Activity & Practical on Find Probability of each Outcome or a Die | Class 9th Mathematics-Edugrown

Objective
To find experimental probability of each outcome of a die when it is thrown a large number of times.

Materials Required

1. Notebook
2. A fair die
3. Pen

Prerequisite Knowledge
Basic knowledge of probability and a fair die.

Theory

1. For basic knowledge of probability refer to Activity 33.
2. A fair die is small cube having dots, 1 to 6 on its faces.
   

Procedure

1. Firstly, divide the whole class in ten groups, say G₁, G₂, G₃, …….., G₁₀ of a suitable size.
2. Allow all groups to throw a die 100 times and ask them to note down the observations, i.e. the number of times the outcomes 1, 2, 3, 4, 5 or 6 come up.
3. If 1 appears in all the groups a times. Similarly, count the number of times each of 2, 3, 4, 5 and 6 has appeared. Denote them by b, c, d, e and f, respectively.
4. Now, find the probability of each outcome (E) by using the formula,
   P(E) = 

Demonstration

1. There are 10 groups and all the groups throw a die 100 times. So, the total number of trials is 1000.
2. As, 1 has appeared a times.
   Hence, experimental probability of 1, P(1) = 
   similarly, experimental probability of 2, P(2) = 
   experimental probability of 3, P(3) = 
   experimental probability of 4, P(4) = 
   experimental probability of 5, P(5) = 
   and  experimental probability of 6, P(6) = 

Observations
Fill the results of your experiment in the table given below.

Outcome/Group	Number of times a number comes up on a die	Total
1	2	3	4	5	6
G1	……	……	……	……	……	……	100
G2	……	……	……	……	……	……	100
G3	……	……	……	……	……	……	100
G4	……	……	……	……	……	……	100
G5	……	……	……	……	……	……	100
G6	……	……	……	……	……	……	100
G7	……	……	……	……	……	……	100
G8	……	……	……	……	……	……	100
G9	……	……	……	……	……	……	100
G10	……	……	……	……	……*,	……	100
Total	a = …….	b = ……..	c = …….	d = ……..	e = …..	f =…….	1000

Hence,
P(1) = 
P(2) = 
P(3) = 
P(4) = 
P(5) = 
P(6) = 

Result
We have got the experimental probability of each outcome of a die, when it is thrown a large number of times.