NCERT MCQ Questions for Class 6 Maths Chapter 10 Mensuration with Answers. MCQ Questions for Class 6 Maths with Answers were prepared based on the latest exam pattern. We have provided Knowing Our Numbers Class 6 Maths MCQs Questions with Answers to help students understand the concept very well
Table of Contents
Chapter-10 Mensuration Class 6th Maths Important Questions & MCQS
MCQ
Question 1.
Perimeter of a rectangle =
(a) Length × Breadth
(b) Length + Breadth
(c) 2 × (Length + Breadth)
(d) 2 × (Length × Breadth).
Answer
Answer: (c)
Question 2.
Perimeter of a square =
(a) 4 × Length of a side
(b) 2 × Length of a side
(c) 3 × Length of a side
(d) 6 × Length of a side.
Answer
Answer: (a)
Question 3.
Perimeter of an equilateral triangle
(a) 2 × Length of a side
(b) 3 × Length of a side
(c) 4 × Length of a side
(d) 6 x Length of a side.
Answer
Answer: (b)
Question 4.
Area of a rectangle =
(a) Length × Breadth
(b) Length + Breadth
(c) 2 × (Length + Breadth)
(d) 2 × (Length × Breadth).
Answer
Answer: (a)
Question 5.
Area of a square =
(a) side × side
(b) 4 × Length of a side
(c) 2 × Length of a side
(d) 6 × Length of a side.
Answer
Answer: (a)
Question 6.
Perimeter of a regular pentagon =
(a) 4 × Length of a side
(b) 3 × Length of a side
(c) 6 × Length of a side
(d) 5 × Length of a side.
Answer
Answer: (d)
Question 7.
Perimeter of a regular hexagon =
(a) 3 × Length of a side
(b) 4 × Length of a side
(c) 5 × Length of a side
(d) 6 × Length of a side.
Answer
Answer: (d)
Question 8.
Apala went to a park 20 m long and 10 m wide. She took one complete round of it. The distance covered by her is
(a) 30 m
(b) 60 m
(c) 20 m
(d) 10 m.
Answer
Answer: (b)
Hint:
Distance covered = 2(20 + 10) = 60 m
Question 9.
The perimeter of the figure is
(a) 12m
(b) 14m
(c) 24 m
(d) 7 m.
Answer
Answer: (b)
Hint:
Perimeter = 2(4 + 3) = 14m
Question 10.
The perimeter of the figure is
(a) 8m
(b) 16m
(c) 4m
(d) none of these.
Answer
Answer: (a)
Hint:
Perimeter = 4 × 2 = 8m
Question 11.
A page is 25 cm long and 20 cm wide. Find the perimeter of this page.
(a) 90 cm
(b) 45 cm
(c) 500 cm
(d) 5 cm.
Answer
Answer: (a)
Hint:
Perimeter = 2(25 + 20) = 90 cm
Question 12.
The perimeter of the figure is
(a) 5 cm
(b) 10 cm
(c) 15 cm
(d) 20 cm.
Answer
Answer: (d)
Hint:
Perimeter = 4(1 + 2 + 2) = 20cm
Question 13.
The perimeterof the figure is
(a) 20 cm
(b) 10 cm
(c) 24 cm
(d) 15 cm.
Answer
Answer: (a)
Hint:
Perimeter = 4 + 3 + 2 + 2 + 3 + 6 = 20 cm
Question 14.
Meenu wants to put a lace border all around a rectangle table cover 2 m long and 1 m wide. Find the length of the lace required by Meenu.
(a) 3 m
(b) 4 m
(c) 5 m
(d) 6m.
Answer
Answer: (d)
Hint:
Length of the lace = 2(2 + 1) = 6 m
Question 15.
Find the perimeter of a rectangle whose length and breadth are 9 cm and 1 cm respectively,
(a) 10 cm
(b) 20 cm
(c) 30 cm
(d) 40 cm.
Answer
Answer: (b)
Hint:
Perimeter = 2(9 + 1) = 20 cm
Question 16.
An athlete takes 10 rounds of a rectangular park, 40 m long and 30 m wide. Find the total distance covered by him.
(a) 1400 m
(b) 700 m
(c) 70 m
(d) 2800 m.
Answer
Answer: (a)
Hint:
Total distance covered = 10 × 2 × (40 + 30) = 1400 m
Question 17.
Find the cost of fencing a rectangular park of length 10 m and breadth 5 m at the rate of? 10 per metre.
(a) ₹ 300
(b) ₹ 600
(c) ₹ 150
(d) ₹ 1200.
Answer
Answer: (a)
Hint:
Cost= 10 × 2 × (10 + 5) = ₹ 300
Important Questions
Question 1.
The perimeter of a square is 64 cm. Find the length of each side.
Solution:
Perimeter of the square = 64 cm
Question 2.
Length and breadth of a rectangular table-top are 36 cm and 24 cm respectively. Find its perimeter.
Solution:
Length of the rectangular table-top = 36 cm
and its breadth = 24 cm.
∴ Perimeter of the table-top = 2 [length + breadth]
= 2 [36 cm + 24 cm]
= 2 x 60 cm = 120 cm.
Question 3.
Which of the following figure has greater perimeter?
Solution:
Fig. (i) Perimeter of the square = 4 x side
= 4 x 4 cm = 16 cm
Fig. (ii) Perimeter of the rectangle
= 2 [length + breadth]
= 2[8 cm + 3 cm]
= 2 x 11 cm = 22 cm
Since 22 cm > 16 cm
∴ Rectangle has greater perimeter than the square.
Question 4.
How much distance will you have to travel in going around each of the following figures?
Solution:
Distance travelled in going around Fig. (i)
= 12 cm + 3 cm + 12 cm + 3 cm = 30 cm
Distance travelled in going around Fig. (ii)
= 6 cm + 4 cm + 4 cm + 4 cm = 18 cm
Question 5.
Find the perimeter of a square whose side is 15 cm.
Solution:
Side of the square = 15 cm
∴ Perimeter of the square = 15 cm x 4 = 60 cm
Question 6.
Find the cost of fencing a rectangular park 300 m long and 200 m wide at the rate of ₹4 per metre.
Solution:
Length of the park = 300 m
Breadth = 200 m
∴ Perimeter of the park = 2 [length + breadth]
= 2 [300 m + 200 m]
= 2 x 500 m = 1000 m.
Cost of fencing the rectangular park = 1000 x 4 = ₹4000
Question 7.
Find the area of a square field whose each side is 150 m.
Solution:
Side of the square field = 150 m
∴ Area of the square field = Side x Side
= 150 m x 150 m
= 22500 sq m.
Question 8.
Length and breadth of a rectangular paper are 22 cm and 10 cm respectively. Find the area of the paper.
Solution:
Length of the rectangular paper = 22 cm
Breadth = 10 cm
∴ Area of the rectangular paper = length x breadth
= 22 cm x 10 cm
= 220 sq cm.
Mensuration Class 6 Extra Questions Short Answer Type
Question 9.
Find the length of a rectangle given that its perimeter is 880 m and breadth is 88 m.
Solution:
Perimeter of the rectangle = 2 [length + breadth]
∴ 2 [length + breadth] = 880
length + breadth = 880 ÷ 2 = 440
∵ Breadth = 88 m
∴ Length = 440 m – 88 m = 352 m
Hence, the required length = 352 m.
Question 10.
How many trees can be planted at a distance of 6 metres each around a rectangular plot whose length is 120 m and breadth is 90 m?
Solution:
Length of the rectangular plot = 120 m
Breadth = 90 m
∴ Perimeter of the rectangular plot
= 2 [length + breadth]
= 2 [120 m + 90 m]
= 2 x 210 m = 420 m
Now distance between two trees = 6 m
∴ Number of trees around the rectangular plot = 420 m ÷ 6 m = 70
Question 11.
A rectangular park is 30 metres long and 20 metres broad. A steel wire fence is put up all around it. Find the cost of putting the fence at the rate of ₹15 per metre.
Solution:
Length of the rectangular park = 30 m
Breadth = 20 m
∴ Perimeter of the rectangular park = 2(length + breadth)
= 2 [30 + 20] = 2 x 50 m = 100 m
∴ Cost of fencing all around the park = ₹15 x 100 = ₹1500
Question 12.
Find the area of the figures A, B, C and D drawn on a squared paper in the following figure by counting squares.
Solution:
(A) Counting the squares, we have 8 squares
∴ Area = 8 sq units
(B) Counting the squares, we have 4 squares
∴ Area = 4 sq units
(C) Counting the squares, we have 5 squares
∴ Area = 5 sq units
(D) Counting the squares, we have 7 squares
∴ Area = 7 sq units
Mensuration Class 6 Extra Questions Higher Order Thinking Skills (HOTS)
Question 13.
A rectangle and a square have the same perimeter 100 cm. Find the side of the square. If the rectangle has a breadth 2 cm less than that of the square. Find the breadth, length and area of the rectangle.
Solution:
Perimeter of the square = 100 cm
Perimeter 100
= 25 cm.
∴ Breadth of the rectangle = 25 cm – 2 cm = 23 cm
Now perimeter of the rectangle = 100 cm
∴ 2 [length + breadth] = 100
length + breadth = 100 ÷ 2 = 50 cm
But breadth = 23 cm
∴ Length = 50 cm – 23 cm = 27 cm
Now, Area of the rectangle
= length x breadth = 27 cm x 23 cm
= 621 sq cm.
Question 14.
Fencing the compound of a house costs ₹5452. If the rate is ₹94 per metre, find the perimeter of the compound. If the breadth is 10 m, find its length.
Solution:
Cost of fencing the compound = ₹5452
and the rate of fencing = ₹94 per metre
∴ Perimeter of the compound = 5452 ÷ 94 = 58 metres
Now breadth of the compound = 10 m.
2 [length + breadth] = 58 m
∴ length + breadth = 58 + 2 m = 29 m
∴ Length of the compound = 29 m – 10 m = 19 m.
Discover more from EduGrown School
Subscribe to get the latest posts sent to your email.