NCERT Solutions for Class 6 Maths: One of the most important and interesting things to keep in mind is that these solutions available are totally free of cost. This also includes all the solutions to the exercises that are given in the textbook. NCERT solutions for class 6 maths gives you chapter-wise solutions to each and every question. This can help you solve even the tougher with ease.
It is always good to have a strong foundation in order to build a good building. This also is true in class when you are still learning the basics of maths. NCERT solutions for class 6 maths provides you the exact opportunity to build a strong foundation in this subject. Below is an overview of each and every chapter covered in the NCERT textbook.
Table of Contents
NCERT Solutions for Class 6 Maths Chapter 8 Decimals
Ex 8.1 Class 6 Maths Question 1.
Write the following as numbers in the given table:
Solution:
On filling the given table, we have
Ex 8.1 Class 6 Maths Question 2.
Write the following decimals in the place value table:
(a) 19.4
(b) 0.3
(c) 10.6
(d) 205
Solution:
Let us make a common place value table, assigning appropriate place value to the digits in the given numbers. We have,
Ex 8.1 Class 6 Maths Question 3.
Write each of the following as decimals:
(a) Seven- tenths
(b) Two tens and nine-tenths
(c) Fourteen point six
(d) One hundred and two ones
(e) Six htihdred point eight
Solution:
(a) Seven-tenths = 710 = 0.7
(b) Two tens, 9 – tenths = 20 + 910 = 20.9
(c) Fourteen point six = 14.6
(d) One Hundred and 2-ones = 1 x 100 + 0 x 10 + 2 x 1 + 0 x 110
= 100 + 0 + 2 = 102.0
(e) Six hundred point eight = 600.8
Ex 8.1 Class 6 Maths Question 4.
Write each of the following as decimals:
Solution:
Ex 8.1 Class 6 Maths Question 5.
Write the following decimals as fractions. Reduce the fractions to lowest form:
(a) 0.6
(b) 2.5
(c) 1.0
(d) 3.8
(e) 13.7
(f) 21.2
(g) 6.4
Solution:
Ex 8.1 Class 6 Maths Question 6.
Express the following as cm vising decimals:
(a) 2 mm
(b) 30 mm
(c) 116 mm
(d) 4 cm 2mm
(e) 162 mm
(f) 83 mm
Solution:
Ex 8.1 Class 6 Maths Question 7.
Between which two whole numbers on the number line are the given numbers lie?
Which of these whole numberes is nearer the number?
(a) 0.8
(b) 5.1
(c) 2.6
(d) 6.4
(e) 9.1
(f) 4.9
Solution:
Ex 8.1 Class 6 Maths Question 8.
Show the following numbers on the number line.
(a) 0.2
(b) 1.9
(c) 1.1
(d) 2.5
Solution:
(a) Since 0.2 > 0 but <1. There are 2 tenth in it. Divide the unit length between 0 and 1 into 10 equal parts and take 2 parts as shown below. Thus, A represents 0.2.
(b) Since 1 < 1.9 < 2. Divide the unit length between 1 and 2 into 10 equal parts and take 9 parts as shown below. Thus, A represents 1.9.
(c) Since 1 < 1.1 < 2. Divide the unit length between 1 and 2 into 10 equal parts and take 1 part as shown below. Thus, A represents 1.1.
(d) Since 2 < 2.5 < 3. Divide the unit length between 2 and 3 into 10 equal parts and take 5 parts as shown below. Thus, A represents 2.5.
Ex 8.1 Class 6 Maths Question 9.
Write the decimal number represented by the points A, B, C, D on the given number line
Solution:
Since A lies between 0 and 1 and the unit length between 0 and 1 stands divided in 10 equal parts. Also A is at the 8th point.
Thus, A represents 0.8.
Since, B lies between 1 and 2 and the unit length between 1 and 2 stands divided in 10 equal parts. Also, B lies 3 points ahead of 1. Therefore, B represents 1.3.
Since C and D lies between 2 and 3 and the unit length between 2 and 3 stands divided between 2 and 3 in 10 equal parts. Also C and D respectively lies 2 and 9 points ahead of 2.
∴ C represents 2.2 and D represents 2.9.
Ex 8.1 Class 6 Maths Question 10.
(a) The length of Ramesh’s notebook is 9 cm 5 mm. What will be its length in cm?
(b) The length of a young gram plant is 65 mm. Express its length in cm.
Solution:
(a) Length of Ramesh’s notebook
(b) Length of gram plant
Ex 8.2 Class 6 Maths Question 1.
Complete the table with the help of these boxes and use decimals to write the number
Solution:
Completing the table, we have
Ex 8.2 Class 6 Maths Question 2.
Write the numbers given in the following place value table in decimal form:
Solution:
Ex 8.2 Class 6 Maths Question 3.
Write the following decimals in the place value table:
(a) 0.29
(b) 2.08
(c) 19.60
(d) 148.32
(e) 200.812
Solution:
Let us make a common place value table, assigning appropriate place value to the digits in the given numbers. We have,
Ex 8.2 Class 6 Maths Question 4.
Write each of the following as decimals:
Solution:
Ex 8.2 Class 6 Maths Question 5.
Write each of the following decimals in words:
(a) 0. 03
(b) 1.20
(c) 108.56
(d) 10.07
(e) 0. 032
(f) 5.008
Solution:
(a) 0.03 = Zero point zero three or three hundredths.
(b) 1.20 = One point two zero.
(c) 108.56 = One hundred eight point five six.
(d) 10.7 = Ten point zero seven.
(e) 0. 032 = Zero point zero three two.
(f) 5.008 = Five point zero zero eight.
Ex 8.2 Class 6 Maths Question 6.
Between which two numbers in tenths place on the number line does each of the given number lie?
(a) 0. 06
(b) 0.45
(c) 0.19
(d) 0.66
(e) 0.92
(f) 0.57
Solution:
All these points lies between 0 and 1.
Ex 8.2 Class 6 Maths Question 7.
Write as fractions in lowest terms:
(a) 0.60
(b) 0.05
(c) 0.75
(d) 0.25
(f) 0.125
(g) 0.066
Solution:
Ex 8.3 Class 6 Maths Question 1.
Which is greater?
(a) 0.3 or 0.4
(b) 0.07 or 0.02
(c) 3 or 0.8
(d) 0.5 or 0.05
(e) 1.23 or 1.2
(f) 0.099 or 0.19
(g) 1.5 or 1.50
(h) 1.431 or 1.490
(i) 3.3 or 3.300
(j) 5.64 or 5.603
Solution:
In this case, the two numbers have the same parts upto tenths. The hundredth part of 5.64 is greater than that of 5.603.
∴ 5.64 > 5.603
Ex 8.3 Class 6 Maths Question 2.
Make five more examples and find the greater number from them.
(i) 0.5 and 0.8
(ii) 2.0 or 0.9
(iii) 0.042 or 0.22
(iv) 3.012 or 2.99
(v) 0.055 or 0.15
Solution:
Their solutions are:
Ex 8.4 Class 6 Maths Question 1.
Express as rupees using decimals:
(a) 5 paise
(b) 75 paise
(c) 20 paise
(d) 50 rupees 90 paise
(e) 725 paise
Solution:
Ex 8.4 Class 6 Maths Question 2.
Express as metres using decimals:
(a) 15 cm
(b) 6 cm
(c) 2 m 45 m
(d) 9 m 7 cm
(e) 419 cm
Solution:
Ex 8.4 Class 6 Maths Question 3.
Express as cm using decimals:
(a) 5 nun
(b) 60 mm
(c) 164 mm
(d) 9 cm 8 mm
(e) 93 mm
Solution:
Ex 8.4 Class 6 Maths Question 4.
Express as km using decimals:
(a) 8 m
(b) 88 m
(c) 8888 m
(d) 70 km 5 m
Solution:
Ex 8.4 Class 6 Maths Question 5.
Express as kg using decimals:
(a) 2 g
(b) 100 g
(c) 3750 g
(d) 5 kg 8 g
(e) 26 kg 50 g
Solution:
Ex 8.5 Class 6 Maths Question 1.
Find the sum in each of the following:
(a) 0.007 + 8.5 + 30.08
(b) 15 + 0.632 + 13.8
(c) 27.076+ 0.55 + 0.004
(d) 25.65 + 9.005 + 3.7
(e) 0.75 + 10.425 + 2
(f) 280.69 + 25.2 + 38
Solution:
Ex 8.5 Class 6 Maths Question 2.
Rashid spent ₹ 35.75 for Maths book and ₹ 32.60 for Science book. Find the total amount spent by Rashid.
Solution:
Money spent on Maths book = ₹ 35.75
Money spent on Science book=₹ 32.60
∴ Total money spent is =₹ 35.75 +₹ 32.60 = ₹ 68.35
Ex 8.5 Class 6 Maths Question 3.
Radhika’s mother gave her ₹ 10.50 and her father gave her ₹ 15.80, find the total amount given to Radhika by the parents.
Solution:
Money given by Radhika’s mother = ₹ 10.50
Money given by Radhika’s father = ₹ 15.80
∴ Total amount given to Radhika = ₹ 10.50 + ₹ 15.80 = ₹ 26.30
Ex 8.5 Class 6 Maths Question 4.
Nasreen bought 3 m 20 cm cloth for her shirt and 2 m 5 cm cloth for her trouser. Find the total length of cloth bought by her.
Solution:
Cloth bought by Nasreen for her shirt = 3 m 20 cm
Cloth bought by Nasreen for her trouser = 2 m 5 cm
∴ Total cloth bought by Nasreen = 3 m 20 cm + 2 m 5 cm
= 5 m 25 cm
Ex 8.5 Class 6 Maths Question 5.
Naresh walked 2 km 35 m in the morning and 1 km 7 m in the evening. How much distance did he walk in all?
Solution:
Distance walked in the morning = 2 km 35 m = 2.035 km
Distance walked in the evening = 1 km 7 m = 1.007 km
∴ Total distance walked by Naresh = 2.035 km +1.007 km = 3.042 km
Ex 8.5 Class 6 Maths Question 6.
Sunita travelled 15 km 268 m by bus, 7 km 7 m by car and 500 m on foot in order to reach her school. How far is her school from her residence?
Solution:
Distance travelled by bus = 15 km 268 m = 15.268 km
Distance travelled by car = 7 km 7 m = 7.007 km
Distance travelled on foot = 500 m = 0.500 km
Total distance of school from her residence
= 15.268 km + 7.007 km + 0.500 km = 22.775km
Ex 8.5 Class 6 Maths Question 7.
Ravi purchased 5 kg 400 g rice, 2 kg 20 g sugar and 10 kg 850 g flour. Find the total weight of his purchases.
Solution:
Weight of rice purchased = 5 kg 400 g = 5.400 kg
Weight of sugar purchased = 2 kg 20 gm = 2.020 kg
Weight of flour purchased = 10 kg 850 g = 10.850 kg
Total weight of purchases = 5.400 kg +2.020 kg +10.850 kg = 18.270 kg
Ex 8.6 Class 6 Maths Question 1.
Subtract:
(a) ₹ 18.25 from ₹ 20.75
(b) ₹ 202.54 m from 250 m
(c) ₹ 5.36 from ₹ 8.40
(d) 2.051 km from 5.206 km
(e) 0.314 kg from 2.107 kg
Solution:
Ex 8.6 Class 6 Maths Question 2.
Find the value of:
(a) 9.756 – 6.28
(b) 21.05 – 15.27
(c) 18.5 – 6.79
(d) 11.6 – 9.
Solution:
Ex 8.6 Class 6 Maths Question 3.
Raju bought a book for ₹ 35.65. He gave ₹ 50 to the shopkeeper. How much money did he get back from the shopkeeper?
Solution:
Cost of the book = ₹ 35.65
Money given to the shopkeeper by Raju = ₹ 50
Money he got back = ₹ 50 – ₹ 35.65 = ₹ 14.35
Ex 8.6 Class 6 Maths Question 4.
Rani had ₹ 18.50. She bought one ice-cream for ₹ 11.75. How much money does she have now?
Solution:
Money with Rani = ₹ 18.50
Money spent on ice-cream=₹ 11.75
Money left with Rani = ₹ 18.50 – ₹ 11.75 = ₹ 6.75
Ex 8.6 Class 6 Maths Question 5.
Tina had 20 m 5 cm long cloth. She cuts 4 m 50 cm length of cloth from this for making a curtain. How much cloth is left with her?
Solution:
Total length of cloth = 20 m 5 cm = 20.05 m
Length cut out for curtain = 4 m 50 cm = 4.50 m
Cloth left over = 20.05 m – 4.50 m = 15.55 m
Ex 8.6 Class 6 Maths Question 6.
Namita travels 20 km 50 m every day. Out of this she travels 10 km 200 m by bus and the rest by auto. How much distance does she travel by auto?
Solution:
Total distance travelled by Namita
20 km 50 m = 20.050 km
Distance travelled by bus = 10 km 200 m = 10.200 km
∴ Distance travelled by auto = 20.050 km – 10.200 km
= 9.850 km
Ex 8.6 Class 6 Maths Question 7.
Aakash bought vegetables weighing 10 kg. Out of this, 3 kg 500 g is onions, 2 kg 75 g is tomatoes and the rest is potatoes. What is the weight of the potatoes?
Solution:
Total weight of vegetables bought = 10 kg
Weight of onions = 3 kg 500 g = 3.500 kg
Weight of tomato= 2 kg 75 g = 2.075 kg
∴ Total weight of these vegetables =3.500 kg + 2.075 kg = 5.575 kg
As per question
Weight of potatoes = 10 kg – 5.575 kg = 4.425 kg
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