1. Boolean Algebra can be used to
- Simplify any algebraic expressions
- Minimize the number of switches in a circuits
- Solve the mathematical problem
- Perform arithmetic calculation
A. Simplify any algebraic expressions
2. An inverter gates can be developed using
- Two diodes
- A resistance and capacitance
- A transistor
- An inductance and capacitance
C. A transistor
3. if an input A is given to an inverter,the output will be
- 1/A
- 1
- A
- ‾A
D. ‾A
4. The output of two input OR gate is high
- . Only if both inputs are high
- Only if both inputs are low
- Only if one input is high and the other is low
- If at least one of the inputs is low
D. If at least one of the inputs is low
5. the output of a two input AND gate is high
- only if both the inputs are high
- only if both the inputs are low
- only if one inputs is high and other is low
- if atleast one of the input is low
A. only if both the inputs are high
6. NAND gate means
- inversion followed by And Gates
- AND gates followed by an inverter
- AND gate followed by an or gate
- None of these
B. AND gates followed by an inverter
7. The out put of two input NAND gate is high
- .only if both the inputs are high
- only if both the inputs are low
- only if one input is high and other input is low
- if atleast one the inputs is low
D. if atleast one the inputs is low
8. A NOT gate means
- Inversion followed by an OR gate
- OR gate followed by an an inverter
- Not gate followed by an OR gate
- NAND gate followed by an OR gate
B. OR gate followed by an an inverter
9. The output of two input NOR gate is high
- Only if both the inputs are high
- only if both the inputs are low
- only if one of the input is high and the other is low
- if atleast one the inputs is high
B. only if both the inputs are low
10. A Digital word has even parity
- if it has even number of 1s
- if it has even number of 0 s
- if the decimal value of word is even
- None of these
A. if it has even number of 1s
11. An XOR gate gives a high output
- if there are odd number of 1s in the input
- if these are even number of 1 s in the input
- .if there are odd number of 0s in the input
- if there are even numbers of 1 s in the input
A. if there are odd number of 1s in the input
12. An exclusive NOR gate is logically equal to
- inverter followed by an XOR gate
- NOT gate followed by an exclusive XOR gate
- Exclusive OR gate followed by an inverter
- Complement of a NOR gate
C. Exclusive OR gate followed by an inverter
13. De Morgan’s theorem states that
- ¯(A+B) = ¯A.¯B AND ¯(A.B) = ¯A.¯B
- ¯(A+B) = ¯A+¯B AND ¯(A.B) = ¯( A).¯B
- ¯( A+B)=¯( A).¯B AND ¯(A.B) = ¯A+¯B
- ¯( A+B) = ¯A+¯B AND ¯(A.B)= ¯A+¯B
C. ¯( A+B)=¯( A).¯B AND ¯(A.B) = ¯A+¯B
14. The logic expression AB+ (A.B) can be implemented by given inputs And B to two input
- NOR gate
- Exclusive NOR gate
- Exclusive OR gate
- NAND gate
C. Exclusive OR gate
15. The logic expression AB+ ¯(A.B) can be implemented by given inputs A And B to two input
- NOR Gate
- Exclusive NOR gate
- Exclusive OR gate
- NAND Gate
B. Exclusive NOR gate
16. The gate ideally suited for bit comparison is a
- Two input exclusive NOR gate
- Two input exclusive OR gate
- Two input NAND date
- Two input NOR gate
A. Two input exclusive NOR gate
17. Two input Exclusive NOR gate gives high output
- when one input is high and the other is low
- only when the both the inputs are low
- when the both the inputs are same
- only when both the inputs are high
C. when the both the inputs are same
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