Chapter 33 Binomial Distribution Exercise Ex. 33.1
Question 1
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Solution 1
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Question 2
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Solution 2
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Question 3
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Solution 3
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Question 4
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Solution 4
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Question 5
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Solution 5
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Question 6
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Solution 6
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Question 7
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Solution 7
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Question 8
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Solution 8
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Required Probability =Question 9
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Solution 9
Question 10
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Solution 10
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Question 11
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Solution 11
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Question 12
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Solution 12
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Question 13
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Solution 13
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Question 14
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Solution 14
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Question 15
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Solution 15
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Question 16
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Solution 16
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Question 17
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Solution 17
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Question 18
Solution 18
Question 19
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Solution 19
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Question 20
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Solution 20
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Question 21
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Solution 21
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Question 22
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Also, find the mean and variance of this distribution.Solution 22
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Question 23
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Solution 23
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Question 24
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Solution 24
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Question 25
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Solution 25
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Question 26
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Solution 26
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Question 27
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Solution 27
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Question 28
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Solution 28
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Question 29
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Solution 29
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Question 30
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Solution 30
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Question 31
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Solution 31
Question 32
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Solution 32
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Question 33
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Solution 33
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= 0.0256Question 34
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Solution 34
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Question 35
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Solution 35
Question 36
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Solution 36
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Question 37
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Solution 37
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Question 38
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Solution 38
Question 39
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Solution 39
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Question 40
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Solution 40
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Question 41
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Solution 41
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Question 42
Solution 42
Question 43
Solution 43
Question 44
Solution 44
Question 45
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Solution 45
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Question 46
Solution 46
Question 47
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Solution 47
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Question 48
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Solution 48
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Question 49
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Solution 49
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Question 50
Find the probability that in 10 throws of a fair die a score which is a multiple of 3 will be obtained in at least 8 of the throws.Solution 50
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Question 51
A die is thrown 5 times. Find the probability that an odd number will come up exactly three times.Solution 51
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Question 52
The probability of a man hitting a target is 0.25. He shoots 7 times. What is the probability of his hitting at least twice?Solution 52
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Question 53
A factory produces bulbs. The probability that one bulb is defective is and they are packed in boxes of 10. From a single box, find the probability that
i. none of the bulbs is defective.
ii. exactly two bulls are defective.
iii. more than 8 bulbs work properly.Solution 53
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Note: Answer given in the book is incorrect.
Chapter 33 Binomial Distribution Exercise Ex. 33.2
Question 1
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Solution 1
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Question 2
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Solution 2
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Question 3
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Solution 3
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Question 4
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Solution 4
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Question 5
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Solution 5
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Question 6
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Solution 6
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Question 7
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Solution 7
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Question 8
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Solution 8
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Question 9
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Solution 9
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Question 10
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Solution 10
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Question 11
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Solution 11
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Question 12
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Solution 12
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Question 13
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Solution 13
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Question 14
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Solution 14
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Question 15
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Solution 15
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Question 16
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Solution 16
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Question 17
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Solution 17
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Question 18
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Solution 18
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Question 19
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Solution 19
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Question 20
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Solution 20
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Question 21
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Solution 21
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Question 22
From a lot of 15 bulbs which include 5 defective, sample of 4 bulbs is drawn one by one with replacement. Find the probability distribution of number of defective bulbs. Hence, find the mean of the distribution.Solution 22
Out of 15 bulbs 5 are defective.

Question 23
A die is thrown three times. Let X be’ the number of twos seen’. Find the expectation of X.Solution 23
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Question 24
A die is thrown twice. A ‘success’ is getting an even number on a toss. Find the variance of number of successes.Solution 24
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Question 25
Three cards are drawn successively with replacement from a well shuffled pack of 52 cards. Find the probability of the number spades. Hence, find the mean of the distribution.Solution 25
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