Chapter 21 – Surface Areas and Volume of a Sphere Exercise Ex. 21.1
Question 1
Solution 1
Question 2
Solution 2
Question 3
Solution 3
Question 4
Solution 4
Question 5A hemispherical bowl made of brass has inner diameter 10.5 cm. Find the cost of tin-plating it on the inside at the rate of Rs 4 per 100 cm2.Solution 5
Question 6
Solution 6
Question 7
Solution 7
Question 8
Solution 8
Question 9
The diameter of the moon is approximately one fourth of the diameter of the earth. Find the ratio of their surface areas.Solution 9
Question 10
A hemi-spherical dome of a building needs to be painted. If the circumference of the base of the dome is 17.6 cm, find the cost of painting, if given the cost of painting is Rs 5 per 100 cm2.Solution 10
Question 11
Solution 11
Question 12
Solution 12
Question 13The front compound wall of a house is decorated by wooden spheres of diameter 21 cm, placed on small supports as shown in the given figure. Eight such spheres are used for this purpose, and are to be painted silver. Each support is a cylinder of radius 1.5 cm and height 7 cm and is to be painted black. Find the cost of paint required if silver paint costs 25 paise per cm2 and black paint costs 5 paise per cm2.
Solution 13
Chapter 21 – Surface Areas and Volume of A Sphere Exercise Ex. 21.2
Question 1
Solution 1
Question 2
Solution 2
Question 3
Solution 3
Question 4
Solution 4
Question 5
Solution 5
Question 6
Solution 6
Question 7
Solution 7
Question 8
Solution 8
Question 9If the radius of a sphere is doubled, what is the ratio of the volume of the first sphere to that of the second sphere?Solution 9
Question 10
A vessel in the form of a hemispherical bowl is full of water. Its contents are emptied in a right circular cylinder. The internal radii of the bowl and the cylinder are 3.5 cm and 7 cm respectively. Find the height to which the water will rise in the cylinder.Solution 10
Question 11
Solution 11
Question 12
Solution 12
Question 13
The diameter of a coper sphere is 18 cm. The sphere is melted and is drawn into a long wire of uniform circular cross-section. If the length of the wire is 108 m, find its diameter.Solution 13
Question 14
Solution 14
Question 15
Solution 15
Question 16
A hemisphere of lead of radius 7 cm is cast into a right circular cone of height 49 cm. Find the radius of the base.Solution 16
Question 17
Solution 17
Question 18
Solution 18
Question 19
Solution 19
Question 20
Solution 20
Question 21
A cube of side 4 cm contained a sphere touching its sides. Find the volume of the gap in between.Solution 21
Question 22
A hemispherical tank is made up of an iron sheet 1 cm thick. If the inner radius is 1 m, then find the volume of the iron used to make the tank.Solution 22Inner radius (r1) of hemispherical tank = 1 m
Thickness of hemispherical tank = 1 cm = 0.01 m
Outer radius (r2) of hemispherical tank = (1 + 0.01) m = 1.01 mVolume of iron used to make the tank =
Question 23
A capsule of medicine is in the shape of a sphere of diameter 3.5 mm. How much medicine (in mm3) is needed to fill this capsule?Solution 23Radius (r) of capsule
Volume of spherical capsule
Thus, approximately 22.46 mm3 of medicine is required to fill the capsule.
Question 24
The diameter of the moon is approximately one-fourth of the diameter of the earth. What fraction of the volume of the earth is the volume of the moon?Solution 24 Let diameter of earth be d. So, radius earth will be .
Then, diameter of moon will be . So, radius of moon will be .
Volume of moon =
Volume of earth =
Thus, the volume of moon is of volume of earth.
Question 25
Solution 25
Question 26
A cylinderical tub of radius 16 cm contains water to a depth of 30 cm. A spherical iron ball is dropped into the tub and thus level of water is raised by 9 cm. What is the radius of the ball?Solution 26
Question 27
A cylinder of radius 12 cm contains water to a depth of 20 cm. A spherical iron ball is dropped into the cylinder and thus the level of water is raised by 6.75 cm. Find the radius of the ball. (Use = 22/7)Solution 27
Question 28
Solution 28
Question 29
Solution 29
Question 30
Solution 30
Question 31
Solution 31
Question 32
Solution 32
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