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Hello Students, Welcome to EduGrown Edutech Channel, Here in this page you got class 9 English Beehive All chapter Detailed video & Written Summary , notes, NCERT Solution, and More. Let’s Check it Now..

Class 9 Full English (Moments) Video Lectures | NCERT | By Vivek Sir– Click here

Chapter Wise Class 9 English ( Moments) Lectures

Chapter 1 The Lost Child
Chapter 2 The Adventures of Toto
Chapter 3 Iswaran the Storyteller
Chapter 4 In the Kingdom of Fools
Chapter 5 The Happy Prince
Chapter 6 Weathering the Storm in Ersama
Chapter 7 The Last Leaf
Chapter 8 A House is Not a Home
Chapter 9 The Accidental Tourist
Chapter 10 The Beggar

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Ch 2 Acids, Bases and Salts Class 10 Important Questions | NCERT Science Chapter-2

Ch 2 Acids, Bases and Salts Class 10 Important Questions

The start of class 10 marks the beginning of the foundation for class 11 and class 12. It is very important study the basics in order to understand each and every chapter properly. In this page, we have provided all the important question for cbse class 9 that could be asked in the examination. Students also need to study the ncert solutions for class 10 in order to gain more knowledge and understanding the lessons. Questions and Answers are way to learn the new things in a proper way. NCERT textbooks downloads for class 9 in pdf are also available for the students if they need more help. By downloading these books, they can study from it. Our experts also prepared revision notes for class 9 so that students should see the details of each and every chapters. Class 9 important questions are the best to revise all the chapters in the best way.

Short Answer Questions-I (SAQs-I): 2 Marks
Q1. Classify the following into acidic oxides anc basic oxides : Na₂O, SO₂, MgO, CO₂

AnswerAcidic oxides — SO₂, CO₂Basic oxides — Na₂O, MgO₂

Q2. What is the change in pH values of milk when it changes into curd? Explain.

Answer

pH decrease by the presence of lactic acid in curd because acids generally have a low pH value. Hence, pH will decrease when milk changes into curd.

Q3.What is cause of decay of tooth? What is the pH of mouth required.

Answer

The enamel of our tooth started getting damaged when pH of tooth is less than 5.5. Tooth decay starts when the pH of the mouth is lower than 5.5 . Bacteria present in the mouth produce acids by degradation of sugar and food particles remaining in the mouth after eating. Toothpaste is basic in nature is used to neutralize the acid.

Q4. A white powder is added while baking breads and cakes to make them soft and fluffy. What is the name of the powder? What are the main ingredients in it? What are the functions of each ingredient? AnswerBaking powder.Baking soda and an edible acid like tartaric acid. Baking soda (NaHCO₃) is used to release CO₂ gas when heated. Tartaric acid is used to avoid the bitter taste by reacting with the Na₂CO₃ formed.

Short Answer Questions-II (SAQs-II): 3 Marks

Q1. (a) What is the action of litmus on: (i) dry ammonia gas(ii) solution of ammonia gas in water (b) State the observations you would make on adding sodium hydroxide to aqueous solution of (i) ferrous sulphate(ii) aluminium chloride. Give balanced chemical equations.

Answer(a)

(i) No change in colour (ii) Red litmus turns blue

(b)

(i) 2NaOH(aq) + FeSO₄(aq) → Fe(OH)₂(s) + Na₂SO₄(aq) Sodium hydroxide + Ferrous sulphate → Ferrous hydroxide + Sodium Sulphate

(ii) 3NaOH(aq) + AlCl₃(aq) → Al(OH)₃(s) + NaCl(aq)Sodium hydroxide + Aluminium chloride → Aluminium hydroxide + Sodium chloride

Q2. Name the three products of ‘chlor-alkali process. Write one commercially or industrially important material each that can be prepared from each of these products.

AnswerThe three products are: Sodium hydroxide (NaOH), Chlorine (Cl₂) and Hydrogen (H₂).NaOH: used in making soaps and detergents and also in paper making or artificial fibres.Cl₂: PVC, pesticides, CFCs.H₂: fuels, margarine, NH₃ for fertilizers.

Q3. Draw a neat and labelled diagram to show the following activity: Action of dilute sulphuric acid on zinc granules(i) Name the gas evolved. (ii) How will you test for the gas.
Answer

(i) The gas evolved is hydrogen. (ii) Zn(s) + H₂SO₄(aq) → ZnSO₄(aq) + H₂(g) Test for H₂ gas: The presence of H₂ gas can be tested by passing the gas through soap solution and then bringing a burning splinter near the soap bubbles filled with the gas. If the gas burns with a pop sound, it is hydrogen.

Long Answer Questions (LAQs): 5 Marks

1. (i) Explain why is hydrochloric acid a strong acid and acetic acid, a weak acid. How can it be verified? (ii) Explain why aqueous solution of an acid conducts electricity. (iii) You have four solutions A, B, C and D. The pH of solution A is 6, B is 9, C is 12 and D is 7.(a) Identify the most acidic and most basic solutions.(b) Arrange the above four solutions in the increasing order of H+ ion concentration. (c) State the change in colour of pH paper on dipping in solution C and D.
Answer
(i) HCI will give rise to more H⁺ ions and CH₃COOH produces less H⁺ ions on dissociation. The colour of pH paper depends on the concentration of H⁺ ion. Colour becomes red for high H⁺ concentration.(ii) Aqueous solution of acids have H⁺ which carry electric current through the solution.(iii) (a) Most acidic: A and Most basic: C(b) C, B, D, A/C < B < D < A(c) In C: blue, In D: green

2. Give suitable reasons for the following statements: (i) Rain water conducts electricity but distilled water does not.(ii) We feel burning sensation in the stomach when we over eat.(iii) A tarnished copper vessel regains its shine when rubbed with lemon.(iv) The crystals of washing soda change to white powder on exposure to air. (v) An aqueous solution of sodium chloride is neutral but an aqueous solution of sodium carbonate is basic.
Answer
(i) Distilled water is a pure form of water, is neither acidic nor basic in nature. So distilled water does not dissociate into ions, since, conduction of electricity requires free ions so, distilled water does not conduct electricity. While rain water being an impure form of water, contains many ionic species. These ions are responsible for electrical conductivity of rain water.(ii) Because when we over eat too much HCI is produced in our stomach which causes burning sensation.(iii) Copper vessels tarnish is due to the formation of basic copper carbonate [Cu₂(OH)₂CO₃] which gets neutralized when rubbed with lemon and the copper vessel regains its shine.(iv) Washing soda (sodium carbonate decahydrate), Na₂CO₃.10H₂O when exposed to air, it loses 10 molecules of water and changes to white powder.(v) Sodium chloride is a salt of strong acid HCI and strong base NaOH, so it is neutral. Sodium carbonate is a salt of weak acid H₂CO₃ and strong base NaOH, so it is basic. NaCI + H₂O → NaOH + HCI Na₂CO₃ + H₂O → NaOH + H₂CO₃

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Ch 1 Chemical Reactions and Equations Class 10 Important Questions | NCERT Science Chapter-1

Ch 1 Chemical Reactions and Equations Class 10 Important Questions

Short Answer Questions-I (SAQs-I): 2 Marks

Q1. Why does the colour of copper sulphate solution change when an iron nail is dipped in it? Write chemical equation for the reaction involved.
Answer

Iron is more reactive than copper so it displaces copper from copper sulphate solution and forms iron sulphate, hence the colour of solution changes.Equation: Fe + CuSO₄ (aq) → FeSO₄ (aq) + CuO

Q2. State reason for the following: (i) Potato chips manufactures fill the packet of chips with nitrogen gas. (ii) Iron articles are shining when new, but get coated with a reddish brown powder, when left for some time.
Answer

(i) Potato chips manufactures fill the packet of chips with nitrogen gas to prevent rancidity.(ii) Rusting and corrosion.

Q3. A student prepares aqueous solutions of the following salts: Copper sulphate : ferrous sulphate, Sodium sulphate, barium chloride. Write the colour of each solution thus formed.
Answer

Copper sulphate — Green Ferrous sulphate — Pale green Sodium sulphate — Milky white Barium chloride — White

Q4. Barium chloride reacts with aluminium sulphate to give, aluminium chloride and barium sulphate.(i) State the two types in which the above reaction can be classified. (ii) Translate the above statement into a chemical equation.
Answer

(i) Double displacement reaction and Precipitation reaction. (ii) 3BaCl₂ + Al₂(SO₄)₃ → 2AlCl₃ + 3BaSO₄(↓)

Short Answer Questions-II (SAQs-II): 3 Marks

Q1. Write one equation each for decomposition reactions where energy is supplied in the form of heat, light and electricity.
Answer

(i) Decomposition by heat of lead nitrate.

(ii) Decomposition by light of Silver Chloride

(iii) Decomposition by electricity of Water

Q2. State the kind of chemical reactions in the following examples in terms of loss and gain of energy:
(i) Digestion of food in stomach
(ii) Combustion of coal in air
(iii) Heating of limestone.
Answer

Digestion of food in StomachC₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O + EnergyEnergy is released in the process. It is exothermic reaction.Combustion of CoalCoal is Carbon. It is a combustion reaction.C+O₂→CO₂Energy is released in the process hence it is known as exothermic reaction.Heating of Limestone. Limestone is calcium carbonate. Ca₂CO₃

Energy is absorbed in the process. So, the reaction is endothermic reaction.

Q3. A solution of a substance ‘X’ is used for testing carbon dioxide. Write the equation of the reaction of X with carbon dioxide. (b) How is X obtained? Write chemical equation.
Answer
(a) Substance X is lime water which is aqueous solution of Calcium Hydroxide. Ca(OH)₂ (aq)+CO₂ (g)→CaCO₃ (s)+H₂O(l)When limewater reacts with Carbon di oxide, it turns milky, that is Calcium Hydroxide.
(b) Calcium oxide reacts vigorously with water to produced slaked time (calcium hydroxide) releasing a large amount of heat.

Q4. Write the steps for balancing the chemical equation for the formation of ammonia by the combination of nitrogen and hydrogen.
Answer
First, we write the skeletal chemical equation for the process.N₂+H₂→NH₃Examine the number of atoms of different elements present in the unbalanced equation.In the above reaction both the sides Nitrogen and Oxygen both are unbalanced.To balance hydrogen, H₂ is multiplied by 3 LHS. It makes 6H-atoms on the left hand side. Now, to balance hydrogen, in RHS, 2 is multiplied to NH3. Nitrogen is balanced automatically. N₂ (g)+3H₂ (g)→2NH₃ (g)

Long Answer Questions (LAQs): 5 Marks

Q1. (a) Explain the term “rancidity.” Name the type of chemical reaction responsible for causing rancidity and define it. (b) Write three methods for preventing rancidity of food.
Answer
We have seen food getting contaminated and having an unpleasant smell if it is left open in summer. In a hot weather, Oil present in food get oxidized and become Rancid. Such food is not recommended for consumption. The food is getting oxidized so the reaction is oxidation reaction.Methods for preventing food from getting oxidized are:-(a) Food is kept in cool place like refrigerator.(b) Packaging should be air tight(c) Antioxidants should be added to food.

Q2. (a) List any three observations that determine that a chemical reaction has taken place. Also list three informations that cannot be obtained about a chemical reaction, merely by its chemical equation.(b) Balance the following chemical equations.(i) Fe + H₂O → Fe₃O₄ + H₂(ii) CO₂ + H₂O → C₆H₁₂O₆+O₂
Answer
The three observations are(i) Change of color(ii) Change of temperature(iii) Evolution of Gas The three informations are Atmospheric conditions(i) Catalyst involved(ii) Physical states of reactants and productsBalancing Equations(i) 3Fe+4H₂O→Fe₃O₄+4H₂(ii) 6CO₂+6H₂O→C₆H₁₂O₆+6O₂

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Probability Class 10 Important Questions | NCERT Maths Chapter-15

Probability Class 10 Important Questions

Question 4.
In a single throw of a pair of different dice, what is the probability of getting

a prime number on each dice?
a total of 9 or 11?

Solution:
Total possible cases when two dice are thrown together = 6 x 6 = 36
Favourable cases when both numbers are prime are (2, 2), (2, 3), (2, 5), (3, 2), (3, 3),(3, 5), (5, 2), (5, 3), (5,5), i.e. 9 outcomes

(ii) Favourable cases when sum of numbers are 9 or 11 are (3, 6), (4, 5), (5, 4), (5, 6),(6, 3), (6,5), i.e. 6 outcomes

Question 5.
Two different dice are thrown together. Find the probability of:

getting a number greater than 3 on each die.
getting a total of 6 or 7 of the numbers on two dice

Solution:

When two dice are thrown together total possible outcomes = 6 X 6 = 36
Favourable outcomes when both dice have number more than 3 are (4, 4), (4, 5),(4, 6), (5, 4), (5, 5), (5, 6), (6,4), (6,5), (6, 6), i.e. 9 outcomes.

=9/36=1/4
Favourable outcomes when sum of the numbers appearing on the dice is 6 or 7 are, i.e. (1,5), (1, 6), (2,4), (2,5), (3,3), (3,4), (4, 2), (4, 3), (5,1), (5,2), (6,1), outcomes.
P(a total of 6 or 7) =11/36

Question 6.
A box consists of 100 shirts of which 88 are good, 8 have minor defects and 4 have major defects. Ramesh, a shopkeeper will buy only those shirts which are good but ‘Kewal’ another shopkeeper will not buy shirts with major defects. A shirt is taken out of the box at random. What is the probability that

Ramesh will buy the selected shirt?
‘Kewal’ will buy the selected shirt?

Solution:

When one shirt is taken out, then number of total possible outcomes = 100
Ramesh will purchase when shirt is good,
Favourable outcomes = number of good shirts = 88
Kewal will buy shirt if a shirt is not having major defect.
Number of favourable outcomes = Number of shirts without major defect = 96
P(Kewal buys a shirt) =96/100=24/25

Question 7.
Three different coins are tossed together. Find the probability of getting

exactly two heads
at least two heads
at least two tails.

Solution:
Possible outcomes when three coins are tossed HHH, HHT, HTT, TTT, THH, TTH, HTH, THT

Number of exactly two heads are HHT, HTH and THH.
P(exactly two heads) = 3/8
In case of at least two heads, outcomes are HHT, HTH, THH and HHH.
P(at least two heads) = 4/8=1/2
In case of at least two tails, outcomes are TTH, THT, HTT and TTT.
P(at least two tails) = 4/8=1/2

Question 8.
From a pack of 52 playing cards, Jacks, Queens and Kings of red colour are removed. From the remaining, a card is drawn at random. Find the probability that drawn card is:

a black king.
a card of red colour.
a card of black colour.

Solution:
Removed red colour cards = 3×2 = 6
Remaining cards = 52 – 6 = 46

Number of black kings = 2
P(a black king) = 2/46=1/23
Number of red colour cards = 26
Remaining red colour cards = 26 – 6 = 20
P(a card of red colour) = 20/46=10/23
Number of black cards = 26
P(a black colour card) =26/46=13/23

Question 9.
There are 100 cards in a bag on which numbers from 1 to 100 are written. A card is taken out from the bag at random. Find the probability that the number on the selected card:

is divisible by 9 and is a perfect square.
is a prime number greater than 80.

Solution:
Total possible cases = 100

Favourable cases when number is a perfect square and is divisible by 9 are 9, 36 and 81.
So, number of favourable cases = 3
Favourable cases the prime numbers greater than 80 are 83, 89 and 97
So, number of favourable cases = 3

Question 10.
A game consist of tossing a one-rupee coin 3 times and nothing the outcome each time. Ramesh will win the game if all the show the tosses same result, (i.e. either all three heads or all three tails) and loses the game otherwise. Find the probability that Ramesh will lose the game.
Solution:
When three coins are tossed together, then total outcomes are HHH, HHT, HTT, TTT, TTH, THH, HTH, THT Total possible cases = 8
Favourable cases to win the game are HHH or TTT, i.e. two cases.

Required probability = P(Ramesh will loose the game) = 1 -1/4=3/4

Long Answer Type Questions [4 Marks]

Question 11.
A game of chance consists of spinning an arrow on a circular board, divided into 8 equal parts, which comes to rest pointing at one of the numbers 1,2,3,…, 8 which are equally likely outcomes. What is the probability that the arrow will point at

an odd number
a number greater than 3
a number less than 9.

Solution:

Total possible outcomes when the arrow points at one of the numbers are 8.
Favourable outcomes when the required number is odd are 1, 3, 5, 7, i.e. 4 outcomes.
Favourable outcomes when the required number is more than 3 are 4,5,6,7, 8, i.e. 5 outcomes.
Favourable outcomes when the required number is less than 9 are 1,2,3,4,5,6,7,8 i.e 8 outcomes

Question 12.
A number JC is selected at random from the numbers 1,2,3 and 4. Another number y is selected at random from the numbers 1, 4, 9 and 16. Find the probability that product of JC and y is less than 16.
Solution:
x can be any one of 1, 2, 3 or 4 andy can be any one of 1, 4, 9 or 16.
Total number of cases of xy = 16
Number of cases when product is less than 16 are 1 x 1,1 x 4,1 x 9, 2 x 1, 2 x 4, 3 x 1, 3 x 4,4 x 1, i.e. 8 cases.

Question 13.
A number x is selected at random from the numbers 1,4,9,16 and another numbery is selected at random from the numbers 1, 2, 3, 4. Find the probability that the value of xy is more than 16
Solution:
x can be 1, 4, 9 or 16 andy can be 1, 2,3 or 4.
Total number of cases of Ay are 16.
Number of cases when Ay is more than 16 are (9 x 2), (9 x 3), (9 x 4), (16 x 2), (16 x 3), (16 x 4), i.e. 6 cases.
6 3
P(value of xy more than 16) =6/16=3/8

Question 14.
In figure is shown a disc on which a player spins an arrow twice. The fraction a/b is formed, where ‘a’ is the number of sector on which arrow stops on the first and b is the numberof the sector in which the arrow stops on second spin. On each spin, each sector has equal chance of selection by the arrow. Find the probability that the a/b> 1.
Probability Class 10 Maths CBSE Important Questions With Solutions 16
Solution:
For a/b > 1, when a = 1, b can not take any value
a = 2, b can take 1 value
a = 3, b can take 2 value, i.e. 1 and 2
a = 4, b can take 3 value, i.e. 1, 2, 3
a = 5, b can take 4 value, i.e. 1, 2, 3,4
a = 6, b can take 5 value, i.e. 1,2,3,4,5
Total possible outcomes = 6 x 6 = 36
Favourable outcomes = 1 + 2 + 3 + 4 + 5 = 15

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Statistics Class 10 Important Questions | NCERT Maths Chapter-14

Surface Areas and Volumes Class 10 Important Questions

Question 3.
Statistics Class 10 Maths CBSE Important Questions With Solutions 2
Solution:

Question 4.
Statistics Class 10 Maths CBSE Important Questions With Solutions 4
Solution:

Short Answer Type Questions II [3 Marks]

Question 5.
The following data gives the information on the observed life times (in hours) of 150 electrical components
Statistics Class 10 Maths CBSE Important Questions With Solutions 6
Solution:

Question 6.
The average score of boys in the examination of a school is 71 and that of the the girls is 73. The average score of the school in the examination is 71.8. Find the ratio of the number of boys to the number of girls who appeared in the examination.
Solution:
Let number of boys in the school be x
Average score of boys = 71
Total score of boys in the examination of the school = 71xx = 71x
Let number of girls in the school be y
Average score of girls = 73
Total score of girls in the examination of the school = 73 x y = 73y
Now,
average score of the school in examination = 71.8
Statistics Class 10 Maths CBSE Important Questions With Solutions 8

Question 7.
Statistics Class 10 Maths CBSE Important Questions With Solutions 9

Solution:

Long Answer Type Questions [4 Marks]

Question 8.
Statistics Class 10 Maths CBSE Important Questions With Solutions 13
Solution:

Question 9.
Statistics Class 10 Maths CBSE Important Questions With Solutions 18
Solution:

Question 10.
Statistics Class 10 Maths CBSE Important Questions With Solutions 20
Solution:

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Surface Areas and Volumes Class 10 Important Questions | NCERT Maths Chapter-13

Surface Areas and Volumes Class 10 Important Questions

Question 1.
In Figure, a decorative block, made up of two solids a cube and a hemisphere. The base of the block is a cube of side 6 cm and the hemisphere fixed on the top has a diameter of 3.5 cm. Find the total surface area of the block.(use π=22/7)
Surface Areas and Volumes Class 10 Maths CBSE Important Questions With Solutions 1
Solution:
Side of the cube = 6 cm

Question 2.
A well of diameter 4 m is dug 21 m deep. The earth taken out of it has been spread evenly all around it in the shape of a circular ring of width 3 m to form an embankment. Find the height of the embankment
Solution:
Surface Areas and Volumes Class 10 Maths CBSE Important Questions With Solutions 3

Question 3.
The sum of the radius of base and height of a solid right circular cylinder is 37 cm. If the total surface area of the solid cylinder is 1628 sq. cm, find the volume of the cylinder, (use π=22/7)
Solution:
Surface Areas and Volumes Class 10 Maths CBSE Important Questions With Solutions 5

Question 4.
A right circular cone of radius 3 cm, has a curved surface area of 47.1 cm2. Find the volume of the cone, (use π = 3.14)
Solution:
Surface Areas and Volumes Class 10 Maths CBSE Important Questions With Solutions 6

Question 5.
A toy is in the form of a cone of base radius 3.5 cm mounted on a hemisphere of base diameter 7 cm. If the total height of the toy is 15.5 cm, find the total surface area of the toy(use π =22/7)
Solution:
Surface Areas and Volumes Class 10 Maths CBSE Important Questions With Solutions 7

Question 6.
In figure, a tent is in the shape of a cylinder surmounted by a conical top of same diameter. If the height and diameter of cylindrical part are 2.1 m and 3 m respectively and the slant height of conical part is 2.8 m, find the cost of canvas needed to make the tent if the canvas is available at therate of rupees 500/sq. metre. (use π=22/7)
Surface Areas and Volumes Class 10 Maths CBSE Important Questions With Solutions 8
Solution:

Question 7.
A conical vessel, with base radius 5 cm and height 24 cm, is full of water. This water is emptied into a cylindrical vessel of base radius 10 cm. Find the height to which the water will rise in the cylindrical vessel
Solution:
Surface Areas and Volumes Class 10 Maths CBSE Important Questions With Solutions 10

Question 8.
A sphere of diameter 12 cm, is dropped in a right circular cylindrical vessel, partly filled with water. If the sphere is completely submerged in water, the water level in the cylindrical vessel rises by 3×5/9 cm. Find the diameter of the cylindrical vessel
Solution:
Surface Areas and Volumes Class 10 Maths CBSE Important Questions With Solutions 12

Question 9.
A hemispherical tank, of diameter 3 m, is full of water. It is being emptied by a pipe 3×4/7 litre per second. How much time will it take to make the tank half empty?
Solution:
Surface Areas and Volumes Class 10 Maths CBSE Important Questions With Solutions 13

Question 10.
A cylindrical tub, whose diameter is 12 cm and height 15 cm is full of ice-cream. The whole ice-cream is to be divided into 10 children in equal ice-cream cones, with conical base surmounted by hemispherical top. If the height of conical portion is twice the diameter of base, find the diameter of conical part of ice-cream cone.
Solution:
Surface Areas and Volumes Class 10 Maths CBSE Important Questions With Solutions 15
Question 11.
A metal container, open from the top, is in the shape of a frustum of a cone of height 21 cm with radii of its lower and upper circular ends are as 8 cm and 20 cm respectively. Find the cost of milk which can completely fill the container at of rupees 35/litre
Solution:

=1/3 x 22/7 x 21[400+64+160]=22 x 624/1000 liters[1 cm³=1/1000 l]
cost of 1l milk=35rupees
cost of milk in container=35 22 x 624/1000=480.48 rupees

Long Answer Type Questions [4 Marks]

Question 12.
A bucket open at the top is in the form of a frustum of a cone with a capacity of 12308.8 cm³. The radii of the top and bottom circular ends are 20 cm and 12 cm respectively. Find the height of the bucket and the area of metal sheet used in making the bucket, (use π=3.14)
Solution:
Let R, r and V be the upper radius, lower radius and volume of the frustum respectively then
R = 20 cm, r = 12 cm and V = 12508.8 cm³

12308.8 = 1/3x 3.14 [400 + 144 +240]h
h=12308.8 x 3/3.14 x 784 h=15 cm
Now, l (slant height) =√(20-12)²+15²=√64+225=√289=17 cm²
Total area of the metal sheet=curved surface area of the cone+area of the base= π(R+r)l+πr²
=π(20+12)x 17+π x 12 x 12
=π x 32 x 17 +144π =688π
=688 x 3.14 =2160.32 cm²

Question 13.
The perimeter of a right triangle is 60 cm. Its hypotenuse is 25 cm. Find the area of the triangle
Solution:
Surface Areas and Volumes Class 10 Maths CBSE Important Questions With Solutions 18

Question 14.
Due to heavy floods in a state, thousands were rendered homeless. 50 schools collectively offered to the state government to provide place and the canvas for 1500 tents to be fixed by the government and decided to share the whole expenditure equally. The lower part of each tent is cylindrical of base radius 2.8 m and height 3.5m, with conical upper part of same base radius but of height 2.1 m. If the canvas used to make the tents costs ? 120 per sq.m, find the amount shared by each school to set up the tents.What value is genetated by above problem?
Solution:
Surface Areas and Volumes Class 10 Maths CBSE Important Questions With Solutions 19

Question 15.
In figure, shown a right circular cone of height 30 cm. A small cone is cut off from the top by a plane parallel to the base. If the volume of the small cone is 1/27 of the volume of given cone, find at what height above the base is the section made.
Surface Areas and Volumes Class 10 Maths CBSE Important Questions With Solutions 20
Solution:

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