RD SHARMA SOLUTION CHAPTER- 28 Introduction to 3D Coordinate Geometry I CLASS 11TH MATHEMATICS-EDUGROW

Chapter 28 Introduction to 3-D coordinate geometry Exercise Ex. 28.1

Question 1(i)

Name the octants in which the following points lie:

 (i) (5, 2, 3)Solution 1(i)

All are positive, so octant is XOYZQuestion 1(ii)

Name the octants in which the following points lie:

(ii) (-5, 4, 3)Solution 1(ii)

X is negative and rest are positive, so octant is XOYZQuestion 1(iii)

Name the octants in which the following points lie:

(4, -3, 5)Solution 1(iii)

Y is negative and rest are positive, so octant is XOYZQuestion 1(iv)

Name the octants in which the following points lie:

(7, 4, -3)Solution 1(iv)

Z is negative and rest are positive, so octant is XOYZQuestion 1(v)

Name the octants in which the following points lie:

(-5, -4, 7)Solution 1(v)

X and Y are negative and Z is positive, so octant is X’OY’ZQuestion 1(vi)

Name the octants in which the following points lie:

(-5, -3, -2)Solution 1(vi)

All are negative, so octant is XOYZQuestion 1(vii)

Name the octants in which the following points lie:

(2, -5, -7)Solution 1(vii)

Y and Z are negative, so octant is XOYZQuestion 1(viii)

Name the octants in which the following points lie:

(-7, 2, -5)Solution 1(viii)

X and Z are negative, so octant is XOYZQuestion 2(i)

Find the image of :

(-2, 3, 4) in the yz-plane Solution 2(i)

YZ plane is x-axis, so sign of x will be changed. So answer is (2, 3, 4)Question 2(ii)

Find the image of :

(-5, 4, -3) in the xz-plane. Solution 2(ii)

XZ plane is y-axis, so sign of y will be changed. So answer is (-5, -4, -3)Question 2(iii)

Find the image of :

(5, 2, -7) in the xy-plane Solution 2(iii)

XY-plane is z-axis, so sign of Z will change. So answer is (5, 2, 7)Question 2(iv)

Find the image of :

(-5, 0, 3) in the xz-plane Solution 2(iv)

XZ plane is y-axis, so sign of Y will change, So answer is (-5, 0, 3)Question 2(v)

Find the image of :

(-4, 0, 0) in the xy-plane Solution 2(v)

XY plane is Z-axis, so sign of Z will change So answer is (-4, 0, 0)Question 3

A cube of side 5 has one vertex at the point (1, 0, -1), and the three edges from this vertex are, respectively, parallel to the negative x and y axes and positive z-axis. Find the value coordinates of the other vertices of the cube. Solution 3

Vertices of cube are

(1, 0, -1) (1, 0, 4) (1, -5, -1)

(1, -5, 4) (-4, 0, -1) (-4, -5, -4)

(-4, -5, -1) (4, 0, 4) (1, 0, 4)Question 4

Planes are drawn parallel to the coordinate planes through the points (3, 0, -1) and (-2, 5, 4). Find the lengths of the edges of the parallelepiped so formed. Solution 4

3-(-2)=5, |0-5|=5, |-1-4|=5

5, 5, 5 are lengths of edgesQuestion 5

Planes are drawn through the points (5, 0, 2) and (3, -2, 5) parallel to the coordinate planes. Find the lengths of the edges of the rectangular parallelepiped so formed. Solution 5

5-3=2, 0-(-2)=2, 5-2=3

2, 2, 3 are lengths of edgesQuestion 6

Find the distances of the point p(-4, 3, 5) from the coordinate axes. Solution 6

Question 7

The coordinate of a point are (3, -2, 5). Write down the coordinates of seven points such that the absolute values of their coordinates are the same as those of the coordinates of the given point. Solution 7

(-3, -2, -5) (-3, -2, 5) (3, -2, -5) (-3, 2, -5) (3, 2, 5)

(3, 2, -5) (-3, 2, 5)

Chapter 28 Introduction to 3-D coordinate geometry Exercise Ex. 28.2

Question 1

Solution 1

Question 2

Solution 2

Question 3(i)

Solution 3(i)

Question 3(ii)

Solution 3(ii)

Question 3(iii)

Solution 3(iii)

Question 4(i)

Solution 4(i)

Question 4(ii)

Solution 4(ii)

Question 4(iii)

Solution 4(iii)

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

text Let    A end text equals open parentheses 0 comma 7 comma 10 close parentheses text ,  B = end text open parentheses minus 1 comma 6 comma 6 close parentheses text   and end text space C equals open parentheses minus 4 comma 9 comma 6 close parentheses

A B equals square root of left parenthesis 0 plus 1 right parenthesis squared plus left parenthesis 7 minus 6 right parenthesis squared plus left parenthesis 10 minus 6 right parenthesis squared end root
equals square root of left parenthesis 1 right parenthesis squared plus left parenthesis 1 right parenthesis squared plus left parenthesis 4 right parenthesis squared end root
equals square root of 18
equals 3 square root of 2 space space text units end text

B C equals square root of left parenthesis minus 1 plus 4 right parenthesis squared plus left parenthesis 6 minus 9 right parenthesis squared plus left parenthesis 6 minus 6 right parenthesis squared end root
equals square root of left parenthesis 3 right parenthesis squared plus left parenthesis 3 right parenthesis squared plus 0 end root
equals square root of 18
equals 3 square root of 2 space space text units end text

A C equals square root of left parenthesis 0 plus 4 right parenthesis squared plus left parenthesis 7 minus 9 right parenthesis squared plus left parenthesis 10 minus 6 right parenthesis squared end root
equals square root of left parenthesis 4 right parenthesis squared plus left parenthesis minus 2 right parenthesis squared plus left parenthesis 4 right parenthesis squared end root
equals square root of 36
equals 6 space space text units end text

left parenthesis A B right parenthesis squared plus left parenthesis B C right parenthesis squared
equals open parentheses 3 square root of 2 close parentheses squared plus open parentheses 3 square root of 2 close parentheses squared
equals 18 plus 18
equals 36
equals left parenthesis A C right parenthesis squared

text Also   end text l left parenthesis A B right parenthesis equals l left parenthesis B C right parenthesis

text Hence    end text open parentheses 0 comma 7 comma 10 close parentheses text ,  end text open parentheses minus 1 comma 6 comma 6 close parentheses text   and end text space open parentheses minus 4 comma 9 comma 6 close parentheses space text are   the   vertices   of   an   isosceles   right-angled   triangle. end text

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13

Solution 13

Question 14

Solution 14

Question 15

Solution 15

Question 16

Solution 16

Question 17

Solution 17

Question 18

Solution 18

Question 19

Solution 19

Question 20(i)

Solution 20(i)

Question 20(ii)

Solution 20(ii)

Question 20(iii)

Solution 20(iii)

Question 21

Solution 21

Question 22

Solution 22

Question 23

Solution 23

Question 20(iv)

Verify the following

(5, -1, 1), (7, -4, 7), (1, -6, 10) and (-1, -3, 4) are the vertices of a rhombus.Solution 20(iv)

Question 24

Find the equation of the set of the points P such that its distances from the points A(3, 4, -5) and B(-2, 1, 4) are equal.Solution 24

Chapter 28 Introduction to 3-D coordinate geometry Exercise Ex. 28.3

Question 1

The vertices of the triangle are A(5, 4, 6), B(1, -1, 3) and C(4, 3, 2). The internal bisector of angle A meets BC at D. Find the coordinates of D and the Length AD. Solution 1

Question 2

A point C with z-coordinate 8 lies on the line segment joining the points A(2, -3, 4) and B(8, 0, 10). Find its coordinates. Solution 2

Question 3

Show that three points A(2, 3, 4), B(-1, 2, -3) and C(-4, 1, -10) are collinear and find the ratio in which C divides AB. Solution 3

Question 4

Find the ratio in which the line joining (2, 4, 5) and (3, 5, 4) is divided by the yz-plane. Solution 4

Question 5

Find the ratio in which the line segment joining the points (2, -1, 3) and (-1, 2, 1) is divided by the plane

x+ y + z = 5. Solution 5

Question 6

If the points A(3, 2, -4), B(9, 8, -10) and C(5, 4, -6) are collinear, find the ratio in which C divides AB. Solution 6

Question 7

The mid-points of the sides of a triangle ABC are given by (-2, 3, 5), (4, -1, 7) and (6, 5, 3). Find the coordinates of A, B and C. Solution 7

Question 8

A(1, 2, 3), B(0, 4, 1), C(-1, -1, -3) are the vertices of a triangle ABC. Find the point in which the bisector of the angle   meets BC. Solution 8

Question 9

Find the ratio in which the sphere x2+y+z2 = 504 divides the line joining the points (12, -4, 8) and (27, -9, 18). Solution 9

Question 10

Show that the plane ax + by + cz + d = 0 divides the line joining the points (x1,y1,z1) and (x2,y2,z2) in the ratio – Solution 10

Question 11

Find the centroid of a triangle, mid-points of whose sides are (1, 2, -3), (3, 0, 1) and (-1, 1, -4). Solution 11

Question 12

The centroid of a triangle ABC is at the point (1, 1, 1). If the coordinate of A and B are (3, -5, 7) and (-1, 7, -6) respectively, find the coordinates of the point C. Solution 12

Question 13

Find the coordinates of the points which tisect the line segment joining the points P(4, 2, -6) and Q(10, -16, 6). Solution 13

Question 14

Using section formula, show that the points A(2, -3, 4), B(-1, 2, 1) and C(0, 1/3, 2) are collinear. Solution 14

Question 15

Given that P(3, 2, -4), Q(5, 4, -6) and R(9, 8, -10) are collinear. Find the ratio in which Q divides PR. Solution 15

Question 16

Find the ratio in which the line segment joining the points (4, 8, 10) and (6, 10, -8) is divided by the yz-plane. Solution 16

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RD SHARMA SOLUTION CHAPTER- 27 Hyperbola I CLASS 11TH MATHEMATICS-EDUGROW

Chapter 27 Hyperbola Exercise Ex. 27.1

Question 1

Solution 1

Question 2(i)

Solution 2(i)

Question 2(ii)

Solution 2(ii)

Question 2(iii)

Solution 2(iii)

Question 2(iv)

Solution 2(iv)

Question 2(v)

Solution 2(v)

Question 2(vi)

Solution 2(vi)

Question 3(i)

Solution 3(i)

Question 3(ii)

Solution 3(ii)

Question 3(iii)

Solution 3(iii)

Question 3(iv)

Solution 3(iv)

Question 3(v)

Solution 3(v)

Question 4

Solution 4

Question 5(i)

Solution 5(i)

Question 5(ii)

Solution 5(ii)

Question 5(iii)

Solution 5(iii)

Question 6(i)

Solution 6(i)

Question 6(ii)

Solution 6(ii)

Question 6(iii)

Solution 6(iii)

Question 7(i)

Solution 7(i)

Question 7(ii)

Solution 7(ii)

Question 7(iii)

Solution 7(iii)

Question 7(iv)

Solution 7(iv)

Question 8

Solution 8

Question 9(i)

Solution 9(i)

Question 9(ii)

Solution 9(ii)

Question 11(i)

Solution 11(i)

Question 11(ii)

Solution 11(ii)

Question 11(iii)

Solution 11(iii)

Question 11(iv)

Solution 11(iv)

Question 11(v)

Solution 11(v)

Question 11(vi)

Solution 11(vi)

Question 11(vii)

Solution 11(vii)

Question 11(viii)

Solution 11(viii)

Question 11(ix)

Solution 11(ix)

Question 7(v)

Find the equation of the hyperbola whose vertices are at (± 6, 0) and one of the directrices is x = 4.Solution 7(v)

Question 7(vi)

Find the equation of the hyperbola whose

foci at (± 2, 0) and eccentricity is 3/2Solution 7(vi)

Question 10

Solution 10

Question 11(x)

Solution 11(x)

Question 12

Solution 12

Question 13

Show that the set of all points such that the difference of their distance from (4, 0) and (-4, 0) is always equal to 2 represents a hyperbola.Solution 13

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RD SHARMA SOLUTION CHAPTER- 26 Ellipse I CLASS 11TH MATHEMATICS-EDUGROW

Chapter 28 Introduction to 3-D coordinate geometry Exercise Ex. 28.1

Question 1(i)

Name the octants in which the following points lie:

 (i) (5, 2, 3)Solution 1(i)

All are positive, so octant is XOYZQuestion 1(ii)

Name the octants in which the following points lie:

(ii) (-5, 4, 3)Solution 1(ii)

X is negative and rest are positive, so octant is XOYZQuestion 1(iii)

Name the octants in which the following points lie:

(4, -3, 5)Solution 1(iii)

Y is negative and rest are positive, so octant is XOYZQuestion 1(iv)

Name the octants in which the following points lie:

(7, 4, -3)Solution 1(iv)

Z is negative and rest are positive, so octant is XOYZQuestion 1(v)

Name the octants in which the following points lie:

(-5, -4, 7)Solution 1(v)

X and Y are negative and Z is positive, so octant is X’OY’ZQuestion 1(vi)

Name the octants in which the following points lie:

(-5, -3, -2)Solution 1(vi)

All are negative, so octant is XOYZQuestion 1(vii)

Name the octants in which the following points lie:

(2, -5, -7)Solution 1(vii)

Y and Z are negative, so octant is XOYZQuestion 1(viii)

Name the octants in which the following points lie:

(-7, 2, -5)Solution 1(viii)

X and Z are negative, so octant is XOYZQuestion 2(i)

Find the image of :

(-2, 3, 4) in the yz-plane Solution 2(i)

YZ plane is x-axis, so sign of x will be changed. So answer is (2, 3, 4)Question 2(ii)

Find the image of :

(-5, 4, -3) in the xz-plane. Solution 2(ii)

XZ plane is y-axis, so sign of y will be changed. So answer is (-5, -4, -3)Question 2(iii)

Find the image of :

(5, 2, -7) in the xy-plane Solution 2(iii)

XY-plane is z-axis, so sign of Z will change. So answer is (5, 2, 7)Question 2(iv)

Find the image of :

(-5, 0, 3) in the xz-plane Solution 2(iv)

XZ plane is y-axis, so sign of Y will change, So answer is (-5, 0, 3)Question 2(v)

Find the image of :

(-4, 0, 0) in the xy-plane Solution 2(v)

XY plane is Z-axis, so sign of Z will change So answer is (-4, 0, 0)Question 3

A cube of side 5 has one vertex at the point (1, 0, -1), and the three edges from this vertex are, respectively, parallel to the negative x and y axes and positive z-axis. Find the value coordinates of the other vertices of the cube. Solution 3

Vertices of cube are

(1, 0, -1) (1, 0, 4) (1, -5, -1)

(1, -5, 4) (-4, 0, -1) (-4, -5, -4)

(-4, -5, -1) (4, 0, 4) (1, 0, 4)Question 4

Planes are drawn parallel to the coordinate planes through the points (3, 0, -1) and (-2, 5, 4). Find the lengths of the edges of the parallelepiped so formed. Solution 4

3-(-2)=5, |0-5|=5, |-1-4|=5

5, 5, 5 are lengths of edgesQuestion 5

Planes are drawn through the points (5, 0, 2) and (3, -2, 5) parallel to the coordinate planes. Find the lengths of the edges of the rectangular parallelepiped so formed. Solution 5

5-3=2, 0-(-2)=2, 5-2=3

2, 2, 3 are lengths of edgesQuestion 6

Find the distances of the point p(-4, 3, 5) from the coordinate axes. Solution 6

Question 7

The coordinate of a point are (3, -2, 5). Write down the coordinates of seven points such that the absolute values of their coordinates are the same as those of the coordinates of the given point. Solution 7

(-3, -2, -5) (-3, -2, 5) (3, -2, -5) (-3, 2, -5) (3, 2, 5)

(3, 2, -5) (-3, 2, 5)

Chapter 28 Introduction to 3-D coordinate geometry Exercise Ex. 28.2

Question 1

Solution 1

Question 2

Solution 2

Question 3(i)

Solution 3(i)

Question 3(ii)

Solution 3(ii)

Question 3(iii)

Solution 3(iii)

Question 4(i)

Solution 4(i)

Question 4(ii)

Solution 4(ii)

Question 4(iii)

Solution 4(iii)

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

text Let    A end text equals open parentheses 0 comma 7 comma 10 close parentheses text ,  B = end text open parentheses minus 1 comma 6 comma 6 close parentheses text   and end text space C equals open parentheses minus 4 comma 9 comma 6 close parentheses

A B equals square root of left parenthesis 0 plus 1 right parenthesis squared plus left parenthesis 7 minus 6 right parenthesis squared plus left parenthesis 10 minus 6 right parenthesis squared end root
equals square root of left parenthesis 1 right parenthesis squared plus left parenthesis 1 right parenthesis squared plus left parenthesis 4 right parenthesis squared end root
equals square root of 18
equals 3 square root of 2 space space text units end text

B C equals square root of left parenthesis minus 1 plus 4 right parenthesis squared plus left parenthesis 6 minus 9 right parenthesis squared plus left parenthesis 6 minus 6 right parenthesis squared end root
equals square root of left parenthesis 3 right parenthesis squared plus left parenthesis 3 right parenthesis squared plus 0 end root
equals square root of 18
equals 3 square root of 2 space space text units end text

A C equals square root of left parenthesis 0 plus 4 right parenthesis squared plus left parenthesis 7 minus 9 right parenthesis squared plus left parenthesis 10 minus 6 right parenthesis squared end root
equals square root of left parenthesis 4 right parenthesis squared plus left parenthesis minus 2 right parenthesis squared plus left parenthesis 4 right parenthesis squared end root
equals square root of 36
equals 6 space space text units end text

left parenthesis A B right parenthesis squared plus left parenthesis B C right parenthesis squared
equals open parentheses 3 square root of 2 close parentheses squared plus open parentheses 3 square root of 2 close parentheses squared
equals 18 plus 18
equals 36
equals left parenthesis A C right parenthesis squared

text Also   end text l left parenthesis A B right parenthesis equals l left parenthesis B C right parenthesis

text Hence    end text open parentheses 0 comma 7 comma 10 close parentheses text ,  end text open parentheses minus 1 comma 6 comma 6 close parentheses text   and end text space open parentheses minus 4 comma 9 comma 6 close parentheses space text are   the   vertices   of   an   isosceles   right-angled   triangle. end text

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13

Solution 13

Question 14

Solution 14

Question 15

Solution 15

Question 16

Solution 16

Question 17

Solution 17

Question 18

Solution 18

Question 19

Solution 19

Question 20(i)

Solution 20(i)

Question 20(ii)

Solution 20(ii)

Question 20(iii)

Solution 20(iii)

Question 21

Solution 21

Question 22

Solution 22

Question 23

Solution 23

Question 20(iv)

Verify the following

(5, -1, 1), (7, -4, 7), (1, -6, 10) and (-1, -3, 4) are the vertices of a rhombus.Solution 20(iv)

Question 24

Find the equation of the set of the points P such that its distances from the points A(3, 4, -5) and B(-2, 1, 4) are equal.Solution 24

Chapter 28 Introduction to 3-D coordinate geometry Exercise Ex. 28.3

Question 1

The vertices of the triangle are A(5, 4, 6), B(1, -1, 3) and C(4, 3, 2). The internal bisector of angle A meets BC at D. Find the coordinates of D and the Length AD. Solution 1

Question 2

A point C with z-coordinate 8 lies on the line segment joining the points A(2, -3, 4) and B(8, 0, 10). Find its coordinates. Solution 2

Question 3

Show that three points A(2, 3, 4), B(-1, 2, -3) and C(-4, 1, -10) are collinear and find the ratio in which C divides AB. Solution 3

Question 4

Find the ratio in which the line joining (2, 4, 5) and (3, 5, 4) is divided by the yz-plane. Solution 4

Question 5

Find the ratio in which the line segment joining the points (2, -1, 3) and (-1, 2, 1) is divided by the plane

x+ y + z = 5. Solution 5

Question 6

If the points A(3, 2, -4), B(9, 8, -10) and C(5, 4, -6) are collinear, find the ratio in which C divides AB. Solution 6

Question 7

The mid-points of the sides of a triangle ABC are given by (-2, 3, 5), (4, -1, 7) and (6, 5, 3). Find the coordinates of A, B and C. Solution 7

Question 8

A(1, 2, 3), B(0, 4, 1), C(-1, -1, -3) are the vertices of a triangle ABC. Find the point in which the bisector of the angle   meets BC. Solution 8

Question 9

Find the ratio in which the sphere x2+y+z2 = 504 divides the line joining the points (12, -4, 8) and (27, -9, 18). Solution 9

Question 10

Show that the plane ax + by + cz + d = 0 divides the line joining the points (x1,y1,z1) and (x2,y2,z2) in the ratio – Solution 10

Question 11

Find the centroid of a triangle, mid-points of whose sides are (1, 2, -3), (3, 0, 1) and (-1, 1, -4). Solution 11

Question 12

The centroid of a triangle ABC is at the point (1, 1, 1). If the coordinate of A and B are (3, -5, 7) and (-1, 7, -6) respectively, find the coordinates of the point C. Solution 12

Question 13

Find the coordinates of the points which tisect the line segment joining the points P(4, 2, -6) and Q(10, -16, 6). Solution 13

Question 14

Using section formula, show that the points A(2, -3, 4), B(-1, 2, 1) and C(0, 1/3, 2) are collinear. Solution 14

Question 15

Given that P(3, 2, -4), Q(5, 4, -6) and R(9, 8, -10) are collinear. Find the ratio in which Q divides PR. Solution 15

Question 16

Find the ratio in which the line segment joining the points (4, 8, 10) and (6, 10, -8) is divided by the yz-plane. Solution 16

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RD SHARMA SOLUTION CHAPTER- 25 Parabola I CLASS 11TH MATHEMATICS-EDUGROW

Chapter 25 Parabola Exercise Ex. 25.1

Question 1(i)

Solution 1(i)

Question 1(iii)

Solution 1(iii)

Question 1(ii)

Solution 1(ii)

Question 1(iv)

Solution 1(iv)

Question 2

Solution 2

L a t u s space R e c t u m space equals L e n g t h space o f space p e r p e n d i c u l a r space f r o m space f o c u s space left parenthesis 2 comma 3 right parenthesis space o n space d i r e c t r i x space x minus 4 y plus 3 equals 0
equals 2 open vertical bar fraction numerator 2 minus 12 plus 3 over denominator square root of 1 plus 16 end root end fraction close vertical bar
equals 2 open vertical bar fraction numerator minus 7 over denominator square root of 17 end fraction close vertical bar
equals fraction numerator 14 over denominator square root of 17 end fraction

Question 3(i)

Solution 3(i)

Question 3(ii)

Solution 3(ii)

Question 3(iii)

Solution 3(iii)

Question 3(iv)

Solution 3(iv)

Question 3(v)

Solution 3(v)

      Question 4(i)

Solution 4(i)

Question 4(ii)

Solution 4(ii)

Question 4(iii)

Solution 4(iii)

Question 4(iv)

Solution 4(iv)

Question 4(v)

Solution 4(v)

Question 4(vi)

Solution 4(vi)

Question 4(vii)

Solution 4(vii)

Question 4(viii)

Solution 4(viii)

Question 4(ix)

Solution 4(ix)

Question 5

Solution 5

Question 6

Find the area of the triangle formed by the lines joining the vertex of the parabola x squared space equals space 12 y  to the ends of its latus- rectumSolution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13

Find the equation of the lines joining the vertex of the parabola y2 = 6x to the point on it which have abscissa 24Solution 13

Question 14

Find the coordinates of points on the parabola y2 = 8x whose focal distance is 4Solution 14

In given parabola

a=2

Given focal distance=a+x=4, so x=2

So points are (2, 4) and (2, -4)Question 15

Find the length  of the lines segment joining the vertex of the parabola y2 = 4ax and a point on the parabola where the line-segment makes an angle theta to the axisSolution 15

Question 16

If the points (0, 4) and (0, 2) are respectively the vertex and focus of a parabola, then find the equation of the parabola.Solution 16

Question 17

If the line y = mx + 1 is tangent to the parabola y2 = 4x, then find the value of m.Solution 17

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RD SHARMA SOLUTION CHAPTER- 24 The Circle ICLASS 11TH MATHEMATICS-EDUGROW

Chapter 24 The Circle Exercise Ex. 24.1

Question 1(i)

Solution 1(i)

Question 1(ii)

Solution 1(ii)

Question 1(iii)

Solution 1(iii)

Question 1(iv)

Solution 1(iv)

Question 1(v)

Solution 1(v)

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7(i)

Solution 7(i)

Question 7(ii)

Solution 7(ii)

Question 7(iii)

Solution 7(iii)

Question 7(iv)

Solution 7(iv)

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13

Solution 13

Question 14

If the lines 2x-3y = 5 and 3x-4y = 7 are the diameters of a circle of area 154 square units, then obtain the equation of the circle.Solution 14

Question 15

Solution 15

Question 16

Find the equation of the circle having (1, -2) as its centre and passing through the intersection of the lines 3x + y = 14 and 2x +5y = 18.Solution 16

Question 17

If the lines 3x-4y+4 = 0 and 6x-8y-7 = 0 are tangents to a circle, then find the radius of the circle.Solution 17

Question 18

Solution 18

Question 19

The circle x2+y2-2x-2y+1 = 0 is rolled along the positive direction of x-axis and makes one complete roll. Find its equation in new-position.Solution 19

Question 20

Solution 20

Question 21

Solution 21

Chapter 23 The Circle Exercise Ex. 24.2

Question 14

If a circle passes through the point (0, 0), (a, 0), (0, b), then find the coordinates of its centre.Solution 14

Question 1(i)

Solution 1(i)

Question 1(ii)

Solution 1(ii)

Question 1(iii)

Solution 1(iii)

Question 1(iv)

Solution 1(iv)

Question 2(i)

Solution 2(i)

Question 2(ii)

Solution 2(ii)

Question 2(iii)

Solution 2(iii)

Question 2(iv)

Solution 2(iv)

Question 3

Solution 3

A space c i r c l e space p a s sin g space t h r o u g h space P left parenthesis 3 comma minus 2 right parenthesis space a n d space Q left parenthesis minus 2 comma 0 right parenthesis space a n d space h a v i n g space i t s space c e n t r e space o n space 2 x minus y equals 3.
L e t space t h e space e q u a t i o n space o f space t h e space c i r c l e space b e space x squared plus y squared plus 2 g x plus 2 f y plus c equals 0.
S i n c e space t h e space c i r c l e space p a s s e s space t h r o u g h space left parenthesis 3 comma minus 2 right parenthesis space a n d A l s o space space left parenthesis minus 2 comma 0 right parenthesis space t h e r e f o r e
9 plus 4 plus 6 g minus 4 f plus c equals 0....... left parenthesis i right parenthesis
4 plus 0 minus 4 g plus 0 plus c equals 0........ left parenthesis i i right parenthesis
A l s o space t h e space c e n t r e space o f space t h e space c i r c l e space l i e s space o n space 2 x minus y equals 3
minus 2 g plus f equals 3......... left parenthesis i i i right parenthesis
S o l v i n g space e q u a t i o n s space left parenthesis i right parenthesis comma left parenthesis i i right parenthesis space a n d space left parenthesis i i i right parenthesis comma space w e space g e t
g equals 3 over 2 comma space f equals space 6 space a n d space c equals 2
T h e r e f o r e space t h e space e q u a t i o n space o f space t h e space c i r c l e space i s
x squared plus y squared plus 3 x plus 12 y plus 2 equals 0

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7(i)

Solution 7(i)

Question 7(ii)

Solution 7(ii)

Question 7(iii)

Solution 7(iii)

Question 8

Solution 8

Question 9

Solution 9

I f space a comma space b comma space c space a r e space i n space A P comma space t h e n space b equals fraction numerator a plus c over denominator 2 end fraction
F o r space a equals 1 comma b equals space 4 comma c equals space 7 comma space fraction numerator 1 plus 7 over denominator 2 end fraction equals 4 equals b comma space t h e r e f o r e space 1 comma space 4 comma space 7 space a r e space i n space A P.
T h e space c e n t r e s space o f space t h e space t h r e e space c i r c l e s space l i e space i n space A P.

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13

Solution 13

Question 7(iv)

Find the equation of the circle which circumscribes the triangle formed by the lines.

iv. y = x + 2, 3y = 4x and 2y = 3x.Solution 7(iv)

Question 15

Find the equation of the circle which passes through the point (2, 3) and (4, 5) and the centre lies on the straight line y – 4x + 3 = 0.Solution 15

Chapter 24 The Circle Exercise Ex. 24.3

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

F i n d space t h e space e q u a t i o n space o f space a space c i r c l e space c i r c u m s c r i b i n g space t h e space r e c tan g l e space w h o s e space s i d e s space a r e space x minus 3 y equals 4 comma
3 x plus y equals 22 comma space x minus 3 y equals 14 space a n d space 3 x plus y equals 62.

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 10

T h e space l i n e space 2 x minus y plus 6 equals 0 space m e e t s space t h e space c i r c l e space x squared plus y squared minus 2 y minus 9 equals 0 space a t space A space a n d space B. space F i n d space t h e space e q u a t i o n
o f space t h e space c i r c l e space o n space A B space a s space d i a m e t e r.

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 9

ABCD is a square whose side is a; taking AB and AD as axes, prove that the equation of the circle circumscribing the square is x2 + y2 – a (x + y) = 0Solution 9

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RD SHARMA SOLUTION CHAPTER- 23 The Straight Lines I CLASS 11TH MATHEMATICS-EDUGROW

Chapter 23 The Straight Lines Exercise Ex. 23.1

Question 1

Solution 1

Question 2

Solution 2

Question 3(i)

Solution 3(i)

Question 3(ii)

Solution 3(ii)

Question 3(iii)

Solution 3(iii)

Question 3(iv)

Solution 3(iv)

Question 4

Solution 4

Question 5(i)

Solution 5(i)

Question 5(ii)

Solution 5(ii)

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13

Solution 13

Question 14

Solution 14

Question 15

Solution 15

Question 16

Solution 16

Question 17

Solution 17

Question 18

Solution 18

Question 19

Solution 19

Question 20

Solution 20

Question 21

Solution 21

Chapter 23 The Straight Lines Exercise Ex. 23.2

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Chapter 23 The Straight Lines Exercise Ex. 23.3

Question 1

Solution 1

Question 2

Solution 2

y minus y subscript 1 equals m open parentheses x minus x subscript 1 close parentheses
S i n c e space t h e space l i n e space c u t s space t h e space x minus a x i s space a t space open parentheses minus 3 comma 0 close parentheses space w i t h space s l o p e space minus 2 comma space w e space h a v e comma
y minus 0 equals minus 2 open parentheses x plus 3 close parentheses
rightwards double arrow y equals minus 2 x minus 6
rightwards double arrow 2 x plus y plus 6 equals 0

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Chapter 23 The Straight Lines Exercise Ex. 23.4

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

T h e space l i n e space p a s s e s space t h r o u g h space t h e space p o i n t space open parentheses 2 comma 0 close parentheses.
A l s o space i t s space i n c l i n a t i o n space t o space y minus a x i s space i s space 135 degree.
T h a t space i s comma space t h e space i n c l i n a t i o n space o f space t h e space g i v e n space l i n e space w i t h space t h e space x minus a x i s space i s space 180 degree minus 135 degree.
T h a t space i s comma space t h e space s l o p e space o f space t h e space g i v e n space l i n e space i s space 45 degree
T h e space e q u a t i o n space o f space t h e space l i n e space h a v i n g space s l o p e space apostrophe m apostrophe space a n d space p a s sin g space t h r o u g h space t h e
p o i n t space open parentheses x subscript 1 comma y subscript 1 close parentheses space i s space y minus y subscript 1 equals m open parentheses x minus x subscript 1 close parentheses
T h e r e f o r e comma space t h e space r e q u i r e d space e q u a t i o n space i s
y minus 0 equals tan 45 degree open parentheses x minus 2 close parentheses
rightwards double arrow y equals 1 cross times open parentheses x minus 2 close parentheses
rightwards double arrow y equals x minus 2
rightwards double arrow x minus y minus 2 equals 0

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13

Solution 13

Question 14

Solution 14

Question 15

Solution 15

Chapter 23 The Straight Lines Exercise Ex. 23.5

Question 1(i)

Solution 1(i)

Question 1(ii)

Solution 1(ii)

Question 1(iii)

Solution 1(iii)

Question 1(iv)

Solution 1(iv)

Question 1(v)

Solution 1(v)

Question 1(vi)

Solution 1(vi)

Question 2(i)

Solution 2(i)

Question 2(ii)

Solution 2(ii)

Question 3

Solution 3

Question 4

Solution 4

T h e space r e c tan g l e space A B C D space w i l l space h a v e space d i a g o n a l s space A C space a n d space B D
A C space p a s s e s space t h r o u g h space A open parentheses a comma b close parentheses space a n d space C open parentheses a apostrophe comma b apostrophe close parentheses. space
T h u s space e q u a t i o n space o f space A C space i s :
fraction numerator y minus y subscript 1 over denominator y subscript 2 minus y subscript 1 end fraction equals fraction numerator x minus x subscript 1 over denominator x subscript 2 minus x subscript 1 end fraction
rightwards double arrow fraction numerator y minus b over denominator b apostrophe minus b end fraction equals fraction numerator x minus a over denominator a apostrophe minus a end fraction
rightwards double arrow open parentheses y minus b close parentheses open parentheses a apostrophe minus a close parentheses equals open parentheses x minus a close parentheses open parentheses b apostrophe minus b close parentheses
rightwards double arrow y open parentheses a apostrophe minus a close parentheses minus a apostrophe b plus a b equals x open parentheses b apostrophe minus b close parentheses minus a b apostrophe plus a b
rightwards double arrow y open parentheses a apostrophe minus a close parentheses equals x open parentheses b apostrophe minus b close parentheses minus a b apostrophe plus a apostrophe b
rightwards double arrow y open parentheses a apostrophe minus a close parentheses minus x open parentheses b apostrophe minus b close parentheses equals a apostrophe b minus a b apostrophe

B D space p a s s e s space t h r o u g h space B open parentheses a apostrophe comma b close parentheses space a n d space D open parentheses a comma b apostrophe close parentheses. space
T h u s space e q u a t i o n space o f space B D space i s :
fraction numerator y minus y subscript 1 over denominator y subscript 2 minus y subscript 1 end fraction equals fraction numerator x minus x subscript 1 over denominator x subscript 2 minus x subscript 1 end fraction
rightwards double arrow fraction numerator y minus b over denominator b apostrophe minus b end fraction equals fraction numerator x minus a apostrophe over denominator a minus a apostrophe end fraction
rightwards double arrow open parentheses y minus b close parentheses open parentheses a minus a apostrophe close parentheses equals open parentheses x minus a apostrophe close parentheses open parentheses b apostrophe minus b close parentheses
rightwards double arrow minus y open parentheses a apostrophe minus a close parentheses minus a b plus a apostrophe b equals x open parentheses b apostrophe minus b close parentheses minus a apostrophe b apostrophe plus a apostrophe b
rightwards double arrow a apostrophe b apostrophe minus a b equals x open parentheses b apostrophe minus b close parentheses plus y open parentheses a apostrophe minus a close parentheses
rightwards double arrow x open parentheses b apostrophe minus b close parentheses plus y open parentheses a apostrophe minus a close parentheses equals a apostrophe b apostrophe minus a b

Question 5

Find the equation of the side BC of the triangle ABC whose vertices are A (-1, -2), B (0, 1) and (2, 0) respectively. Also, find the equation of the median through (-1, -2).Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11

Solution 11

L equals 4 over 1875 C plus 124.942 minus 4 cross times 20 over 1875
rightwards double arrow L equals 4 over 1875 C plus 124.899

Question 12

Solution 12

Question 13

Solution 13

rightwards double arrow y minus 3 equals 1 third open parentheses x minus 4 close parentheses
rightwards double arrow 3 open parentheses y minus 3 close parentheses equals x minus 4
rightwards double arrow x minus 3 y plus 9 minus 4 equals 0
rightwards double arrow x minus 3 y plus 5 equals 0

Question 14

Solution 14

Question 15

Find the equations of the diagonals of the square formed by the lines x = 0, y = 0, x = 1 and y = 1.Solution 15

Chapter 23 The Straight Lines Exercise Ex. 23.6

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

3Question 4

For what values of a and b the intercepts cut off on the coordinate axes by the line ax + by +8 = 0 are equal in length but opposite in signs to those cut off by the line 2x – 3y + 6 = 0 on the axes.Solution 4

Question 5

Solution 5

Question 6

Find the equation of the line which passing through the point (-4, 3) and the portion of the line intercepted  between the axes is divided internally in the ratio 5:3 by this pointSolution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

P o i n t space left parenthesis h comma k right parenthesis space d i v i d e s space t h e space l i n e space s e g m e n t space i n space t h e space r a t i o space 1 : 2
T h u s comma space u sin g space s e c t i o n space p o i n t space f o r m u l a comma space w e space h a v e
h equals fraction numerator 2 cross times a plus 1 cross times 0 over denominator 1 plus 2 end fraction
a n d
k equals fraction numerator 2 cross times 0 plus 1 cross times b over denominator 1 plus 2 end fraction
T h e r e f o r e comma space w e space h a v e comma
h equals fraction numerator 2 a over denominator 3 end fraction space a n d space k equals b over 3
rightwards double arrow a equals fraction numerator 3 h over denominator 2 end fraction a n d space b equals 3 k
T h u s comma space t h e space c o r r e s p o n d i n g space p o i n t s space o f space A space a n d space B space a r e space open parentheses fraction numerator 3 h over denominator 2 end fraction comma 0 close parentheses space a n d space open parentheses 0 comma 3 k close parentheses
T h u s comma space t h e space e q u a t i o n space o f space t h e space l i n e space j o i n i n g space t h e space p o i n t s space A space a n d space B space i s
fraction numerator y minus 3 k over denominator 3 k minus 0 end fraction equals fraction numerator x minus 0 over denominator 0 minus fraction numerator 3 h over denominator 2 end fraction end fraction
rightwards double arrow minus fraction numerator 3 h over denominator 2 end fraction open parentheses y minus 3 k close parentheses equals x cross times 3 k
rightwards double arrow minus 3 h y plus 9 h k equals 6 k x
rightwards double arrow 2 k x plus h y equals 3 k h

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13

Solution 13

Question 14

Solution 14

Question 15

Solution 15

Question 16

Solution 16

Question 17

Solution 17

Question 18

Solution 18

Question 19

Solution 19

Chapter 23 The Straight Lines Exercise Ex. 23.7

Question 1(i)

Solution 1(i)

Question 1(ii)

Solution 1(ii)

Question 1(iii)

Solution 1(iii)

Question 1(iv)

Solution 1(iv)

Question 2

Find the equation of the line on which the length of the perpendicular segment from the origin to the line is 4 and the inclination of the perpendicular segment with the positive direction of x-axis is 300.Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Chapter 23 The Straight Lines Exercise Ex. 23.8

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13

Solution 13

Chapter 23 The Straight Lines Exercise Ex. 23.9

Question 1

Solution 1

Question 2(i)

Solution 2(i)

Question 2(ii)

Solution 2(ii)

Question 2(iii)

Solution 2(iii)

Question 2(iv)

Solution 2(iv)

Question 2(v)

Solution 2(v)

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Chapter 23 The Straight Lines Exercise Ex. 23.10

Question 1(i)

Solution 1(i)

Question 1(ii)

Solution 1(ii)

Question 1(iii)

Solution 1(iii)

Question 2(i)

Solution 2(i)

Question 2(ii)

Solution 2(ii)

Question 3(i)

Solution 3(i)

Question 3(ii)

Solution 3(ii)

Question 3(iii)

Solution 3(iii)

Question 4

Solution 4

Question 5

Solution 5

Question 6(i)

Solution 6(i)

Question 6(ii)

Solution 6(ii)

Question 6(iii)

Solution 6(iii)

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

 Question 10

Solution 10

Question 11

Solution 11

 Question 12

Solution 12

Question 13

Solution 13

Question 14

Solution 14

 Question 15

Solution 15

Question 16

Find the equations of the line passing through the intersection of the lines 2x + y = 5 and x + 3y + 8 = 0 and parallel to the line 3x + 4y = 7.Solution 16

Question 17

Find the equation of the line passing through the point of intersection of the lines 5x – 6y – 1 = 0 and 3x + 2y + 5 = 0 and perpendicular to the line 3x – 5y + 11 = 0.Solution 17

Chapter 23 The Straight Lines Exercise Ex. 23.11

Question 1(i)

Solution 1(i)

Question 1(ii)

Solution 1(ii)

Question 1(iii)

Solution 1(iii)

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Chapter 23 The Straight Lines Exercise Ex. 23.12

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13

Solution 13

Question 14

Solution 14

Question 15

Solution 15

Question 16

Solution 16

Question 17

Solution 17

Question 18

Solution 18

Question 19

Solution 19

Question 20

Solution 20

Question 21

Solution 21

Question 22

Solution 22

Question 23

Solution 23

Question 24

Solution 24

Question 25

Solution 25

Question 26

Solution 26

Question 27

Find the equation of the straight line passing through the point of intersection of the lines 5x – 6y – 1 = 0 and 3x + 2y + 5 = 0 and perpendicular to the line 3x – 5y + 11 = 0.Solution 27

Chapter 23 The Straight Lines Exercise Ex. 23.13

Question 1(i)

Solution 1(i)

Question 1(ii)

Solution 1(ii)

Question 1(iii)

Solution 1(iii)

Question 1(iv)

Solution 1(iv)

Question 1(v)

Solution 1(v)

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Chapter 23 The Straight Lines Exercise Ex. 23.14

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Chapter 23 The Straight Lines Exercise Ex. 23.15

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13

Solution 13

Question 14

Solution 14

Question 15

Solution 15

Chapter 23 The Straight Lines Exercise Ex. 23.16

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Find the ratio in which the line 3x + 4y + 2 = 0 divides the distance between the lines 3x + 4y + 5 = 0 and 3x + 4y – 5 = 0.Solution 6

Chapter 23 The Straight Lines Exercise Ex. 23.17

Question 1

Deduce the condition for these lines to form a rhombus.Solution 1

Question 2

Solution 2

Question 3

Solution 3

Chapter 23 The Straight Lines Exercise Ex. 23.18

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13

Solution 13

Consider the following figure:

T h e space e q u a t i o n space o f space A B space i s
y minus 2 equals 1 fifth open parentheses x minus 1 close parentheses
rightwards double arrow 5 y minus 10 equals x minus 1
rightwards double arrow x minus 5 y plus 9 equals 0
A n d space t h e space e q u a t i o n space o f space B C space i s
y minus 8 equals minus 5 open parentheses x minus 5 close parentheses
rightwards double arrow y minus 8 equals minus 5 x plus 25
rightwards double arrow 5 x plus y minus 33 equals 0

Chapter 23 The Straight Lines Exercise Ex. 23.19

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

rightwards double arrow fraction numerator 6 x minus 21 y plus 33 plus 7 x plus 21 y minus 56 over denominator 3 end fraction equals 0
rightwards double arrow 6 x minus 21 y plus 33 plus 7 x plus 21 y minus 56 equals 0
rightwards double arrow 13 x minus 23 equals 0
rightwards double arrow 13 x equals 23

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11

Solution 11

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RD SHARMA SOLUTION CHAPTER- 22 Brief Review of Cartesian System of Rectangular Coordinates I CLASS 11TH MATHEMATICS-EDUGROWN

Chapter 22 Brief Review of Cartesian System of Rectangular Coordinates Exercise Ex. 22.1

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Chapter 22 Brief Review of Cartesian System of Rectangular Coordinates Exercise Ex. 22.2

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Chapter 22 Brief Review of Cartesian System of Rectangular Coordinates Exercise Ex. 22.3

Question 1

Solution 1


Question 2

Solution 2

Question 3(i)

Solution 3(i)

Question 3(ii)

Solution 3(ii)

Question 3(iii)

Solution 3(iii)

Question 3(iv)

Solution 3(iv)

Question 4

Solution 4

Question 5

Solution 5

Question 6(i)

Solution 6(i)

Question 6(ii)

Solution 6(ii)

Question 6(iii)

Solution 6(iii)

Question 6(iv)

Solution 6(iv)

Question 7(i)

Solution 7(i)

Question 7(ii)

Solution 7(ii)

Question 7(iii)

Solution 7(iii)

Question 8

Solution 8

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RD SHARMA SOLUTION CHAPTER- 21 Some Special Series I CLASS 11TH MATHEMATICS-EDUGROWN

Chapter 21 Some Special Series Exercise Ex. 21.1

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8(i)

Solution 8(i)

Question 8(ii)

Solution 8(ii)

Question 8(iii)

Solution 8(iii)

Question 8(iv)

Solution 8(iv)

Question 9

Solution 9

Chapter 21 Some Special Series Exercise Ex. 21.2

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

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RD SHARMA SOLUTION CHAPTER- 20 Geometric Progressions I CLASS 11TH MATHEMATICS-EDUGROWN

Chapter 20 Geometric Progressions Exercise Ex. 20.1

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6(i)

Solution 6(i)

Question 6(ii)

Solution 6(ii)

Question 6(iii)

Solution 6(iii)

Question 6(iv)

Solution 6(iv)

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13

Solution 13

Question 14

Solution 14

Question 15

Solution 15

Question 16

Solution 16

Question 17

Solution 17

Chapter 20 Geometric Progressions Exercise Ex. 20.2

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Chapter 20 Geometric Progressions Exercise Ex. 20.3

Question 1(i)

Solution 1(i)

Question 1(ii)

Solution 1(ii)

Question 1(iii)

Solution 1(iii)

Question 1(iv)

Solution 1(iv)

Question 1(v)

Solution 1(v)

Question 2(i)

Solution 2(i)

Question 2(ii)

Solution 2(ii)

Question 2(iii)

Solution 2(iii)

Question 2(iv)

Solution 2(iv)

Question 2(v)

Find the sum of the geom etric series:

begin mathsize 11px style 3 over 5 plus 4 over 5 squared plus 3 over 5 cubed plus 4 over 5 to the power of 4 plus.... space to space 2 straight n space terms semicolon end style

Solution 2(v)

Question 2(vi)

Solution 2(vi)

Question 2(vii)

1, -a, a2, – a3 , ….. to n terms (a ≠ 1)Solution 2(vii)

Question 2(viii)

Solution 2(viii)

Question 2(ix)

Solution 2(ix)

Question 3(i)

Solution 3(i)

Question 3(ii)

Solution 3(ii)

Question 3(iii)

Solution 3(iii)

Question 4(i)

Solution 4(i)

Question 4(ii)

Solution 4(ii)

Question 4(iii)

Solution 4(iii)

Question 4(iv)

Solution 4(iv)

Question 4(v)

Solution 4(v)

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13

Solution 13

Question 14

Solution 14

Question 15

Solution 15

Question 16

Solution 16

Question 17

Solution 17

Question 18

A person has 2 parents, 4 grandparents, 8 great grand parents,  and so on. Find the number his ancestors during the ten generations preceding his own.Solution 18

Question 19

(n – 1) Sn = 1n + 2n + 3n + ….+ nnSolution 19

Question 20

Solution 20

Question 21

Solution 21

Question 22

Solution 22

Chapter 20 Geometric Progressions Exercise Ex. 20.4

Question 1(i)

Solution 1(i)

Question 1(ii)

Solution 1(ii)

Question 1(iii)

Solution 1(iii)

Question 1(iv)

Solution 1(iv)

Question 1(v)

Solution 1(v)

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8(i)

Solution 8(i)

Question 8(ii)

Solution 8(ii)

Question 8(iii)

Solution 8(iii)

Question 8(iv)

Solution 8(iv)

Question 9

Solution 9

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13

Solution 13

Chapter 20 Geometric Progressions Exercise Ex. 20.5

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8(I)

Solution 8(I)

Question 8(ii)

Solution 8(ii)

Question 8(iii)

Solution 8(iii)

Question 8(iv)

Solution 8(iv)

Question 8(v)

Solution 8(v)

Question 9(i)

Solution 9(i)

Question 9(ii)

Solution 9(ii)

Question 9(iii)

Solution 9(iii)

Question 10(i)

Solution 10(i)

Question 10(ii)

Solution 10(ii)

Question 10(iii)

Solution 10(iii)

Question 11(i)

Solution 11(i)

Question 11(ii)

Solution 11(ii)

Question 11(iii)

Solution 11(iii)

Question 11(iv)

Solution 11(iv)

Question 12

Solution 12

Question 13

Solution 13

Question 14

If the 4th, 10th, and 16th terms of a G.P. are x, y, and z respectively. Prove that x, y, z are in G.P.Solution 14

Question 15

Solution 15

Question 16

Solution 16

Question 17

Solution 17

Question 18

Solution 18

Question 19

Solution 19

Question 20

Solution 20

Question 21

Solution 21

Question 22

Solution 22

Question 23

If pth, qth, and rth terms of an A.P. and G.P. are both a, b, and c respectively, show that ab-c bc-a ca-b = 1.Solution 23

Chapter 20 Geometric Progressions Exercise Ex. 20.6

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13

Solution 13

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RD SHARMA SOLUTION CHAPTER-19 Arithmetic Progressions I CLASS 11TH MATHEMATICS-EDUGROWN

Chapter 19 Arithmetic Progressions Exercise Ex. 19.1

Question 1

Solution 1

Question 2

Solution 2

Question 4

Solution 4

Question 5

Solution 5

Question 6(i)

Solution 6(i)

Question 6(ii)

Solution 6(ii)

Question 6(iii)

Solution 6(iii)

Question 6(iv)

Solution 6(iv)

Question 7

Solution 7

Question 8

Solution 8

Question 3

Find the first four terns of the sequence defined by a1 = 3 and, an = 3an– 1 + 2, for all n > 1Solution 3

Chapter 19 Arithmetic Progressions Exercise Ex. 19.2

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13

Solution 13

Question 14

Solution 14

Question 15

Solution 15

Question 16

Solution 16

Question 17

Solution 17

Question 18

Solution 18

Question 19

Solution 19

Question 20

Solution 20

Question 21

Solution 21

Question 22

Solution 22

Question 23

Solution 23

Chapter 19 Arithmetic Progressions Exercise Ex. 19.3

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Chapter 19 Arithmetic Progressions Exercise Ex. 19.4

Question 1

Solution 1

( vii ) 

            Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13

Solution 13

Question 14

Solution 14

Question 16

Solution 16

Question 17

Solution 17

Question 18

Solution 18

Question 19

Solution 19

Question 20

Solution 20

Question 21

Solution 21

Question 22

Solution 22

Question 23

Solution 23

Question 24

Solution 24

Question 25

Solution 25

Question 26

Solution 26

Question 27

Solution 27

Question 28

Solution 28

Question 29

Solution 29

Question 30

Solution 30

Question 31

Solution 31

Question 32

Solution 32

Question 33

Solution 33

Question 34

Solution 34

Question 15

Find the rth term of an A.P., the sum of whose first n terms is 3n2 + 2n.Solution 15

Chapter 19 Arithmetic Progressions Exercise Ex. 19.5

Question 1(i)

Solution 1(i)

Question 1(ii)

Solution 1(ii)

Question 2

Solution 2

Question 3(i)

Solution 3(i)

Question 3(ii)

Solution 3(ii)

Question 3(iii)

Solution 3(iii)

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Show that x2 + xy + y2, z2 + zx + x2 and y2 + yz + z2 are consecutive terms of an A.P., if x, y and z are in A.P.Solution 7

Chapter 19 Arithmetic Progressions Exercise Ex. 19.6

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Insert five numbers between 8 and 26 such that the resulting sequence is an A.P.Solution 9

Chapter 19 Arithmetic Progressions Exercise Ex. 19.7

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11

Solution 11

Question 12

A carpenter was hired to build 192 window frames. The first day he made five frames and each day thereafter he made two more frames than he made the day before. How many days did it take him to finish the job?Solution 12

Question 13

We know that the sum of the interior angles of a triangle is 180o. Show that the sums of the interior angles of polygons with 3, 4, 5, 6,…. sides form an arithmetic progression. Find the sum of the interior angles for a 21 sided polygon.Solution 13

Question 14

In a potato race 20 potatoes are placed in a line at intervals of 4 meters with the first potato 24 meters from the starting point. A contestant is required to bring the potatoes back to the starting place one at a time. How far would he run in bringing back all the potatoes?Solution 14

Question 15(i)

A man accepts a position with an initial salary of Rs. 5200 per month. It is understood that he will receive an automatic increase of Rs. 320 in the very next month and each month thereafter.

i. Find his salary for the tenth month.Solution 15(i)

Question 15(ii)

A man accepts a position with an initial salary of Rs. 5200 per month. It is understood that he will receive an automatic increase of Rs. 320 in the very next month and each month thereafter.

What is his total earnings during the first year?Solution 15(ii)

Question 16

A man saved Rs. 66000 in 20 years. In each succeeding year after the first year he saved Rs. 200 more then what he saved in the previous year. How much did he save in the first year?Solution 16

Question 17

In a cricket team tournament 16 teams participated. A sum of Rs. 8000 is to be awarded among themselves as prize money. If the last place team is awarded Rs. 275 in prize money and the award increases by the same amount for successive finishing places, how much amount will the first place team receive?Solution 17

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