CHAPTER -9 Rational Numbers | CLASS 7TH |NCERT MATHS IMPORTANT QUESTIONS & MCQS | EDUGROWN
MATHS IMPORTANT QUESTIONS & MCQS FOR CLASS 7th
Get Chapter Wise MCQ Questions for Class 7 Maths with Answers prepared here according to the latest CBSE syllabus and NCERT curriculum. Students can practice CBSE Class 7 Maths MCQs Multiple Choice Questions with Answers to score good marks in the examination. Students can also visit the most accurate and elaborate NCERT Solutions for Class 7 Maths. Every question of the textbook has been answered here.
Chapter - 9 Rational Numbers
MCQs
Question 1.
The numerator of the rational number 35 is
(a) 3
(b) 5
(c) 2
(d) 8
Answer
Answer: (a) 3
Question 2.
The numerator of the rational number 1100 is
(a) 100
(b) 1
(c) 10
(d) 99
Answer
Answer: (b) 1
Question 3.
The denominator of the rational number 47 is
(a) 7
(b) 4
(c) 3
(d) 11
Answer
Answer: (a) 7
Question 4.
The denominator of the rational number 713 is
(a) 13
(b) 7
(c) 6
(d) 91
Answer
Answer: (a) 13
Question 5.
The numerator of the rational number −34 is
(a) -3
(b) 3
(c) 4
(d) -4
Answer
Answer: (a) -3
Question 6.
The numerator of the rational number −29 is
(a) -2
(b) 2
(c) -9
(d) 9
Answer
Answer: (a) -2
Question 7.
The denominator of the rational number 5−3 is
(a) 5
(b) -3
(c) 3
(d) 8
Answer
Answer: (b) -3
Question 8.
The denominator of the rational number 3−7 is
(a) 7
(b) -7
(c) 3
(d) -3
Answer
Answer: (b) -7
Question 9.
The numerator of the rational number −2−5 is
(a) 2
(b) -2
(c) 5
(d) -5
Answer
Answer: (b) -2
Question 10.
the numerator of the rational number −5−3 is
(a) -5
(b) 5
(c) -3
(d) 3
Answer
Answer: (a) -5
Question 11.
The denominator of the rational number −2−9 is
(a) -2
(b) 2
(c) 9
(d) -9
Answer
Answer: (d) -9
Question 12.
The denominator of the rational number −6−5 is
(a) 6
(b) -6
(c) 5
(d) -5
Answer
Answer: (d) -5
Question 13.
The denominator of the rational number −13−11 is
(a) -13
(b) 13
(c) 11
(d) -11
Answer
Answer: (d) -11
Question 14.
The numerator of the rational number 0 is
(a) 0
(b) 1
(c) 2
(d) 3
Answer
Answer: (a) 0
Question 15.
The denominator of the rational number 0 is
(a) 0
(b) 1
(c) -1
(d) any non-zero integer
Answer
Answer: (d) -1
Question 16.
The numerator of a rational number 8 is
(a) 2
(b) 4
(c) 6
(d) 8
Answer
Answer: (d) 8
Question 17.
The denominator of the rational number 8 is
(a) 8
(b) 2
(c) 4
(d) 1
Answer
Answer: (d) 1
Question 1.
Find three rational numbers equivalent to each of the following rational numbers.
(i) −25
(ii) 37
Solution:
Question 2.
Reduce the following rational numbers in standard form.
(i) 35−15
(ii) −36−216
Solution:
Question 3.
Represent 32 and −34 on number lines.
Solution:
Question 4.
Which of the following rational numbers is greater?
(i) 34, 12
(ii) −32, −34
Solution:
Question 5.
Find the sum of
Solution:
Question 6.
Subtract:
Solution:
Question 7.
Find the product:
Solution:
Rational Numbers Class 7 Extra Questions Short Answer Type
Question 8.
If the product of two rational numbers is −916 and one of them is −415, find the other number.
Solution:
Let the required rational number be x.
Question 9.
Arrange the following rational numbers in ascending order.
Solution:
Question 10.
Insert five rational numbers between:
Solution:
Rational Numbers Class 7 Extra Questions Long Answer Type
Question 11.
Evaluate the following:
Solution:
Question 12.
Subtract the sum of −56 and -135 from the sum 223 and -625.
Solution:
Question 13.
Solution:
We have
Question 14.
Divide the sum of -21517 and 3534 by their difference.
Solution:
Question 15.
During a festival sale, the cost of an object is ₹ 870 on which 20% is off. The same object is available at other shops for ₹ 975 with a discount of 623 %. Which is a better deal and by how much?
Solution:
The cost of the object = ₹ 870
Discount = 20% of ₹ 870 = 20100 × 870 = ₹ 174
Selling price = ₹ 870 – ₹ 174 = ₹ 696
The same object is available at other shop = ₹ 975
Selling price = ₹ 975 – ₹ 65 = ₹ 910
Since ₹ 910 > ₹ 696
Hence, deal at first shop is better and by ₹ 910 – ₹ 696 = ₹ 214
Rational Numbers Class 7 Extra Questions Higher Order Thinking Skills (HOTS) Type
Question 16.
Simplify:
21.5 ÷ 5 – 15 of (20.5 – 5.5) + 0.5 × 8.5
Solution:
Using BODMAS rule, we have
21.5 ÷ 5 – 15 of (20.5 – 5.5) + 0.5 × 8.5
= 21.5 ÷ 5 – 15 of 15 + 0.5 × 8.5
= 21.5 × 15 – 15 × 15 + 0.5 × 8.5
= 4.3 – 3 + 4.25
= 4.3 + 4.25 – 3
= 8.55 – 3
= 5.55
Question 17.
Simplify:
Solution:
Using BODMAS rule, we have
2.3 – [1.89 – {3.6 – (2.7 – 0.77)}]
= 2.3 – [1.89 – {3.6 – 1.93}]
= 2.3 – [1.89 – 1.67]
= 2.3 – 0.22
= 2.08
Question 18.
Solution:
Using BODMAS rule, we have
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