided the join of A(8, 2), B(-6, 9) in the ratio k : 1
By section formula, the coordinates of p are
Hence, the required ratio of which is (3 : 4)Question 14
Solution 14
Question 15
Find the ratio in which the point P(m, 6) divides the join of A(-4, 3) and B(2, 8). Also, find the value of m.Solution 15
Let P divided the join of line segment A(-4, 3) and B(2, 8) in the ratio k : 1
the point P is
Question 16
Find the ratio in which the point (-3, k) divides the join of A(-5, -4) and B(-2, 3). Also, find the value of k.Solution 16
Let P is dividing the given segment joining A(-5, -4) and B(-2, 3) in the ratio r : 1
Coordinates of point P
Question 17
In what ratio is the line segment joining A(2, -3) and B(5, 6) divided by the x-axis? Also, find the coordinates of the point of division.Solution 17
Let the x- axis cut the join of A(2, -3) and B(5, 6) in the ratio k : 1 at the point P
Then, by the section formula, the coordinates of P are
But P lies on the x axis so, its ordinate must be 0
So the required ratio is 1 : 2
Thus the x – axis divides AB in the ratio 1 : 2
Putting we get the point P as
Thus, P is (3, 0) and k = 1 : 2Question 18
In what ratio is the line segment joining the points A(-2, -3) and B(3, 7) divided by the y-axis? Also, find the coordinates of the point of division.Solution 18
Let the y – axis cut the join A(-2, -3) and B(3, 7) at the point P in the ratio k : 1
Then, by section formula, the co-ordinates of P are
But P lies on the y-axis so, its abscissa is 0
So the required ratio is which is 2 : 3
Putting we get the point P as
i.e., P(0, 1)
Hence the point of intersection of AB and the y – axis is P(0, 1) and P divides AB in the ratio 2 : 3Question 19
In what ratio does the line x – y – 2 = 0 divide the line segment joining the points A(3, -1) and B(8, 9)?Solution 19
Let the line segment joining A(3, -1) and B(8, 9) is divided byx – y – 2 = 0 in ratio k : 1 at p
Coordinates of P are
Thus the line x – y – 2 = 0 dividesAB in the ratio 2 : 3Question 20
Find the lengths of the medians of a ABC whose vertices are A(0, -1), B(2, 1) and C(0, 3).Solution 20
Let D, E, F be the midpoint of the side BC, CA and AB respectively in ABC
Then, by the midpoint formula, we have
Hence the lengths of medians AD, BE and CF are given by
Question 21
Find the centroid of ABC whose vertices are A(-1, 0), B(5, -2) and C(8, 2).Solution 21
Here
Let G(x, y) be the centroid of ABC, then
Hence the centroid of ABC is G(4, 0)Question 22
If G(2, -1) is the centroid of a ABC and two of its vertices are A(1, -6) and B(-5,2), find the third vertex of the triangle.Solution 22
Two vertices of ABC are A(1, -6) and B(-5, 2) let the third vertex be C(a, b)
Then, the co-ordinates of its centroid are
But given that the centroid is G(-2, 1)
Hence, the third vertex C of ABC is (-2, 7)Question 23
Find the third vertex of a ABC if two of its vertices are B(-3, 1) and C(0, -2), and its centroid is at the origin.Solution 23
Two vertices of ABC are B(-3, 1) and C(0, -2) and third vertex be A(a, b)
Then the coordinates of its centroid are
Hence the third vertices A of ABC is A(3, 1)Question 24
Show that the points A(3, 1), B(0, -2), C(1, 1) and D(4, 4) are the vertices of a parallelogram ABCD.Solution 24
Let A(3,1), B(0, -2), C(1, 1) and D(4, 4) be the vertices of quadrilateral
Join AC, BD. AC and BD, intersect other at the point O.
We know that the diagonals of a parallelogram bisect each other
Therefore, O is midpoint of AC as well as that of BD
Now midpoint of AC is
And midpoint of BD is
Mid point of AC is the same as midpoint of BD
Hence, A, B, C, D are the vertices of a parallelogram ABCDQuestion 25
If the points P(a, -11), Q(5, b), R(2, 15) and S(1, 1) are the vertices of a parallelogram PQRS, find the values of a and b.Solution 25
Let P(a, -11), Q(5, b), R(2, 15) and S(1, 1) are the vertices of a parallelogram PQRS.
Join the diagonals PR and SQ.
They intersect each other at the point O. We know that the diagonals of a parallelogram bisect each other.
Therefore, O is the midpoint of PR as well as that of SQ
Now, midpoint of PR is
And midpoint of SQ is
Hence the required values are a = 4 and b = 3Question 26
If three consecutive vertices of a parallelogram ABCD are A(1, -2), B(3, 6) and C(5, 10), find the fourth vertex D.Solution 26
Let A(1, -2), B(3, 6) and C(5, 10) are the given vertices of the parallelogram ABCD
Let D(a, b) be its fourth vertex. Join AC and BD.
Let AC and BD intersect at the point O.
We know that the diagonals of a parallelogram bisect each other.
So, O is the midpoint AC as well as that of BD
Midpoint of AC is
Midpoint of BD is
Hence the fourth vertices is D(3, 2)Question 27
In what ratio does y-axis divide the line segment joining the points (-4, 7) and (3, -7)?Solution 27
Question 28
If the point Plies on the line segment joining the points A(3, -5) 2 and B(-7, 9) then find the ratio in which P divides AB. Also, find the value of y.Solution 28
Question 29
Find the ratio in which the line segment joining the points A(3, -3) and B(-2, 7) is divided by x-axis. Also, find the point of division.Solution 29
Question 30
The base QR of an equilateral triangle PQR lies on x-axis. The coordinates of the point Q are (-4, 0) and origin is the midpoint of the base. Find the coordinates of the points P and R.Solution 30
Question 31
The base BC of an equilateral triangle ABC lies on y-axis. The coordinates of point C are (0, -3). The origin is the midpoint of the base. Find the coordinates of the points A and B. Also, find the coordinates of anther point D such that ABCD is a rhombus.Solution 31
Question 32
Find the ratio in which the points p(-1, y) lying on the line segment joining points A(-3, 10) and B(6, -8) divides it. Also, find the value of y.Solution 32
Question 33
ABCD is a rectangle formed by the points A(-1, -1), B(-1, 4), C(5, 4) and D(5, -1). If P, Q, R and S be the midpoints of AB, BC, CD and DA respectively, show that PQRS is a rhombus.Solution 33
Question 34
The midpoint P of the line segment joining the points A(-10, 4) and B(-2, 0) lies on the line segment joining the points C(-9, -4) and D(-4, y). Find the ratio in which P divides CD. Also find the value of y.Solution 34
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