Chapter -1 Food: Where Does It Come From? | Class 6TH | NCERT Science Solutions | EDUGROWN

Here students can get info about NCERT Solutions for Class 6 Science so that they can get to know the answers to the questions in case they are not able to find it. You can find the best Class 6th Science NCERT Solutions explained in conformance with the CBSE curriculum for Class 6.

NCERT Solutions for Class 6 Science Chapter 1 Food Where Does It Come From

Class 6 Science Chapter 1 Textbook Questions Solved

Q. 1. Do you find that all living beings need the same kind of food?
Ans. No, all living beings do not need same kind of food.

Q.2. Name five plants and their parts that we eat.
Ans. The names of five plants and their parts that we eat are:
(i) Paddy: seeds
(ii) Wheat: seeds
(iii) Mustard plant: seeds and leaves
(iv) Brinjal plant: fruits
(v) Potato plant: stems

Q. 3. Match the items given in column A with those in column B.
NCERT Solutions for Class 6 Science Chapter 1 Food Where Does It Come From Q3
Q. 4. Fill up the blanks with the words given:
herbivore, plant, milk, sugarcane, carnivore.
(a) Tiger is a__________ because it eats only meat.
(b) Deer eats only plant products and so is called______________ .
(c) Parrot eats only__________
(d) The_________ that we drink, which comes from cows, buffaloes and goats is
an animal product.
(e) We get sugar from___________ .
Ans. (a) carnivore                                   (b) herbivore                 (c) plant
(d) milk                                     (e) sugarcane

Extra Questions for Class 6 Science Chapter 1

Class 6 Science Chapter 1 VERY SHORT ANSWER TYPE QUESTIONS

Q. 1. Give two examples where two or more parts of a single plant are used as food.
Ans. Mustard — seeds and leaves,
Pumpkin — fruit and flowers.

Q.2. Name any one plant that grows in water and is eaten as food.
Ans. Lotus — Stem of lotus is eaten as food.

Q.3. Suggest any three ways you can think of to avoid wastage of food.
Ans. (i) Avoid leaving food uneaten in meals.
(ii) “Eat to live” and not “live to eat” — excess eating should be avoided.
(iii) Raw food like pulses, grains should be stored properly.

Q.4. Name two sugar producing plants.
Ans. (a) Sugarcane                                           (b) Sugarbeet.

Q.5. Name a non-green plant that we eat.
Ans. Mushroom.

Q.6. What do you call the habit of an individual to eat a particular type of food items commonly?
Ans. Food habit.

Q.7. Compare your food habits with food habits of your friend who lives in Tamil Nadu.
Ans. My food habit: Chapatti, pulses, lassi, rice, vegetables, mustard oil.
Food habit of my friend: Idli, dosa, sambhar, bara, rasam, upma and coconut oil, etc.

Q.8. What items are used to prepare cooked rice?
Ans. Raw rice and water.

Q.9. Study the ingredients of various food items. Do they have some common food ingredients?
Ans. Yes, they have some common ingredients like: water, salt and oil or ghee.

Q.10. What are the two common sources of most of the ingredients of food items?
Ans. (i) Plants                                                  (ii) Animals

Q.11. Name the three products each provided by plants and animals.
Ans. Plant products: Grains, cereals and vegetables.
Animal products: Milk, egg and meat.

Q.12. Name three edible (eatable) parts of plants.
Ans. (i) Roots                                        (ii) Fmits                                (iii) Leaves

Q.13. Which part of the plants do we eat generally?
Ans. We generally eat fruits of many plants.

Q. 14. Which type of seeds give more energy, sprouted seeds or normal seeds?
Ans. Sprouted seeds give more energy than normal seeds.

Q.15. What is honey? 
Ans. A sweet substance (liquid) prepared by bees from the riectar, i.e., sweet juice collected from flowers is called honey.

Q.16. Where would you place human beings on the basis of food that they eat?
Ans. Omnivores.

Class 6 Science Chapter 1 SHORT ANSWER TYPE QUESTIONS

Q.l. What is food?
Ans. The eatable substances eaten by humans and other animals to get energy for various activities for growth and development is called food.

Q.2. Why should we eat cooked food?
Ans. We should eat cooked food because by cooking we can kill harmful germs and make it germless. Cooked food can be easily digested and absorbed by our body. Cooking also improves the taste of food.

Q.3. Explain the importance of food for living organisms.
Ans. Importance of food is:
(i)  It provides energy to do various activities.
(ii) It helps in growth.
(iii) It helps to repair and replace damaged parts of the body.
(iv) It protects us from infections and diseases.

Q.4.  Explain the various sources of food items and ingredients with the help of examples.
Ans.  There are mainly two sources of ingredients of various food items:
(i) Plants: Plants provide us fruits, vegetables, pulses, grains, cereals, etc.
(ii) Animals: Animals provide us milk, eggs, meat etc.

Q.5. Define the term herbivores.
Ans. The animals which eat only plants or plant products are called herbivores. For example, cow, goat and buffalo.

Q.6. What are carnivores? Explain with examples.
Ans. The-animals which eat other animals are called carnivores. For example, lion and tiger. Carnivores generally eat herbivores and other carnivores.

Q.7. Define the term omnivores.
Ans. The animals which eat both the plants and animals are called omnivores. For example, cat, dog and human beings.

Class 6 Science Chapter 1 LONG ANSWER TYPE QUESTIONS

Q. 1. With the help of a flow chart show various contributors involved when we eat a chapatti.
NCERT Solutions for Class 6 Science Chapter 1 Food Where Does It Come From LAQ Q1

Q.2. Make flow charts for the preparation of honey and ghee.
Ans. Preparation of honey:
NCERT Solutions for Class 6 Science Chapter 1 Food Where Does It Come From LAQ Q2
Q. 3. Differentiate between herbivorescarnivores and omnivores. Give two examples of each
NCERT Solutions for Class 6 Science Chapter 1 Food Where Does It Come From LAQ Q3
Q. 4. (i) Name the different parts of a banana plant that are used as food.
(ii)  Animal food we get from water resources.
(iii) Four fruits which we eat as vegetables.
Ans. (i) Flower, fruit and stem of banana.
(ii) Fish, prawn, lobustar and crabes.
(iii) Fruits of tomato, brinjal, Ladyfinger (bhindi), cucumber (Loki).

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Chapter-14 Practical Geometry | Class 6th | NCERT Maths Solutions | Edugrown

NCERT Solutions for Class 6 Maths: One of the most important and interesting things to keep in mind is that these solutions available are totally free of cost. This also includes all the solutions to the exercises that are given in the textbook. NCERT solutions for class 6 maths gives you chapter-wise solutions to each and every question. This can help you solve even the tougher with ease.

It is always good to have a strong foundation in order to build a good building. This also is true in class when you are still learning the basics of maths. NCERT solutions for class 6 maths provides you the exact opportunity to build a strong foundation in this subject. Below is an overview of each and every chapter covered in the NCERT textbook.

NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry

Ex 14.1 Class 6 Maths Question 1.
Draw a circle of radius 3.2 cm.
Solution:
Steps of Construction:

    1. Mark a point 0 on the paper.
    2. Open the compasses for the required radius 3.2 cm.
      NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 1
  1. Keep the steel end of the compasses fixed at the point O and rotate the pencil end at 3.2 cm distance from O till it returns to the starting point P.
    Then, the figure so obtained is the required circle.

Ex 14.1 Class 6 Maths Question 2.
With the same centre O, draw two circles of radii 4 cm and 2.5 cm.
Solution:
Steps of Construction:

  1. Mark a point 0 on the paper.
  2. Open the compasses for the radii 4 cm/2.5 cm (tumwise).
    NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 2
  3. Keep the steel end of the compasses fixed at the point 0 and rotate the pencil end at 4 cm/2.5 cm (turnwise)distance from O till it returns to their starting points respectively.
    The circles obtained are the required circles.
    Note: Circles with the same centre are called concentric circles.

Ex 14.1 Class 6 Maths Question 3.
Draw a circle and any two ofits diameters. If you join the ends of these diameters, what is the figure obtained? What figure is obtained if the diameters are perpendicular to each other? How do you check your answer?
Solution:
Steps of Construction:

  1. Draw a circle with O as centre of any radius.
  2. Draw any two diameters AOB and COD.
    NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 3
  3.  Join AC, CB, BD and DA.
    Clearly, the figure ACBD is a rectangle.
    When the diameter AOB and COD are perpendicular to each other:
    NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 4
    Then, figure obtained on joining AC, CB, BD and DA is a square ACBD.

Ex 14.1 Class 6 Maths Question 4.
Draw any circle and mark points A, B and C such that:
(a) A is on the circle.
(b) B is in the interior of the circle.
(c) C is in the exterior of the circle.
Solution:
Steps of Construction:
NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 5

1. Draw a circle with O as centre of any radius.
2. Mark point
(a) A on the circle,
(b) B in the interior of the circle, and
(c) C in the exterior of the circle.

Ex 14.1 Class 6 Maths Question 5.
Let A, B be the centres of two circles of equal radii; draw them so that each one of them passes through the centre of the other. Let them intersect at C and D.
Examine whether AB and CD are at right angles.
Solution:
Steps of Construction:

  1. Mark points A and Bona paper such that AB = radii (i.e., 3 cm, say).
    NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 6
  2. With A as centre draw a circle of any radius (say, 3 cm).
  3. With B as centre draw a circle of radius 3 cm as shown.
  4. Let these circles intersect at C and D.
    Clearly, on measuring we find ∠AMC = 90°, so AB ⊥ CD.

Ex 14.2 Class 6 Maths Question 1.
Draw a line segment of length 7.3 cm, using a ruler.
Solution:
Steps of Construction:

    1. Mark a point A on the plane of the paper and place the ruler so that zero mark of the ruler is at A.
      NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 7
  1. Mark with pencil a point B against the mark on the ruler which indicates 7.3 cm.
  2. Join points A and B by moving the tip of the pencil against the straight edge of the ruler.
    The line segment AB so obtained is the required line segment.

Ex 14.2 Class 6 Maths Question 2.
Construct a line segment of length 5.6 cm using ruler and compasses.
Solution:
Steps of Construction:

  1. Mark a point A on the plane of the paper and draw a line, say l, passing through it.
    NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 8
  2. Place the steel end of the compasses at zero mark on the ruler and open out it such that the pencil end on the mark indicates 5.6 cm.
  3. Transfer the compasses as it is to the line l so that the steel end is on A.
  4. With the pencil end make a small stroke on l so as to cut it at B.
  5. The segment AB so obtained is the required line segment.

Ex 14.2 Class 6 Maths Question 3.
Construct AB¯¯¯¯¯¯¯¯ of length 7.8 cm. From this, cut off AC¯¯¯¯¯¯¯¯ of length 4.7 cm. Measure BC¯¯¯¯¯¯¯¯.
Solution:
Steps of Construction:

  1. Draw a line segment AB of length 7.8 cm.
    NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 9
  2. Using compasses find a point C on the line segment AB so that segment AC = 4.7 cm.
  3. On measuring BC, we find that BC = 3.1 cm.

Ex 14.2 Class 6 Maths Question 4.
Given AB¯¯¯¯¯¯¯¯ of length 3.9 cm, construct PQ¯¯¯¯¯¯¯¯ such that the length of PQ¯¯¯¯¯¯¯¯ is twice that of AB¯¯¯¯¯¯¯¯. Verify by measurement.
NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 10
Solution:
Steps of Construction:

  1. Draw a line l and mark a point P on it.
    NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 11
  2. Using compasses find a point X so that PX(= AB) = 3.9 cm on the line l.
  3. Using compasses find a point Q so that XQ = 3.9 cm on the line l.
    Thus, PQ = PX + XQ = 3.9 cm + 3.9 cm
    = 2(3.9 cm) = 2AB.

Ex 14.2 Class 6 Maths Question 5.
Given AB¯¯¯¯¯¯¯¯ of length 7.3 cm and CD¯¯¯¯¯¯¯¯ of length 3.4 cm, construct a line segment XY¯¯¯¯¯¯¯¯ such that the length of XY¯¯¯¯¯¯¯¯ is equal to the difference between the lengths of AB¯¯¯¯¯¯¯¯ and CD¯¯¯¯¯¯¯¯. Verify by measurement
Solution:
Steps of Construction:
NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 12

  1. Draw line segments AB = 7.3 cm and CD = 3.4 cm.
  2. Draw a line l and mark a point X on it.
  3. Using compasses find a point P on the line l so that segment XP = segment AB (i.e., 7.3 cm).
  4. Using compasses find a point Y so that the segment PY = segment CD (i.e., 3.4 cm). The segment XY so obtained is the required segment, because XY = OP -PY – AB -CD.

Ex 14.3 Class 6 Maths Question 1.
Draw any line segment PQ¯¯¯¯¯¯¯¯. Without measuring PQ¯¯¯¯¯¯¯¯, construct a copy of PQ¯¯¯¯¯¯¯¯.
Solution:
Steps of Construction:
Let PQ be the given line segment and l be a given line.
NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 13

  1. Mark a point 0 on the line l.
  2. Open out the compasses and adjust so that the steel end is on A and the pencil end is A on B.
  3. Transfer the compasses to the line l without disturbing their opening so that the steel end is on 0.
  4. With the pencil end make a small stroke on the line l to cut it at the point P.
    Then, the fine segment OP so obtained = the given line segment AB.

Ex 14.3 Class 6 Maths Question 2.
Given some line segment AB¯¯¯¯¯¯¯¯, whose length you do not know, construct PQ¯¯¯¯¯¯¯¯ such that the length of PQ¯¯¯¯¯¯¯¯ is twice that of AB¯¯¯¯¯¯¯¯.
Solution:
Steps of Construction:
Let AB be the given line segment.

  1. Draw any line l and make a point 0 on it.
  2. Open out the compasses in such way that the steel end is on A and the pencil end is on B.
  3. Transfer the compasses without disturbing their opening to the line l so that the steel end is on O.
  4. With the pencil end make a small stroke on -the line l to cut it at the point P.
  5. Repeat the steps 3 and 4 with same opening having P as the initial point and Q as the terminal point.
    Then, the segment OQ = OP + PQ = AB + AB= 2 AB.

Ex 14.4 Class 6 Maths Question 1.
Draw any line segment AB¯¯¯¯¯¯¯¯,. Mark any point M on it. Through M, draw a perpendicular to AB¯¯¯¯¯¯¯¯,. (use ruler and compasses)
Solution:
Steps of Construction:
NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 14

Draw a line segment AB, and mark any point M on it.
With centre M and any radius, cut off MX and MY of equal lengths on both sides of M.
With centre X and any radius > MX, draw an arc.
With centre Y and the same radius draw another arc, cutting the previously drawn arc at P
Join MP
Then, the segment PM so obtained is the required perpendicular.
Ex 14.4 Class 6 Maths Question 2.
Draw any line segment PQ¯¯¯¯¯¯¯¯,. Take any point R not on it. Through R, draw a perpendicular to PQ¯¯¯¯¯¯¯¯,. (use ruler and set-square)
Solution:
Steps of Construction:

Let PQ be the line and R is any point not lying on PQ.
Place the set-square so that the base AB of the set-square lies exactly on the line PQ.
Hold the set-square fixed and place a ruler so that its edge position lies along the side AC of the set-square.
Holding the ruler fixed, slide the set-square along the ruler till the point R coincides with the point B of the set-square.
Keeping the set-square fixed in this position, draw a line RT along the edge BC of the set-square through R.
NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 15
Thus, RT is the required perpendicular line to the line PQ passing through R.
Ex 14.4 Class 6 Maths Question 3.
Draw a line l and a point X on it. Through X, draw a line segment XY¯¯¯¯¯¯¯¯ perpendicular to l. Now draw a perpendicular to XY at Y. (use ruler and compasses)
Solution:
Steps of Construction:
NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 16

Draw a line l and mark any point X on it. ,
With centre X and any radius, cut off XA = XB on both sides of X.
With centre A and any radius > XA, draw an arc.
With centre B and the same radius draw another arc, cutting the previously drawn arc at Y.
Join XY. Then XY is perpendicular to line 1.
By proceeding as above draw a perpendicular YZ to XY.

Ex 14.5 Class 6 Maths Question 1.
Draw AB¯¯¯¯¯¯¯¯ of length 7.3 cm and find its axis of symmetry.
Solution:
Steps of Construction:

  1. Draw a line segment AB = 7.3 cm.
  2. With centre A and radius > 12 AB, draw arcs one on each side of AB.
  3. With centre B and the same radius as before, draw arcs cutting the previously drawn arcs at C and D respectively.
  4. Join CD intersecting AB at M. Then M bisects the line segment AB as shown.
    NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 17
    The line segment so obtained is the required axis of symmetry.

Ex 14.5 Class 6 Maths Question 2.
Draw a line segment of length 9.5 cm and construct its perpendicular bisector.
Solution:
Steps of Construction:
NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 18

  1. Draw a line segment AB = 9.5 cm.
  2. With centre A and radius > 12 AB, draw arcs one on each side of AB. . A
  3. With centre B and the same radius as before, draw arcs cutting the previously drawn arcs at C and D respectively.
  4. Join CD. Then the line segment CD is the required perpendicular bisector of AB.

Ex 14.5 Class 6 Maths Question 3.
Draw the perpendicular bisector of XY¯¯¯¯¯¯¯¯ whose length is 10.3 cm.
(a) Take any point P on the bisector drawn. Examine whether PX = PY.
(b) If M is the mid-point of XY¯¯¯¯¯¯¯¯ , what can you say about the lengths MX and XY?
Solution:
Steps of Construction:

  1. Draw a line segment XY =10.3 cm.
    NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 19
  2. With centre X and radius > 12 XY, draw arcs one on each side of XY.
  3. With centre Y and the same radius as before, draw arcs cutting the previously drawn arcs at A and B respectively.
  4. oin .AB intersecting XY at M. Then, AB is the perpendicular bisector of XY.
    (a) Mark any point P on AB, the perpendicular bisector. On measuring, we find that PX = PY.
    (b) Since M is the mid-point of the segment XY. Therefore,
    MX = 12XY = 12 x 10.3 cm
    = 5.15 cm

Ex 14.5 Class 6 Maths Question 4.
Draw a line segment of length 12.8 cm. Using compasses, divide it into four equal parts. Verify by actual measurement.
Solution:
Steps of Construction:
NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 20

  1. Draw a line segment AB = 12.8 cm.
  2. With centre A and radius > 12 AB, draw arcs one on each side of AB.
  3. With centre B and the same radius as before, draw arcs cutting the previously drawn arcs at C and D respectively.
  4. Join CD intersecting AB at M.
  5. Further find the mid-points M1 and M2 of AM and MB respectively proceeding in the same way qs-before.
    ∴ AM1 = M1M = MM2 = M2B, On measuring, we find that each part = 3.2 cm.

Ex 14.5 Class 6 Maths Question 5.
With PQ¯¯¯¯¯¯¯¯ of length 6.1 cm as diameter draw a circle.
Solution:
Steps of Construction:
NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 21

  1. Draw a line segment PQ = 6.1 cm.
  2. Bisect the segment PQ by drawing its perpendicular bisector. Let M be its mid-point.
  3. M as centre and radius = MP draw a circle.
    The circle so obtained is the required circle.

Ex 14.5 Class 6 Maths Question 6.
Draw a circle with centre C and radius 3.4 cm. Draw any chord AB¯¯¯¯¯¯¯¯. Construct the perpendicular bisector of AB¯¯¯¯¯¯¯¯ and examine if it passes through C.
Solution:
Steps of Construction:
NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 22

  1. Mark a point C on the plane of a paper.
  2.  With C as centre and radius 3.4 cm, draw a circle.
  3. Let AB be any chord to this circle.
  4. Draw PQ, the perpendicular bisector of chord AB.
    Clearly, this perpendicular bisector passes through C, the centre of the circle.

Ex 14.5 Class 6 Maths Question 7.
Repeat Question 6, if AB happens to he a diameter.
Solution:
If AB happens to be a diameter then C will be the mid-point of the diameter AB.

Ex 14.5 Class 6 Maths Question 8.
Draw a circle of radius 4 cm. Draw any two of its chords. Construct the perpendicular bisectors of these chords. Where do they meet?
Solution:
Steps of Construction:
NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 23

  1. Mark a point O on the plane of paper.
  2. With O as centre, draw a circle of radius 4 cm.
  3. Let AB and CD be any two chords of this circle.
  4. Draw PQ and RS the perpendicular bisectors of chords AB and CD respectively.
    Clearly, these perpendicular bisectors pass through 0, the centre of the circle.

Ex 14.5 Class 6 Maths Question 9.
Draw any angle with vertex O. Take a point A on one of its arms and B on another such that OA = OB. Draw the perpendicular bisectors of OA¯¯¯¯¯¯¯¯ and OB¯¯¯¯¯¯¯¯ . Let them meet at P. Is PA = PB?
Solution:
Steps of Construction:
NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 24

  1. Draw any angle XOY.
  2. Take a point A on OX and a point B on OY such that OA = OB.
  3. Draw CD and EF, the perpendicular bisectors of OA and OB respectively. Let them meet at P.
    On measuring, we find that PA = PB.

Ex 14.6 Class 6 Maths Question 1.
Draw ZPOQ of measure 75° and find its line of symmetry.
Solution:
Steps of Construction:
NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 25

  1. Draw a ray OP.
  2. Draw ∠POR = 60° and ∠POS = 90°.
  3. Draw OQ, the bisector of ∠ROS.
    Then,
    NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 26

Ex 14.6 Class 6 Maths Question 2.
Draw an angle of measure 147° and construct its bisector.
Solution:
Steps of Construction:

  1. Draw a ray OA.
  2. Place the protractor on OA such that its centre falls on the initial point O and 0 -180 line lies along OA.
    NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 27
  3. Mark a point B on the paper against the mark of 147° on the protractor.
  4. Remove the protractor and draw OB. Then, the ∠AOB so obtained is the required angle such that ZAOB = 147°.

To construct its bisector:

  1. With centre O and a convenient radius draw an arc cutting sides OA and OB at P and Q respectively.
  2. With centre P and radius > 12 PQ, draw an arc.
  3. With centre Q and the same radius, as in the previous step, draw another arc intersecting the arc drawn in the previous step at R.
  4. Join OR and produce it to form ray OC.
    Then, the ∠AOC so obtained is the bisector of ∠AOB.

Ex 14.6 Class 6 Maths Question 3.
Draw a right angle and construct its bisector.
Solution:
Steps of Construction:
NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 28
To draw an angle of 90°:

  1. Draw a ray OA.
  2. With O as centre and any convenient radius, draw an arc cutting at P.
  3. With P as centre and same radius, draw an arc cutting the arc of step 2 at Q.
  4. With Q as centre and the same radius as in steps 2 and 3, draw an arc cutting the arc drawn in step 3 at R.
  5. With Q as centre and the same radius, draw an arc.
  6. With R as centre and the same radius, draw an arc cutting the arc drawn in step 5 at B.

To draw its bisector:

  1. With P as centre and radius > 12 PT, draw an arc in the interior of ∠AOC.
  2. With T as centre and the same radius, an in step 1, draw another arc intersecting the arc in step 1 at D.
  3. Join OD and produce it to any point E.
    Then, ∠AOE so obtained is the bisector of ∠AOC.

Ex 14.6 Class 6 Maths Question 4.
Draw an angle of measure 153° and divide it into four equal parts.
Solution:
Steps of Construction:
NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 29

  1. With the help of the protractor, draw ∠AOB = 153°.
  2. With centre O and any convenient radius, draw an arc cutting OA and OB at P and Q respectively.
  3. With centre P and radius > 12 PQ, draw an arc in the interior of ∠AOB.
  4. With centre Q and the same radius, as in step 3, draw another arc intersecting the arc in step 3 at B1.
  5. Join OB1 and produce it to any point C.
    Then, ∠AOC = 12 x ∠AOB i.e., bisector of ∠AOB.
  6. Draw OD, the bisector of ∠AOC. Then ∠AOD = ∠DOC.
  7. Draw OE, the bisector of ∠COB. Then, ∠COE = ∠COB.
    Combining these results, we have
    ∠AOD = ∠DOC = ∠COE = ∠EOB.
    Thus, ∠AOB is divided into four equal parts by the rays OD,OC and OE.

Ex 14.6 Class 6 Maths Question 5.
Construct with ruler and compasses, angles of following measures:
(a) 60°
(b) 30°
(c) 90°
(d) 45°
(f) 135°
Solution:
(a) Steps of Construction:
NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 30

  1. Draw a ray OA.
  2. With centre O and any radius, draw an arc PQ with the help of compasses, cutting the ray at P.
  3. With centre P and the same radius draw an arc cutting the arc PQ at R.
  4. Join OR and produce it to obtain ray OB.
    Then, ∠AOB so obtained is of 60°.

(b) Steps of Construction:
NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 31

  1. Draw a ray OA.
  2. With centre O any radius draw an arc PT with the help of compasses, cutting ray OA at P.
  3. With centre P and the same radius draw an arc cutting the arc PT at Q.
  4. Join OQ and produce it to obtain ray OB.
    Then, ∠AOB = 60°.
  5. With centre P and radius > 12 PQ, draw an arc in the interior of ∠AOB.
  6. With centre Q and the same radius, as in step 5, draw another arc intersecting the arc in step 5 at R.
  7. Join OR and produce it on any point C.
    Then, ∠AOC = 30°

(c) Step of Construction:
NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 32

  1. Draw a ray OA.
  2. With O as centre and any convenient radius, draw an arc cutting at P.
  3. With P as centre and same radius, draw an arc cutting the arc of step 2 at Q.
  4. With Q as centre and the same radius as in steps 2 and 3, draw an arc cutting the arc drawn in step 3 at R.
  5. With Q as centre and the same radius, draw an arc.
  6. With R as centre and the same radius, draw an arc cutting the arc drawn in step 5 at B.
  7. Join O to B and produce it to any point C.
    Then, ∠AOC =90°

(d) Steps of Construction:
NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 33

  1. Draw a ray OA.
  2. With O as centre and any convenient radius, draw an arc cutting OA at P.
  3. With P as centre and the same radius draw an arc cutting the first arc at Q.
  4. With Q as centre and the same radius, draw an cutting the arc drawn in step 2 at R.
  5. Join AR and produce it to any point C.
    Then, ∠AOC so obtained is of 120°.

(e) Steps of Construction:

  1. Draw ∠AOC = 90° by following the steps given in part (iii) above,
  2. Draw OE, the bisector of ∠AOC.
    NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 34
    Then, ∠AOD so obtained is the required angle of 45°.

(f) Steps of Construction:
NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 35

  1. Draw ∠AOC = 120°
    ∠AOB =150°.
  2. Draw OD, bisector of ∠COB.
    Then,
    NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 36

Or

Steps of Construction:
NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 37

 

  1. Draw a line AB and mark a point O on it.
  2. With centre O and any convenient radius draw a semi-circle cutting OA and OB at P and Q respectively.
  3. With Q as centre and same radius, draw an arc cutting the semi-circle as R.
  4. With R as centre and same radius, draw an arc cutting the semi-circle of step 2 at S.
  5. With R as centre and same radius draw an arc.
  6. With S as centre and same radius draw an arc cutting the arc drawn in step 5 at T. Join OT and produce it to D such that ∠BOD – ∠AOD = 90°.
  7. Draw OE, the bisector of ∠AOD.
    NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 38

Ex 14.6 Class 6 Maths Question 6.
Draw an angle of measure 45° and bisect it.
Solution:
Steps of Construction:

  1. Draw ∠AOB = 90° by the steps given in question 5 (c).
    NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 39
  2. Draw OC, the bisector of ∠AOB. Then, ∠AOC = 45°.
  3. Draw OD, the bisector of ∠AOC. Then, ∠AOD = ∠DOC.

Ex 14.6 Class 6 Maths Question 7.
Draw an angle of measure 135° and bisect it.
Solution:
Steps of Construction:

  1. Draw ∠EOB = 135° by the steps given in question 5 (f).
    NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 40
  2.  Draw OF, the bisector of ∠EOB.
    Then, ∠BOF = ∠FOE.

Ex 14.6 Class 6 Maths Question 8.
Draw an angle of 70°. Make a copy of it using only a straight edge and compasses.
Solution:
Steps of Construction:

  1. Draw an angle 70° with protractor, i. e. ∠POQ = 70°
  2. Draw a ray AB¯¯¯¯¯¯¯¯
  3. Place the compasses at O and draw an arc to cut the ray of ∠POQ at I and M.
  4. Use the same compasses, setting to draw an arc with A as centre, cutting AB at X.
  5. Set your compasses setting to the length LM with the same radius.
    NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 41
  6.  Place the compasses pointer at X and draw the arc to cut the arc drawn earlier at Y.
  7. Join A7.
    Thus, ∠YAX =70°

Ex 14.6 Class 6 Maths Question 9.
Draw an angle of 40° copy its supplementary angle.
Solution:
Steps of construction:

  1. Draw an angle of 40° with the help of protractor, naming ∠ AOB.
  2. Draw a line PQ.
    NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 42
  3. Take any point M on PQ.
  4. Place the compasses at O and draw an arc to cut the rays of ∠ AOB at L and N.
  5. Use the same compasses setting to draw an arc O as centre, cutting MQ at X.
  6.  Place the compasses at X and draw the arc to cut the arc drawn earlier Y.
  7. Join MY.
    Thus, ∠QMY = 40° and ∠PMY is supplementary of it.
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NCERT MOST IMPORTANT QUESTIONS CLASS – 12 | PSYCHOLOGY IMPORTANT QUESTIONS | CHAPTER-7 | SOCIAL INFLUENCE AND GROUP PROCESSESS | EDUGROWN |

In This Post we are  providing  CHAPTER 7 SOCIAL INFLUENCE AND GROUP PROCESSESS NCERT MOST IMPORTANT QUESTIONS for Class 12 PSYCHOLOGY which will be beneficial for students. These solutions are updated according to 2021-22 syllabus. These MCQS  can be really helpful in the preparation of Board exams and will provide you with a brief knowledge of the chapter

NCERT MOST IMPORTANT QUESTIONS ON SOCIAL INFLUENCE AND GROUP PROCESSESS

1. Compare and contrast formal and informal groups, and in groups and outgroups.

Answer

Formal and Informal Groups
These groups differ in the degree to which the functions of the group are stated explicitly and formally. The functions of a formal group are explicitly stated as in the case of an office organisation. The roles to be performed by group members are stated in an explicit manner. The formal and informal groups differ on the basis of structure. The formation of formal groups is based on some specific rules or laws and members have definite roles. There are a set of norms which help in establishing order. A university is an example of a formal group. On the other hand, the formation of informal groups is not based on rules or laws and there is close relationship among members.

Ingroup and Outgroup
Just as individuals compare themselves with others in terms of similarities and differences with respect to what they have and what others have, individuals also compare the group they belong to with groups of which they are not a member. The term ‘ingroup’ refers to one’s own group, and ‘outgroup’ refers to another group. For ingroup members, we use the word ‘we’ while for outgroup members, the word ‘they’ is used. By using the words they and we, one is categorising people as
similar or different. It has been found that persons in the ingroup are generally supposed to be similar, are viewed favourably, and have desirable traits. Members of the outgroup are viewed differently and are often perceived negatively in comparison to the ingroup members. Perceptions of ingroup and outgroup affect our social lives.

2. Are you a member of a certain group? Discuss what motivated you to join that group.

Answer

Yes, I am a member of a certain group.These are the factors which motivated me to join that group:
(i) Security : When we are alone, we feel insecure.  Groups  reduce  this insecurity. Being with people gives a sense of comfort, and protection. As a result, people feel stronger, and are less vulnerable to threats.
(ii) Status : When we are members of a group that is perceived to be important by others, we feel recognised and experience a sense of power. Suppose your school wins in an inter-institutional debate competition, you feel proud and think that you are better than others.
(iii) Self-esteem : Groups provide feelings of self-worth and establish a positive social identity. Being a member of prestigious groups enhances one’s self-concept.
(iv) Satisfaction of one’s psychological and social needs : Groups satisfy one’s social and psychological needs such as sense of belongingness, giving and receiving attention, love, and power through a group.
(v) Goal achievement : Groups help in achieving such goals which cannot be attained individually. There is power in the majority.
(vi) Provide knowledge and information : Group membership provides knowledge and information and thus broadens our view. As individuals, we may not have all the required information. Groups supplement this information and knowledge.

3. How does Tuckman’s stage model help you to understand the formation of groups?

Answer

Groups usually go through different stages of formation, conflict, stabilisation, performance, and dismissal. Tuckman’s stage model suggested that groups pass through five developmental sequences which are forming, storming, norming, performing and adjourning.
(i) Forming stage: When group members first meet, there is a great deal of uncertainty about the group, the goal, and how it is to be achieved. People try to know each other and assess whether they will fit in. There is excitement as well as apprehensions.
(ii) Storming stage: It is a stage of intragroup conflict which is referred to as storming. In this stage, there is conflict among members about how the target of the group is to be achieved, who is to control the group and its resources, and who is to perform what task. When this stage is complete, some sort of hierarchy of leadership in the group develops and a clear vision as to how to achieve the group goal.
(iii) Norming stage: This storming stage is followed by norming. Group members by this time develop norms related to group behaviour. This leads to development of a positive group identity.
(iv) performing stage: It is the fourth stage. By this time, the structure of the group has evolved and is accepted by group members. The group moves towards achieving the group goal. For some groups, this may be the last stage of group development.
(v) Adjourning stage: For some groups, for example, in the case of an organising committee for a school function, there may be last stage and group comes to an end. In this stage, once the function
is over, the group may be disbanded.

4. How do groups influence our behaviour?

Answer

Groups and individuals exert influence on us which may force us to change our behaviours in a particular direction. Group influence our behaviour by the method of ‘social influence’ which means getting influenced by the imagined presence of other people. Throughout the day we may encounter a
number of situations where others have tried to influence our and make us think in ways they want.Social influence is a part of our life. In some situations, social influence on us is very strong as a result of which we tend to do things which we otherwise would have not done. On other occasions, we are able to defy influence of others and may even influence them to adopt our own viewpoint
There are three important group influence processes, i.e. conformity, compliance and obedience.
(i) Conformity: It means behaving according to the group norm, i.e. the expectations of other group members. Persons who do not conform (called ‘deviants’ or ‘non-conformists’) get noticed more than those who do conform.
(ii) Compliance: In this, there are external conditions that force the individual to accept the influence of the significant other. Compliance also refers to behaving in a particular way in response to a request made by someone. It could take place even without a norm
(iii) Obedience: A distinguishing feature of obedience is that such behaviour is a response to a person in authority. The presence of an authority figure immediately makes this behaviour different from conformity. For instance, you may stop talking loudly in the classroom when the teacher asks you
to keep quiet, but not when your classmate tells you to do the same thing.

5. How can you reduce social loafing in groups? Think of any two incidents of social loafing in school. How did you overcome it?

Answer

It has been found that individuals work less hard in a group than they do when performing alone. This
points to a phenomenon referred to as ‘social loafing’. Social loafing is a reduction in individual effort when working on a collective task, i.e. one in which outputs are pooled with those of other group members. An example of such a task is the game of tug-of-war. It is not possible for
us to identify how much force each member of the team has been exerting. Such situations give opportunities to group members to relax and become a free rider.
This phenomenon has been demonstrated in many experiments by Latane and his associates who asked group of male students to clap or cheer as loudly as possible as they (experimenters) were interested in knowing how much noise people make in social settings. They varied the group size; individuals were either alone, or in groups of two, four and six. The results of the study showed that although the total amount of noise rose up, as size increased, the amount of noise produced by each participant dropped. In other words, each participant put in less
effort as the group size increased. Reasons for the occurrence of social loafing:
(i) Group members feel less responsible for the overall task being performed and therefore exert less effort.
(ii) Motivation of members decreases because they realise that their contributions will not be evaluated on individual basis.https://b9ce6b68e5900a017d56c6b5a379a7ad.safeframe.googlesyndication.com/safeframe/1-0-38/html/container.html(iii) The performance of the group is not to be compared with other groups.
(iv) There is an improper coordination (or no coordination) among members.
(v) Belonging to the same group is not important for members. It is only an aggregate of individuals.

Two incidents of social loafing in school:
(i) Some students work very less in group projects and works.
(ii) Sometimes during sports competition, some students practice very less and thus this affect the whole team.
It may be reduced by:
(i) Making the efforts of each person identifiable.
(ii) Increasing the pressure to work hard (making group members committed to successful task performance).
(iii) Increasing the apparent importance or value of a task.
(iv) Making people feel that their individual contribution is important.
(v) Strengthening group cohesiveness which increases the motivation for successful group outcome.

6. How often do you show conformity in your behaviour? What are the determinants of conformity?

Answer

Conformity in your behavior means behaving according to the group norm, i.e. the expectations of other group members. Conformity in behavior can be shown by the following examples. Some of your friends come to you with a letter of protest against a rule that has been recently announced, i.e. banning use of mobile phones in the school. Personally you believe that the rule is very sensible and should be enforced. But you also know that if you do not sign the letter. Thus, I have to behave according to the group norm.
Determinants of conformity are size of the group, Size of the minority, nature of the task, public or private expression of behaviour and personality.
(i) Size of the group: Conformity is greater when the group is small than when the group is large. It
is easier for a deviant member (one who does not conform) to be noticed in a small group. However, in a large group, if there is strong agreement among most of the members, this makes the majority
stronger, and therefore, the norm is also stronger. In such a case, the minority member(s) would be more likely to conform because the group pressure would be stronger.
(ii) Size of the minority :  Suppose the subject finds that after some rounds of judgment of the lines, there is another participant who starts agreeing with the subject’s answer. When the dissenting
or deviating minority size increases, the likelihood of conformity decreases. In fact, it may increase the number of dissenters or non-conformists in the group.
(iii) Nature of the task: In Asch’s experiment, the task required an answer that could be verified, and could be correct or incorrect. Suppose the task involves giving an opinion about some topic. In
such a case, there is no correct or incorrect answer then conformity would be less likely in the second situation.
(iv) Public or private expression of behaviour: In the Asch technique, the group members are asked to give their answers publicly, i.e. all members know who has given which response. However, there can be other situations in which the behaviour of members is private. Less conformity is found under private expression than it is seen under public expression.
(v) Personality: The conditions described above show how the features of the situation are important in determining the degree of conformity shown. We also find that some individuals have a conforming personality. Such persons have a tendency to change their behaviour according to what others say or do in most situations.

7. Why do people obey even when they know that their behaviour may be harming others? Explain.

Answer

People obey even when they know that their behaviour may be harming others because if we disobey, some punishment might follow. Sometimes, it is because we believe that persons in authority must be obeyed.
Several reasons for this are:
(i) People obey because they feel that they are not responsible for their own actions, they are simply carrying out orders from the authority.
(ii) Authority generally possesses symbols of status (e.g., uniform, title) which people find difficult to resist.
(iii) Authority  gradually increases commands from lesser to greater levels and initial obedience binds the followers for commitment. Once you obey small orders, slowly there is an escalation of commitment for the person who is in authority and one starts obeying bigger orders.
(iv) Many times, events are moving at such a fast speed, for example in a riot situation, that one has no time to think, just obey orders from above.

8. What are the benefits of cooperation?

Answer

When groups work together to achieve shared goals, we call it cooperation. The rewards in
cooperative situations are group rewards and not individual rewards.
Benefits of coopoeration:
(i) People work together and hence work load on each individual is less.
(ii) Each individual can attain the goal only if other members of the group also attain the goal.
(iii) In cooperative groups, there is more coordination and acceptance for each other’s ideas.
(iv) members became more friendly and can excel easily in groups.
(v) Members are more active towards communication, interaction and discussions.

9. How is one’s identity formed?

Answer

One’s self-definition of who s/he is which may include both personal attributes, e.g. hard working, happy-go-lucky, or attributes which you share with others, e.g. girl or boy is known as social identity.
One’s self identity is formed by oneself as a unique individual, and social identities derived from groups we perceive ourselves to be members of.
Although some aspects of our identity are determined by physical characteristics, one may acquire other aspects as a consequence of our interaction with others in society. Sometimes we perceive ourselves as unique individuals and at other times we perceive ourselves as members of groups. Both are equally valid expressions of self. The extent to which we define ourselves either at personal or at social levels is flexible. From our own experience, we would realise that identification with social groups can have a great deal of importance for your self-concept. feel so because of our social identity as an Indian. Social identity is, thus, that aspect of our self-concept which is based
on our group membership. Social identity places us, i.e. tells us what and where we are in the larger social context, and thus helps us to locate ourselves in society.

10. What are some of the causes of intergroup conflict? Think of any international conflict. Reflect on the human price of this conflict.

Answer

Some of the major reasons for group conflicts are:
(i) Lack  of communication and faulty communication by both parties. This kind of communication leads to suspicion, i.e. there is a lack of trust. Hence, conflict results.
(ii) Another reason for intergroup conflict is relative deprivation. It arises when members of a group compare themselves with members of another group, and perceive that they do not have what they desire to have, which the other group has. In other words, they feel that they are not doing well in comparison to other groups. This may lead to feelings of deprivation and discontentment, which may trigger off conflict.
(iii) Another cause of conflict is one party’s belief that it is better than the other, and what it is saying should be done. When this does not happen, both parties start accusing each other. One may often witness a tendency to magnify even smaller differences, thereby conflict gets escalated because every member wants to respect the norms of her/his group.
(iv) A feeling that the other group does not respect the norms of my group, and actually violates those norms because of a malevolent intent.
(v) Desire for retaliation for some harm done in the past could be another reason for conflict.
(vi) Biased perceptions are at the root of most conflicts. As already mentioned earlier, feelings of ‘they’ and ‘we’ lead to biased perceptions.
(vii) Research has shown that when acting in groups, people are more competitive as well as more aggressive than when they are on their own. Groups compete over scarce resources, both material resources, e.g. territory, and money as well as social resources, e.g. respect and esteem.

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Chapter-13 Symmetry | Class 6th | NCERT Maths Solutions | Edugrown

NCERT Solutions for Class 6 Maths: One of the most important and interesting things to keep in mind is that these solutions available are totally free of cost. This also includes all the solutions to the exercises that are given in the textbook. NCERT solutions for class 6 maths gives you chapter-wise solutions to each and every question. This can help you solve even the tougher with ease.

It is always good to have a strong foundation in order to build a good building. This also is true in class when you are still learning the basics of maths. NCERT solutions for class 6 maths provides you the exact opportunity to build a strong foundation in this subject. Below is an overview of each and every chapter covered in the NCERT textbook.

NCERT Solutions for Class 6 Maths Chapter 13 Symmetry

Ex 13.1 Class 6 Maths Question 1.
List any four symmetrical objects from your home or school.
Solution:
List of four symmetrical objects from home or school are
(i) An electric tube
(ii) A glass
(iii) An electric bulb
(iv) A fan

Ex 13.1 Class 6 Maths Question 2.
For the given figure, which one is the mirror line, l1 or l2
NCERT Solutions for Class 6 Maths Chapter 13 Symmetry 1
Solution:
From the given figure, clearly l2 is the mirror line.

Ex 13.1 Class 6 Maths Question 3.
Identify the shapes given below. Check whether they are symmetric or not. Draw the line of symmetry as well.
NCERT Solutions for Class 6 Maths Chapter 13 Symmetry 2
Solution:
Figures (a), (b), (d), (e) and (f) are symmetrical and their line of symmetry is shown as a dotted line.
NCERT Solutions for Class 6 Maths Chapter 13 Symmetry 3

Ex 13.1 Class 6 Maths Question 4.
Copy the following on a squared paper. A square paper is what you would have used in your arithmetic notebook in earlier classes. Then complete them such that the dotted line is the line of symmetry.
NCERT Solutions for Class 6 Maths Chapter 13 Symmetry 4
Solution:
Keeping the dotted line as the line of symmetry and completing the figure, we have
NCERT Solutions for Class 6 Maths Chapter 13 Symmetry 5

Ex 13.1 Class 6 Maths Question 5.
In the figure, l is the line of symmetry. Complete the diagram to make it symmetric.
NCERT Solutions for Class 6 Maths Chapter 13 Symmetry 6
Solution:
Complete diagram is as under:
NCERT Solutions for Class 6 Maths Chapter 13 Symmetry 7

Ex 13.1 Class 6 Maths Question 6.
In the figure, l is the line of symmetry. Draw the image of the triangle and complete the diagram so that it becomes symmetric.
NCERT Solutions for Class 6 Maths Chapter 13 Symmetry 8

Solution:
The image of the triangle is shown such that the complete diagram becomes symmetric.
NCERT Solutions for Class 6 Maths Chapter 13 Symmetry 9

Ex 13.2 Class 6 Maths Question 1.
Find the number of lines of symmetry for each of the following shapes.
NCERT Solutions for Class 6 Maths Chapter 13 Symmetry 10
Solution:
Each one of the given figures are symmetrical about the dotted line(s) drawn. The number lines of symmetry are indicated against each figure:
NCERT Solutions for Class 6 Maths Chapter 13 Symmetry 11
NCERT Solutions for Class 6 Maths Chapter 13 Symmetry 12

Ex 13.2 Class 6 Maths Question 2.
Copy the triangle in each of the following figures on squared paper. In each case, draw the line(s) of symmetry, if any and identify the type of triangle. (Some of you may like to trace the figures and try paper-folding first!)
NCERT Solutions for Class 6 Maths Chapter 13 Symmetry 13
Solution:
(a), (b) and (d) are isosceles triangles, (c) is a right angled isosceles triangle. Their line(s) of symmetry marked with dotted line(s) in each case as under:
NCERT Solutions for Class 6 Maths Chapter 13 Symmetry 14

Ex 13.2 Class 6 Maths Question 3.
Complete the following table :
NCERT Solutions for Class 6 Maths Chapter 13 Symmetry 15
Solution:
Complete table with rough figures duly filled is as under:
NCERT Solutions for Class 6 Maths Chapter 13 Symmetry 16
NCERT Solutions for Class 6 Maths Chapter 13 Symmetry 17

Ex 13.2 Class 6 Maths Question 4.
Can you draw a triangle which has
(a) exactly one. line of symmetry?
(b) exactly two lines of symmetry?
(c) exactly three lines of symmetry?
(d) no lines of symmetry? Sketch a rough figure in each case.
Solution:
(a) Yes, it is an isosceles triangle. Its rough sketch is as shown.
NCERT Solutions for Class 6 Maths Chapter 13 Symmetry 18
(b) No.
(c) Yes, it is an equilateral triangle. Its rough sketch is as shown.
NCERT Solutions for Class 6 Maths Chapter 13 Symmetry 19
(d) Yes, it is a scalene triangle. Its rough sketch is as shown.
NCERT Solutions for Class 6 Maths Chapter 13 Symmetry 20

Ex 13.2 Class 6 Maths Question 5.
On a squared paper, sketch the following:
(a) A triangle with a horizontal line of symmetry but no vertical line of symmetry.
(b) A quadrilateral with both horizontal and vertical lines of symmetry.
(c) A quadrilateral with a horizontal line of symmetry but no vertical line of symmetry.
(d) A hexagon with exactly two lines of symmetry.
(e) A hexagon with six lines of symmetry.
Solution:
Sketches of the required figure with their line(s) of symmetry are shown as under:
NCERT Solutions for Class 6 Maths Chapter 13 Symmetry 21

Ex 13.2 Class 6 Maths Question 6.
Trace each figure and draw the lines of symmetry, if any:
NCERT Solutions for Class 6 Maths Chapter 13 Symmetry 22
Solution:
The line(s) of symmetry of the given figures are shown as dotted lines as under:
NCERT Solutions for Class 6 Maths Chapter 13 Symmetry 23
NCERT Solutions for Class 6 Maths Chapter 13 Symmetry 24

Ex 13.2 Class 6 Maths Question 7.
Consider the letters of English alphabets, A to Z.
List among them the letters which have
NCERT Solutions for Class 6 Maths Chapter 13 Symmetry 25

(a) vertical lines of symmetry (like A)
(b) horizontal lines of symmetry (like B)
(c) no lines of symmetry (like Q)
Solution:
The English alphabets A to Z having
(a) vertical lines of symmetry (like A) are
A, H, I, M, O, T, U, V, W, X and Y.
(b) horizontal lines of symmetry (like B) are
B, C, D, E, H, I, K, O and X.
(c) no lines of symmetry (like Q) are G, J, L, P, Q, R, S and Z.

Ex 13.2 Class 6 Maths Question 8.
Given here are figures of a few folded sheets and designs drawn about the fold. In each case, draw a rough diagram of the complete figure that would be seen when the design is cut off.
NCERT Solutions for Class 6 Maths Chapter 13 Symmetry 26
Solution:
The rough diagram of the complete figure that would be seen when the design is cut off is as under:
NCERT Solutions for Class 6 Maths Chapter 13 Symmetry 27

Ex 13.3 Class 6 Maths Question 1.
Find the number of lines of symmetry in each of the following shapes: .
How will you check your answers?
NCERT Solutions for Class 6 Maths Chapter 13 Symmetry 28
Solution:
By drawing the line(s) of symmetry, we find that the number of line(s) possessed by them are
NCERT Solutions for Class 6 Maths Chapter 13 Symmetry 29

Ex 13.3 Class 6 Maths Question 2.
Copy the following drawing on squared paper. Complete each one of them such that the resulting figure has two dotted lines as two lines of symmetry:
NCERT Solutions for Class 6 Maths Chapter 13 Symmetry 30
How did you go about completing the picture?
Solution:
Completing the figures using the given line(s) of symmetry. The completed figures are as under:
NCERT Solutions for Class 6 Maths Chapter 13 Symmetry 31

Ex 13.3 Class 6 Maths Question 3.
In each figure alongside, a letter of the alphabet is shown along with a vertical line. Take the mirror image of the letter in the given line. Find which letters look the same after reflection (i.e. which letters look the same in the image) and which do not. Can you guess why?
NCERT Solutions for Class 6 Maths Chapter 13 Symmetry 32
Try for O E M N P H L T S V X
Solution:
Taking the mirror image of the letters A and B in the given line. These will look as shown.
NCERT Solutions for Class 6 Maths Chapter 13 Symmetry 33
Clearly, A after reflection looks same but B does not.
It is due to the reason that the shape is preserved but sense is not.
Out of the given letters:
O, M, H, T, V, and X look as before after reflection, whereas E, P, N, L, and S does not.

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Chapter-12 Ratio and Proportion | Class 6th | NCERT Maths Solutions | Edugrown

NCERT Solutions for Class 6 Maths: One of the most important and interesting things to keep in mind is that these solutions available are totally free of cost. This also includes all the solutions to the exercises that are given in the textbook. NCERT solutions for class 6 maths gives you chapter-wise solutions to each and every question. This can help you solve even the tougher with ease.

It is always good to have a strong foundation in order to build a good building. This also is true in class when you are still learning the basics of maths. NCERT solutions for class 6 maths provides you the exact opportunity to build a strong foundation in this subject. Below is an overview of each and every chapter covered in the NCERT textbook.

NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion

Ex 12.1 Class 6 Maths Question 1.
There are 20 girls and 15 boys in a class,
(a) What is the ratio of number of girls to the number of boys?
(b) What is the ratio of number of girls to the total number of students in the class?
Solution:
We have,
Number of girls = 20
Number of boys =15
Number of students in the class = (20 + 15) = 35.
(a) Ratio of number of girls to the number of boys
=20 : 15 = 4 : 3
[Dividing the first and second term by their H.C.F. = 5]

(b) Ratio of number of girls to the total number of students
= 20 : 35
= 4 : 7
[Dividing the first and second term by their H.C.F = 5]

Ex 12.1 Class 6 Maths Question 2.
Out of 30 students in a class, 6 like football, 12 like cricket and remaining like tennis. Find the ratio of:
(a) Number of students liking football to number of students liking tennis.
(b) Number of students liking cricket to total number of students.
Solution:
We have,
Total number of students = 30
Number of students who like football = 6
Number of students who like cricket = 12
Number of students who like tennis = 30 – (6 +12)
= 30 – 18 = 12
(a) Ratio of number of students liking football to the number of students liking tennis
= 6 : 12 = 1 : 2
[Dividing the first and second term by their H.C.F. = 6]

(b) Ratio of number of students liking cricket to total number of students
= 12 : 30
= 2 : 5
[Dividing the first and second term by their H.C.F. = 6]

Ex 12.1 Class 6 Maths Question 3.
See the figure and find the ratio of:
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 1
(a)
 Number of triangles to the number of circles inside the rectangle.
(b) Number of square to all the figures inside the rectangle.
(c) Number of circles to all the figures inside the rectangle.
Solution:
From the given figure, we have
Number of triangle =3
Number of circles =2
Number of square =2
Total number of figures = 3+ 2 + 2 = 7
(a) Ratio of the number of triangles to the number of circles = 3 : 2
(b) Ratio of the number of squares to all the figures =2 : 7
(c) Ratio of the number of .circles it) all the figures = 2 : 7

Ex 12.1 Class 6 Maths Question 4.
Distance travelled by Hamid and Akhtar in an hour are 9 km and 12 km. Find the ratio of speed of Hamid to the speed of Akhtar.
Solution:
We know that,
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 2
∴ Ratio of the speed of Hamid to the speed of Akhtar
= 9 : 12
= 3 : 4
[Dividing the first term and the second term by their H.C.F. = 3

Ex 12.1 Class 6 Maths Question 5.
Fill in the following blanks:
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 3
Solution:
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 4
These are equivalent fractions.

Ex 12.1 Class 6 Maths Question 6.
Find the ratio of the following:
(a) 81 to 108
(b) 98 to 63
(c) 33 km to 121 km
(d) 30 minutes to 45 minutes.
Solution:
(a) 81 to 108 = 81 : 108 = 3 : 4
[Dividing the first and second terms by their H.C.F. = 27]
(b) 98 to 63 = 98 : 63
= 14 : 9
[Dividing the first and the second terms by their H.C.F-= 7]
(c) 33 km to 121 km = 33 : 121
= 3 : 11
[Dividing the first and the second terms by their H.C.F. =11]
(d) 30 minutes to 45 minutes = 30 : 45
= 2:3
[Dividing the first and the second terms by their H.C.F. = 15]

Ex 12.1 Class 6 Maths Question 7.
Find the ratio of the following:
(a) 30 minutes to 1.5 hours
(b) 40 cm to 1.5 m
(c) 55 paise to ₹1
(d) 500 ml to 2 litres
Solution:
(a) 30 minutes to 1.5 hours = 30 minutes: 1.5 x 60 minutes
[∵ 1 hour = 60 minutes]
= 30 min : 90 min = 30 :90 = 1:3
[Dividing the first and the second terms by their H.C.F = 30]

(b) 40 cm to 1.5 m = 40 cm : 1.5 x 100 cm [∵ 1 m = 100 cm]
= 40 cm : 150 cm
= 40 :150 = 4:15
[Dividing the first and the second terms by their H.C.F. = 10]

(c) 55 paise to ₹ 1 = 55 paise : 100 paise [∵ ₹ 1 =100 paise]
= 55 : 100
= 11 : 20
[Dividing the first and the second terms by their H.C.F = 5]

(d) 500 ml to 2 litres = 500 ml: 2 x 1000 ml [∵ 1 litre = 1000 ml]
= 500 : 2000
= 1 : 4
[Dividing the first term and the second terms by their H.C.F = 500]

Ex 12.1 Class 6 Maths Question 8.
In a year, Seema earns ? 1,50,000 and saves ? 50,000. Find the ratio of:
(a) Money that Seema earns to the money she saves.
(b) Money that she saves to the money she spends.
Solution:
Seema’s income = ₹150000
Seema’s savings = ₹ 50000
Seema’s expenditure = ₹ 150000 – ₹ 50000
= ₹ 100000
(a) Ratio of Seema’s earnings to her savings
= ₹ 150000 : ₹ 50000
= 150000 : 50000
= 3 : 1
[Dividing the first term and the second term by their H.C.F = 50000]

(b) Ratio of Seema’s savings to her expenditure
= ₹ 50000 : ₹ 100000
= 50000 : 100000 = 1 : 2
[Dividing the first term and the second term by their H.C.F. = 50000]

Ex 12.1 Class 6 Maths Question 9.
There are 102 teachers in a school of 3300 students. Find the ratio of the number of teachers to the number of students.
Solution:
We have,
Number of teachers =102
Number of students = 3300
∴ Ratio of the number of teachers to the number of students
= 102 : 3300
= 17 : 550
[Dividing the first term and the second term by their H.C.F = 6]

Ex 12.1 Class 6 Maths Question 10.
In a college out of 4320 students, 2300 are girls. Find the ratio of:
(a) Number of girls to the total number of students.
(b) Number of boys to the number of girls.
(c) Number of boys to the total number of students.
Solution:
We have,
Total number of students = 4320
Number of girls = 2300
∴ Number of boys = (4320 – 2300) = 2020
(a) Ratio of number of girls to the total number of students
= 2300 : 4320
= 115 : 216
[Dividing the first term and the second term by their H.C.F = 20]

(b) Ratio of number of boys to number of girls
= 2020 : 2300
= 101 : 115
[Dividing the first term and the second term by their H.C.F = 20]

(c) Ratio of number of boys to the total number of students
= 2020 : 4320
= 101 : 216
[Dividing the first term and the second term by their H.C.F. = 20]

Ex 12.1 Class 6 Maths Question 11.
Out of 1800 students in a school, 750 opted basketball, 800 opted cricket and remaining opted table tennis. If a student can opt only one game, find the ratio of:
(a) Number of students who opted basketball to the number of students who opted table tennis.
(b) Number of students who opted cricket to the number of students opting basketball.
(c) Number of students who opted basketball to the total number of students.
Solution:
We have,
Total number of students = 1800
Number of students who opted basketball = 750
Number of students who opted cricket = 800
∴ Number of students who opted table tennis
= 1800 – (750 + 800)
= 1800 – 1550 = 250
(a) Ratio of number of students opting basketball to number of students opting table tennis
= 750 : 250
= 3 : 1
[Dividing the first term and the second term by their H.C.F. = 250]

(b) Ratio of number of students opting cricket to number of students opting basketball
= 800 : 750
= 16 : 15
[Dividing the first term and the second term by their H.C.F. = 50]

(c) Ratio of number of students opting basketball to the total number of students
= 750 : 1800
= 5 : 12
[Dividing the first term and the second term by their H.C.F = 150]

Ex 12.1 Class 6 Maths Question 12.
Cost of a dozen pens is ? 180 and cost of 8 ball pens is ? 56. Find the ratio of the cost of a pen to the cost of a ball pen.
Solution:
In order to compare the cost of pen with that of ball pen, we must first find the cost of the same quantity of each of them.
Let us find the cost of one item of each.
Cost of 1 dozen i.e., 12 pens
= ₹ 180
∴ Cost of 1 pen = ₹ 180 -12 = ₹ 15
Cost of 8 ball pens = ₹ 56
∴ Cost of 1 ball pen = ₹ 56 – 8 = ₹ 7
∴ Ratio of the cost of a pen to the cost of a ball pen
= Cost of 1 pen : Cost of 1 ball pen
= ₹ 15 : ₹ 7 = 15 : 7.

Ex 12.1 Class 6 Maths Question 13.
Consider the statement: Ratio of breadth and length of a hall is 2:5.
Complete the following table that shows some possible breadths and lengths of the hall.
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 5
Solution:
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 6
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 7

Ex 12.1 Class 6 Maths Question 14.
Divide 20 pens between Sheela and Sangeeta in the ratio of 3:2.
Solution:
Sum of the terms of the ratio = (3 + 2) = 5
Total number of pens = 20
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 8

Ex 12.1 Class 6 Maths Question 15.
Mother wants to divide ? 36 between her daughters Shreya and Bhoomika in the ratio of their ages. If age of Shreya is 15 years and age of Bhoomika is 12 years, find how much Shreya and Bhoomika will get.
Solution:
Shreya’s age : Bhoomika’s age =15 : 12
= 5 : 4
[Dividing the 1st and the 2nd term by their H.C.F = 3]
Since mother wants to divide ₹ 36 between Shreya and Bhoomika in the ratio of their ages. So, the money will be divided in the ratio 5 : 4.
Sum of the terms of the ratio = (5 + 4) = 9
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 9

Ex 12.1 Class 6 Maths Question 16.
Present age of father is 42 years and that of his son is 14 years. Find the ratio of:
(a) Present age of father to the present age of son.
(b) Age of the father to the age of son, when son was 12 years old.
(c) Age of father after 10 years to the age of son after 10 years. Age of father to the age of son when father was 30 years old.
Solution:
We have,
Present age of father = 42 years
Present age pf son = 14 years.
(a) Ratio of present age of father to the present age of son
= 42 years : 14 years
= 42 : 14
= 3 : 1
[Dividing the first term and the second terms by their H.C.F. = 14]

(b) When son’s age is 12 years (i.e., 2 years ago). Then, father’s age
= (42 – 2) = 40 years.
Required ratio = 40 years : 12 years = 40 :12
= 10 : 3
[Dividing the first term and the second terms by their H.C.F = 4]

(c) After 10 years:
Father’s age = (42+10) years = 52 years
Son’s age = (14 +10) years = 24 years
∴ Required ratio = 52 years : 24 years
= 52 : 24
= 13 : 6
[Dividing the first term and the second terms by their H.C.F = 4]

(d) When father’s age is 30 years (i.e., 12 years age), then son’s age
= (14 -12) years = 2 years.
∴ Required ratio = 30 years : 2 years
= 30 : 2
= 15 : 1
[Dividing the first term and the second terms by their H.C.F = 2]

Ex 12.2 Class 6 Maths Question 1.
Determine if the following are in proportion:
(a) 15, 45, 40, 120
(b) 33, 121, 9, 96
(c) 24, 28, 36, 48
(d) 32, 48, 70, 210
(e) 4, 6, 8, 12
(f) 33, 44, 75, 100
Solution:
We have,
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 10
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 11
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 12

Ex 12.2 Class 6 Maths Question 2.
Write True (T) or False (F) against each of the following statements:
(a) 16: 24:: 20: 30
(b) 21 : 6 :: 35 : 10
(c) 12 : 18 :: 28 : 12
(d) 8 : 9 :: 24 : 27
(e) 5.2 : 3.9 :: 3 : 4
(f) 0.9 : 0.36 :: 10 : 4
Solution:
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 13

Ex 12.2 Class 6 Maths Question 3.
Are the foUowing statements true?
(a) 40 persons : 200 persons =₹ 15 : ₹ 75
(b) 7.5 litres : 15 litres = 5 kg : 10 kg
(c) 99 kg: 45 kg = ₹ 44 : ₹ 20
(d) 32 m : 64 m = 6 sec : 12 sec
(e) 45 km : 60 km = 12 hours : 15 hours,
Solution:
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 14
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 15

Ex 12.2 Class 6 Maths Question 4.
Determine if the following ratios form a proportion. Also, write the middle terms and extreme terms where the ratios form a proportion.
(a) 25 cm : 1 m and ₹ 40: ₹ 160
(b) 39 litres : 65 litres and 6 bottles : 10 bottles
(c) 2 kg : 80 kg and 25 g : 625 g
(d) 200 ml: 2.5 litre and ₹ 4 : ₹ 50.
Solution:
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 16
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 17

Question 1.
If the cost of 7 m of cloth is X 294, find the cost of 5 m of cloth.
Solution:
Cost of 7 m of cloth = ₹ 294
∴ Cost of 1 m of cloth = ₹ (294 7)
= ₹ 42
∴ Cost of 5 m of cloth = ₹ (42 x 5)
= ₹ 210.
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 18

Question 2.
Ekta earns X1500 in 10 days. How much will she earn in 30 days?
Solution:
Ekta’s earning of 10 days = ₹ 1500
Ekta’s earning of 1 day = ₹ (1500 ÷ 10)
= ₹ 150
∴ Ekta’s earning of 30 days = ₹ (150 x 30)
= ₹ 4500

Question 3.
If it has rained 276 mm in the last 3 days, how many cm of rain will fall in one full week (7 days) ? Assume that the rain continues to fall at the same rate.
Solution:
Rainfall in 3 days = 276 mm
∴ Rainfall in 1 day = (276 + 3) mm = 92 mm
Rainfall in 1 week (i.e., 7 days) = (92 x 7) mm
= 644 mm.
In cm, rainfall in one full week = 644 x 110 cm [1 m = 110 cm]
= 64.4 cm

Question 4.
Cost of 5 kg of wheat is ? 30.50.
(a) What will be the cost of 8 kg of wheat?
(b) What quantity of wheat can be purchased in ₹ 61?
Solution:
(a) Cost of 5 kg of wheat = ₹ 30.50
∴ Cost of 1 kg of wheat = ₹ (30.50 ÷ 5) = ₹ 6.10
∴ Cost of 8 kg of wheat = ₹ (6,10 x8) = ₹ 48.80
(b) For ₹ 30.50, wheat purchased= 5 kg
For ₹ 1, wheat purchased = (5 ÷30.50) kg
NCERT Solutions for Class 6 Maths Chapter 12 Ratio and Proportion 19
Question 5.
The temperature dropped 15 degree celsius in the last 30 days. If the rate of temperature drop remains the same, how many degrees will the temperature drop in the next ten days?
Solution:
In 30 days, drop in temperature =15 degrees
∴ In 1 day, drop in temperature = 1530 degree = 12 degree
∴ In the next 10 days, drop in temperature = (12×10) degree = 5 degrees.

Question 6.
Shaina pays ? 7500 as rent for 3 months. How much does she has to pay for a whole year, if the rent per month remains same?
Solution:
Rent payment for 3 months = ₹ 7500
∴ Rent payment for 1 month = ₹ (7500 + 3) = ₹ 2500
∴ Rent payment for 1 year i.e., 12 months
= ₹ (2500 x 12) = ₹ 30000.

Question 7.
Cost of 4 dozens of bananas is ₹ 60. How many bananas can be purchased for ₹ 12.50?
Solution:
For ₹ 60, number of bananas purchased = 4 dozens i.e., 48
∴ For ₹ 1, number of bananas purchased = 4860=45
∴ For ₹ 12.50, number of bananas purchased = (45×12.50)
= 4 x 2.50 = 10.

Question 8.
The weight of 72 books is 9 kg. What is the weight of 40 such books?
Solution:
Weight of 72 books = 9 kg
∴ Weight of 1 book = 972 kg = 18kg
∴ Weight of 40 books = (18×40) = 5 kg.

Question 9.
A truck requires 108 litres of diesel for covering a distance of 594 km. How much diesel will be required by the truck to cover a distance of 1650 km?
Solution:
For 594 km, diesel required = 108 litres
∴ For 1 km, diesel required = (108594) litres = (211) litres
∴ For 1650 km, diesel required = (211×1650) litres
= (2 x 150) litres = 300 litres.

Question 10.
Raju purchases 10 pens for ^₹ 150 and Manish buys 7 pens for ₹ 84. Can you say who got the pens cheaper?
Solution:
In case of Raju:
Cost of 10 pens = ₹ 150
∴ Cost of 1 pen = ₹ (15010) = ₹ 15
In case of Manish :
Cost of 7 pens = ₹ 84
∴ Cost of 1 pen = ₹ (847) = ₹ 12
Since 12 < 15 ∴ Manish got the pen cheaper. Question 11. Anish made 42 runs in 6 overs and Anup made 63 runs in 7 overs. Who made more runs per over? Solution: In case of Anish: Runs made in 6 overs = 42 Runs made in 1 over = (426) = 7 In case of Anup: Runs made in 7 overs = 63 Runs made in 1 over = (637) = 9 Since 9 >7
∴ Anup made more runs per over.

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NCERT MOST IMPORTANT QUESTIONS CLASS – 12 | PSYCHOLOGY IMPORTANT QUESTIONS | CHAPTER-6 | ATTITUDE AND SOCIAL COGNITION | EDUGROWN |

In This Post we are  providing  CHAPTER 6 ATTITUDE AND SOCIAL COGNITION NCERT MOST IMPORTANT QUESTIONS for Class 12 PSYCHOLOGY which will be beneficial for students. These solutions are updated according to 2021-22 syllabus. These MCQS  can be really helpful in the preparation of Board exams and will provide you with a brief knowledge of the chapter

NCERT MOST IMPORTANT QUESTIONS ON ATTITUDE AND SOCIAL COGNITION

1.Define attitude. Discuss the components of an attitude.
Ans. Attitudes are state of the mind, set of views or thoughts or ideas regarding some topic which have an evaluative feature (positive, negative or neutral). These are relatively stable predispositions. .
Various components of an attitude are as follows:
(i)The thought component is referred to as the cognitive aspect of attitude.
(ii)The emotional component is known as the affective aspect.
(iii)The tendency to act is called the behavioural (conative) aspect.
These three aspects have been referred to as the A-B-C (affective-behavioural-cognitive)components of attitude. Attitudes are themselves not a tendency to behave or act in certain ways. They are part of cognition, along with an emotional component which cannot be observed from outside.

2.Are attitudes learnt? Explain how?
Ans. By enlarge attitudes are learnt. They are formed on the basis of learning.
Formation of Attitudes: The term ‘attitude formation’ refers to the movement we make from having no attitude toward an object to having a positive or negative attitude. There are some factors which contribute to the formation of attitudes:
1.Learning: The attitudes are acquired through learning. Many of our views are acquired in situations in which we interact with others or merely observe their behaviour.
-Classical Conditioning/Leaming by Association:
•A basic form of learning in which one stimulus, initially neutral, acquires the capacity to evoke reactions through repeated pairing with another stimulus.
•Player often develop a strong liking for the bat by which they made good runs. Many students start liking a subject if they like the teacher.
-Instrumental Conditioning/Leaming Altitude by Reward and Punishment: A basic form of learning in which responses that lead to positive outcomes or that permit avoidance of negative outcomes are strengthened.
•It applies to the situations when people learn attitudes which are systematically rewarded by significant others, such as parents, teachers or friends.
-Observational Learning: A basic form of learning in which individuals acquire new forms of behaviour or through observing others.
•Children are keen observers and learn a whole lot of things from their parents and other family members.
•They learn many attitudes about other ethnic groups, neighbours and idealize simply by observing the behaviours of adults.
2.Learning through Exposure to Information:
•Many attitudes are learnt in a social context without physical presence of others. Print media, electronic media, biographies of self-actualized people facilitate attitude formations.
3.Learning Attitudes through Group or Cultural Norms:
•Norms are unwritten rules of behaviour. Gradually these norms may become part of our social cognition, in the form of attitudes, e.g., offering money, sweets, fruits and flowers in a place of worship is a normative behaviour in various religions. People imitate such behaviour shown by others as socially approved and develop positive attitude towards it.

3.What are the factors that influence the formation of an attitude?
Ans. The following factors provide the context for the learning of attitude through various processes:
(i) Family and School Environment: parents and other family-members play a significant role in attitude formation. Learning of attitudes within the family and school usually takes place by association, through rewards and punishment and through modelling.
(ii)Reference Groups: Attitudes towards political, religious and social groups, occupations, national and other issues are often developed through reference groups. Reference groups indicate to an individual the norms regarding acceptable behaviour and ways of thinking. Various institutions, religion, culture and communities are form of reference groups.
(iii) Personal Experiences: Many attitudes are formed, not in the family environment or through reference groups, but through direct personal experiences which bring about a drastic change in our attitude towards people and our own life.
(iv) Media Related Influences: Technological advances have made audio-visual media and internet as very powerful sources for attitude formation. School textbooks also influence attitude formation. The media can be used to create consumerist attitude. The media can exert both good and bad influences on attitudes.

4. Is behaviour always a reflection of one’s attitude? Explain with a relevant example.
Ans. An individual’s attitude may not always be exhibited through behaviour. Likewise one’s actual behaviour may be contrary to one’s attitude towards a particular topic. Psychologists have found that there would be consistency between attitude and behaviour when:
(i)The attitude is strong and occupies a central place in the attitude system.
(ii)The person is aware of his/her attitudes.
(iii)Person’s behaviour is not being watched or evaluated by others.
(iv)Person thinks that the behaviour would have a positive consequences.
Richard La Piere, an American social psychologist, conducted the following study. He asked a Chinese couple to travel across the United States, and stay in different hotels. Only once during these occasions they were refused service by one of the hotels. La Piere sent out questionnaires to managers of hotels and tourist homes in the same areas where the Chinese couple had travelled asking them if they would give accommodation to Chinese guest. A very large percentage said that they would not do so. This response showed a negative attitude towards the Chinese, which was inconsistent with the positive behaviour that was actually shown towards the travelling Chinese couple. Attitudes may not always predict actual pattern of one’s behaviour.

5.Highlight the importance of schemas in social cognition.
Ans.•Social schemas (schemata) are mental structure.
•They function as a framework to process social information. These schemas lead to emergence of prototypes.
•Prototypes are concepts which have most of the defining features of a concept, class or family.
•These are best representatives of the population.
•Various stereotypes emerge from these schemas. In other words stereotypes are category-based schemas.

6. Differentiate between prejudice and stereotype.
Ans. Prejudices are negative attitude.
•These are bias about others.
•Prejudices are baseless and false.
•It refers to biased attitude formed about an individual or a group of people.
•These are usually negative.
•It has three components, i.e., A-B-C-
(a) Affective (Emotional i.e dislike or hatred).
(b)Behavioural (i.e., discrimination).
(c)Cognitive (Believes, i.e., stereotypes).
Stereotypes are cognitive component of prejudice. It is strongly influenced by the processing of incoming social information.
•These are over-generalized beliefs, e.g., girls are talkative.
•Stereotypes are category based schemas.
•These may be positive or negative or neutral.
•Stereotype has no emotional blending.
•From stereotypes, prejudices may emerge very easily.
•Stereotypes are usually formed for the groups.
•Stereotypes are pre conceived notions.

7. Prejudice can exist without discrimination and vice-versa. Comment.
Ans. Prejudices can exist without being shown in the form of discrimination. Similarly,
discrimination can be shown without prejudice.
•Wherever prejudice and discrimination exist, conflicts are very likely to arise between groups within the same society.
•We all witnessed many instances of discrimination, with and without prejudice, based on gender, religion, community, caste, physical handicap, and illnesses such as AIDS.
•Moreover, in many cases, discriminatory behaviour can be curbed by law. But, the cognitive and emotional components of prejudice are more difficult to change.

8. Describe the important factors that influence impression formation.
Ans. Impression formation is a process by which impression about others is converting into more or less induring cognitions or thoughts about them.In short, impression formation is a process through which we draw quick conclusion/ inferences regarding others.
Factors facilitating Impression Formation:
•Nature of the phenomena (familiar or unfamiliar).
•Personality traits of the perceiver.
•Social schemas stored in the mind of perceiver.
•Situational factors.
The process of impression formation consists of the following three sub-processes:
•Selection: We take into account only some bits of information about the target person.
•Organization: the selected information is combined in a systematic way.
•Inference: We draw a conclusion about what kind of person the target is.
Some specific qualities, that influence impression formation, are:
•The information presented first has a stronger effect than the information presented at the end. This is called the primacy effect.
•We have a tendency to think that a target person who has one set of positive qualities must also be having other specific positives that are associated with first set. This is known as halo effect, e.g., if we think that a person is ‘tidy’ then we are likely to think that this person must also be hard/working.
•Whatever information comes at the end may have a stronger influence on impression formation. This is known as the recency effect.

9.Explain how the attribution made by an ‘actor’ would be different from that of an ‘observer’.
Ans. Actor observer phenomena refers to the tendency to attribute our own behaviour mainly to situational causes but the behaviour of others mainly to internal (dispositional) cause.
A distinction is found between the attribution that a person makes for actorrole and observer-role.
Person makes attribution for his/her own positive and negative experiences, it is actor role and the attribution made for another person’s positive and negative experience is observer-role.
For example, if we get good marks, we will attribute it to our own ability and hard work (actor-role, internal attribution for a positive experience). If we get bad marks, we will say we were unlucky or test was difficult (actor-role, external attribution for negative experience).
On the other hand, if our classmate gets good marks, we will attribute his/her success to good luck or easy test (observer-role, external attribution for positive experience). If same classmate gets bad marks, we are likely to feel that his/her failure was because of low ability or due to lack of effort (observer-role, internal attribution for a negative experience).
The reason for the difference between the actor and observer roles is that people want to have a nice image of themselves, as compared to others.

10.How does social facilitation take place?
Ans. • It is form of group influence.
•Social facilitation refers to a concept that performance on specific task is influenced by the mere presence of others.
•Norman Triplett observed that individuals show better performance in presence of others, than when they are performing the same task alone.
Better performance in presence of others is because the person experiences arousal, which makes the person react in a more intense manner.
The arousal is because the person feels he or she is being evaluated. Cottrell called this idea evaluation apprehension. The person will be praised if performance is good (reward); is criticised if performance is bad (punishment). We wish to get praise and avoid criticism, therefore we try to perform well and avoid criticism.
As in case of complex task, the person may be afraid of making mistakes. And the fear of criticism or punishment is stronger.
If the others present are also performing same task, this is called a situation of co-action. When task is simple or a familiar one, performance is better under co-action than when the person is alone.
Task performing can be facilitated and improved or inhibited and worsened by the presence of others. If we are working together in a larger group, the less effort each member puts in. This phenomena is called social loafing, based on diffusion of responsibility. Diffusion of responsibility can also be frequently seen in situations where people are expected to help.

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Chapter-11 Algebra | Class 6th | NCERT Maths Solutions | Edugrown

NCERT Solutions for Class 6 Maths: One of the most important and interesting things to keep in mind is that these solutions available are totally free of cost. This also includes all the solutions to the exercises that are given in the textbook. NCERT solutions for class 6 maths gives you chapter-wise solutions to each and every question. This can help you solve even the tougher with ease.

It is always good to have a strong foundation in order to build a good building. This also is true in class when you are still learning the basics of maths. NCERT solutions for class 6 maths provides you the exact opportunity to build a strong foundation in this subject. Below is an overview of each and every chapter covered in the NCERT textbook.

NCERT Solutions for Class 6 Maths Chapter 11 Algebra

Ex 11.1 Class 6 Maths Question 1.
Find the rule, which gives the number of matchsticks required to make the following matchstick patterns. Use a variable to write the rule.
(a) A pattern of letter T as
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 1

(b) A pattern of letter Z as
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 2
(c)
 A pattern of letter U as
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 3
(d)
 A pattern of letter V as
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 4
(e) A pattern of letter E as
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 5
(f)
 A pattern of letter S as
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 6
(g)
 A pattern of letter A as
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 7
Solution:
(a) For T:
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 8
Clearly, to make one T, we use 2 matchsticks as shown in the figure. Rule is given as
“Number of matchsticks required = 2n”, where n can take any value 1, 2, 3, …
(b) For Z :
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 9
Clearly, to make one Z, we use 3 matchsticks as shown in the figure. Rule is given as
“Number of matchsticks required = 3 n”, where n can take any value 1, 2, 3, …
(c) For U :
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 10
Clearly, to make one U, we use 3 matchsticks as shown in the figure. Rule is given as
“Number of matchsticks required = 3n”, where rt can take any value 1, 2, 3, …
(d) For V :
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 11
Clearly, to make one V, we use 2 matchsticks as shown in the figure. Rule is given as
“Number of matchsticks required = 2n”, where n can take any value 1, 2,3,…
(e) For E :
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 12
Clearly, to make one E, we use 5 matchsticks as shown in the figure. Rule is given as
“Number of matchsticks required = 5n”, where n can take any value 1, 2, 3, …
(f) For S :
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 13
Clearly, to make one S, we use 5 matchsticks as shown in the figure. Rule is given as
“Number of matchsticks required = 5n”, where n can take any value 1, 2, 3, …
(g) For A :
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 14
Clearly, to make one A, we use 6 matchsticks as shown in the figure. Rule is given as
“Number of matchsticks required = 6 n”, where n can take any value 1, 2, 3, …

Ex 11.1 Class 6 Maths Question 2.
We already know the rule for the pattern of letters L, C and F. Some of the letters from Q. 1 (given above) give us the same rule as that given by L. Which are these? Why does this happen?
Solution:
(a) and (d) parts of Q. 1. give the same rule as for L. It happens as the same number of matchsticks are being used in these cases.

Ex 11.1 Class 6 Maths Question 3.
Cadets are marching in a parade. There are 5 cadets in a row. What is the rule, which gives the number of cadets, given the number of rows? (Use n for the number of rows.)
Solution:
Since, there are 5 cadets in a row and number of rows are n
∴ Rule is given as
Number of cadets in the parade = 5n

Ex 11.1 Class 6 Maths Question 4.
If there are 50 mangoes in a box, how will you write the total number of mangoes in terms of the number of boxes? (Use b for the number of boxes.)
Solution:
Since, there are 50 mangoes in a box and b is the number of boxes.
∴ Total number of mangoes = 50b

Ex 11.1 Class 6 Maths Question 5.
The teacher distributes 5 pencils per student. Can you tell how many pencils are needed, given the number of students? (Use s for the number of students.)
Solution:
Since, there are s number of students and each student having 5 pencils.
∴ Total number of pencils needed = 5n

Ex 11.1 Class 6 Maths Question 6.
A bird flies 1 kilometre in one minute. Can you express the distance covered by the bird in terms of its flying time in minutes? (Use t for flying time in minutes.)
Solution:
Since, a bird flies at 1 kilometre in one minute. If it flies for t minutes. Total distance covered by bird in t minutes = 1 x t km = t km

Ex 11.1 Class 6 Maths Question 7.
Radha is drawing a dot Rangoli (a beautiful pattern of lines joining dots with chalk powder. She has 9 dots in a row. How many dots will her Rangoli have for r rows? How many dots are there if there are 8 rows? If there are 10 rows?
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 15

Solution:
Since, a row contains 9 dots.
Therefore, number of dots in r rows = 9 r.
Number of dots in 8 rows = 9 x 8 = 72
and, number of dots in 10 rows = 9 x 10 = 90

Ex 11.1 Class 6 Maths Question 8.
Leela is Radha’s younger sister. Leela is 4 years younger than Radha. Can you write Leela’s age in terms of Radha’s age? Take Radha’s age to be x years.
Solution:
Let Radha’a age be x years. Since Radha’s younger sister Leela is 4 years younger than Radha.
∴ Leela’s age = (x – 4) year

Ex 11.1 Class 6 Maths Question 9.
Mother has made laddus. She gives some laddus to gilests and family members; still 5 laddus remain. If the number of laddus mother gave away is l, how many laddus did she make?
Solution:
Number of laddus given to guests and family members = l
Number of laddus left over = 5
Number of laddus made by mother = 1 + 5

Ex 11.1 Class 6 Maths Question 10.
Oranges are to be transferred from larger boxes into smaller boxes. When a large box is emptied, the oranges from it fill two smaller boxes and still 10 oranges remain outside. If the number of oranges in a small box are taken to be x, what is the number of oranges in the larger box?
Solution:
Number of oranges in the larger box
= 2 x Number of oranges iR small box + oranges left over
= 2x +10
where x is. the number of oranges in the small box.

Ex 11.1 Class 6 Maths Question 11.
(a) Look at the following matchstick pattern of squares (see figure). The squares are not separate. Two neighbouring squares have a common matchstick. Observe the pattern and find the rule that gives the number of matchsticks in terms of the number of squares.
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 16
(b)
 Figure gives a matchstick pattern of triangles. As in Exercise 11(a) above, find the general rule that gives the number of matchsticks in terms of the number of triangles.
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 17
Solution:
(a) Clearly, from the figure:
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 18
Thus, rule is as under:
Number of matchsticks = 3x +1, where x is the number of squares,
(b) Clearly, from the figure :
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 19
Thus, rule is as under: ,
Number of matchsticks = 2x +1, where x is the number of triangles.

Ex 11.2 Class 6 Maths Question 1.
The side of an equilateral triangle is shown by l. Express the perimeter of the equilateral triangle using l.
Solution:
If P represents the perimeter of an equilateral triangle of side l, then P = l + l + l= 3 x l

Ex 11.2 Class 6 Maths Question 2.
The side of a regular hexagon (see figure) is denoted by l. Express the perimeter of the hexagon using l.
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 20

Solution:
If P represents the perimeter of a regular hexagon of side l, then P = l + l + l + l + l + l = 6 x l.

Ex 11.2 Class 6 Maths Question 3.
A cube is a three-dimensional figure as shown in figure. It has six faces and all of them are identical squares. The length of an edge of the cube is given by l. Find the formula for the total length of the edges of a cube.
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 21
Solution:
Since all the 12 edges of a cube are of same length, l. Then, their total length = 12 x l.

Ex 11.2 Class 6 Maths Question 4.
The diameter of a circle is a line, which joins two points on the circle and also passes through the centre of the circle. (In the adjoining figure AB is a diameter of the circle;
C is its centre). Express the diameter of the circle (d) in terms of its radius (r).
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 22
Solution:
Diameter AB = AC + CB
If d represents the diameter of the circle and r is the radius of circle, then
d = CP + CP [∵ CP = r]
d = r + r = 2r

Ex 11.2 Class 6 Maths Question 5.
To find sum of three numbers 14, 27 and 13, we can have two ways.
(a) We may first add 14 and 27 to get 41 and then add 13 to it to get the total sum 54 or
(b) We may add 27 and 13 to get 40 and then add 14 to get the sum 54.
Thus, (14 + 27) + 13 = 14 + (27 + 13).
This can be done for any three numbers. This property is known as the associativity of addition of numbers. Express this property which we have already studied in the chapter on Whole Numbers, in a general way, by using variables a, b and c.
Solution:
The given properly is stated as
For 3 variables a, b and c, we have
(a + b) + c = a + (b + c)

Ex 11.3 Class 6 Maths Question 1.
Make up as many expressions with numbers (no variables) as you can from three numbers 5, 7 and 8. Every number should be used not more than once. Use only addition, subtraction and multiplication.
Solution:
Some possible expressions using three numbers 5, 7 and 8 are
(i) 5 + (8 – 7)
(ii) 5 -(8 – 7)
(iii) 5 +(8 + 7)
(iv) (5 + 8)+ 7
(v) 5 x 8 + 7
(vi) 5 x 7 + 8
(vii) 5 x 8 – 7
(viii) 5 x 7 – 8
(ix) 5 x (8 – 7)
(x) 5 x (8 + 7)
(xi) 8 x (7 – 5)
(xii) 8 x (7 + 5) etc.

Ex 11.3 Class 6 Maths Question 2.
Which out of the following are expressions with numbers only?
(a) y + 3
(b) (7 x 20) – 8z
(c) 5(21 – 7) + 7 x 2
(d) 5
(e) 3x
(f) 5 – 5n
(g) (7 x 20) (5 x 10) – 45 + p
Solution:
(c) and (d) are expressions with numbers only.

Ex 11.3 Class 6 Maths Question 3.
Identify the operations (addition, subtraction, division, multiplication) in forming the following expressions and tell how the expressions have been formed:
(a) z +1, z – 1 y +17, y -17
(b) 17y, y17, 5z
(c) 2y +17, 2y -17
(d) 7m, -7m + 3, -7m – 3
Solution:
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 23

Ex 11.3 Class 6 Maths Question 4.
Give expressions for the following cases:
(a) 7 added to p
(b) 7 subtracted from p
(c) p multiplied by 7
(d) p divided by 7
(e) 7 subtracted from -m
(f) -p multiplied by 5
(g) -p divided by 5
(h) p multiplied by -5
Solution:
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 24

Ex 11.3 Class 6 Maths Question 5.
Give expressions in the following cases:
(a) 11 added to 2m
(b) 11 subtracted from 2m
(c) 5 times y to which 3 is added
(d) 5 times y from which 3 is subtracted
(e) y is multiplied by -8
(f) y is multiplied by -8 and then 5 is added to the result
(g) y is multiplied by 5 and the result is subtracted from 16
(h) y is multiplied by -5 and the result is added to 16
Solution:
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 25

Ex 11.3 Class 6 Maths Question 6.
(a) Form expressions using t and 4. Use not more than one number operation. Every expression must have t in it.
(b) Form expressions using y, 2 and 7. Every expression must have y in it. Use only two number operations. These should be different.
Solution:
(a) Possible expressions using t and 4 are
t + 4, t – 4, 4t and t4.
(b) Possible expressions using y, 2 and 7 (having only two different number operations) are
2y + 7, 2y – 7, 7y + 2, 7y – 2, y2 + 7, y2 – 7, y7+2 and y7 – 2.

Ex 11.4 Class 6 Maths Question 1.
Answer the following:
(a) Take Sarita’s present age to be y years

  • What will be her age 5 years from now?
  • What was her age 3 years back?
  • Sarita’s grandfather is 6 times her age. What is the age of her grandfather?
  • Grandmother is 2 years younger than grandfather. What is grandmother’s age?
  • Sarita’s father’s age is 5 years more than 3 times Sarita’s age. What is her father’s age?

(b) The length of a rectangular hall is 4 metres less than 3 times the breadth of the hall. What is the length, if the breadth is b metres?
(c) A rectangular box has height h cm. Its length is 5 times the height and breadth is 10 cm less than the length. Express the length and the breadth of the box in terms of the height.
(d) Meena, Beena and Leena are climbing the steps io the hill top. Meena is at step s, Beena is 8 steps ahead and Leena 7 steps behind. Where are Beena and Meena? The total number of steps to the hill top is 10 less than 4 times what Meena has reached. Express the total number of steps using s.
(e) A bus travels at v km per hour. It is going from L>aspur to Beespur. After the bus has travelled 5 hours, Beespuris still 20 km away. What is the distance from Daspur to Beespur? Express it using v.
Solution:
(a) Let Santa’s present age be y years.

  • Her age 5 years from now = (y + 5) years.
  • Her age 3 years back = (y – 3) years.
  • Since Sarita’s grandfather’s age is 6 times that of Sarita’s age.
    ∴ Her grandfather’s age = 6y years.
  • Since grandmother is 2 years younger than grandfather. Therefore,
    Grandmother’s age = (6 y – 2) years.
  • Since Sarita’s father’s age is 5 years more than 3 times Sarita’s age.
    Therefore, her father’s age = (3y + 5) years.

(b) Let the breadth of the hall be b metres
Since its length is 4 metres less than 3 times the breadth of the hall.
∴ Length of the hall = (3b – 4) metres
(c) Let the height of the rectangular box = h cm
It is given that its length is 5 times the height and breadth is 10 cm less than the length. Therefore,
Its length = 5h cm
and, breadth = (5h-10) cm
(d) Let Meena be at step s while climbing the steps to the hill top.
Since Beena is 8 steps ahead and Leena 7 steps behind Meena.
∴ Beena is at step (s + 8) and Leena is at step (s – 7)
Also, the total number of steps to the hill top is 10 less than 4 times what Meena has reached. .
∴ Total number of steps to the hill top = 4s-10
(e) Speed of the bus = v km per hour
Distance travelled by the bus in 5 hours = 5v km
According to question,
Distance from Daspur to Beespur
= Distance travelled by bus in 5 hours +20 km
= 5km +20 km = (5v +20) km.

Ex 11.4 Class 6 Maths Question 2.
Change the following statements using expressions into statements in ordinary language.
(For example, Given Salim scores r runs in a cricket match, Nalin scores (r +15) runs. In ordinary language-Nalin scores 15 runs more than Salim.)
(a) A notebook costs ₹ p.A book costs ₹ 3p.
(b) Tony puts q marbles on the table. He has 8 q marbles in his box.
(c) Our class has n students. The school has 20n students.
(d) Jaggu is z years old. His uncle is 4z years old and his aunt is (4z – 3) years old.
(e) In an arrangement of dots there are r rows. Each row contains 5 dots.
Solution:
(a) A book costs 3 times the cost of a notebook.
(b) Tony’s box contains 8 times the marbles on the table.
(c) Total number of students in the school is 20 times that of our class.
(d) Jaggu’s uncle is 4 times older than Jaggu and Jaggu’s aunt is 3 years younger than his uncle.
(e) The number of dots in a row is 5 times the number of rows.

Ex 11.4 Class 6 Maths Question 3.
(a) Given, Munnu’s age %p be x years, can you guess what (x – 2) may show?
Can you guess what (x + 4) may show? What (3x + 7) may show?
(b) Given Sara’s age today to be y years. Think of her age in the future or in the past. What will the following expression indicate?
y + 7, y-3, y + 412, y – 212.
(c) Given n students in the class like football, what may 2n show? What may n2 show?
Solution:
(a) (x – 2) may show the age of his younger sister.
(x + 4) may show the age of his elder brother.
(3x + 7) may show the age of his grandfather.
(b) The expressions (y + 7), (y + 412) may indicate Sara’s age in future.
The expressions (y – 3), (y – 212) may indicate Sara’s past age.
(c) The expression 2n may show the number of students who like hockey. The expression n2 may show the number of students who like basketball.

Ex 11.5 Class 6 Maths Question 1.
State which of the following are equations (with a variable). Give reason for your answer. Identify the variable from the equations with a variable.
(a) 17 = x + 7
(b) (t – 7) > 5
(c) 42 = 2
(d) 7 x 3 – 19 = 8
(e) 5 x 4 – 8 = 2x
(f) x – 2 = 0
(g) 2m < 30
(h) 2n + 1 = 11
(i) 7 = (11 x 5) – (12 x 4)
(j) 7 = 11 x 2 + p
(k) 20 = 5y
(l) 3q2 < 5
(m) z + 12 > 24
(n) 20 – (10 – 5) = 3 x 5
(o) 7 – x = 5
Solution:
(a) An equation, equation with variable (x).
(b) Not an equation (as have no = sign).
(c) An equation, equation with numbers.
(d) An equation, equation with numbers.
(e) An equation, equation with variable (x).
(f) An equation, equation with variable (x).
(g) Not an equation (as have no = sign).
(h) An equation, equation with variable (n).
(i) An equation, equation with numbers.
(j) An equation, equation with variable (p).
(k) An equation, equation with variable (y).
(l) Not an equation (as have no = sign).
(m) Not an equation (as have no = sign),
(n) An equation, equation with numbers.
(o) An equation, equation with variable (x).

Ex 11.5 Class 6 Maths Question 2.
Complete the entries in the third column of the table.
Solution:
The table duly completed is as under :
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 26

Ex 11.5 Class 6 Maths Question 3.
Pick out the solution from the values given in the bracket next to each equation. Show that the other values do not satisfy the equation.
(a) 5m = 60 (10, 5, 12, 15)
(b) n + 12 = 20 (12, 8, 20, 0)
(c) p – 5 = 5 (7, 2, 10, 14)
(d) q2 = 7 (4, -2, 8, 0)
(e) r – 4 = 0 (4, -4, 8, 0)
(f) x + 4 = 2 (-2, 0, 2, 4)
Solution:
(a) Given equation is 5m = 60.
For m=10: 5m = 5 x 10 = 50 ≠ 60. So, m=10 does not satisfy the given equation.
For m = 5 5m = 5 x 5 = 25 ≠ 60. So, m = 5 does not satisfy the given equation.
For m=12: 5m = 5 x 12 = 60. So, m=12 does not satisfy the given equation.
Thus, n = 12 is its solution.
For m = 15 5m = 5 x 15 = 75 ≠ 60. So, m = 15 does not satisfy the given equation.

(b) Given equation is n +12 = 20.
For n=12: n +12 = 12 + 12 = 24 ≠ 20. So, n = 12 does not satisfy the the given equation.
For n = 8: n +12 = 8 + 12 = 20. So, n = 8 satisfies the given equation.
Thus, n = 8 is its solution.
For n = 20: n + 12 = 20 + 12 = 32 ≠ 20. So, n = 20 does not satisfy the given equation.
For n = 0: n + 12 = 0 + 12 = 12 ≠ 20. So, n = 0 does not satisfy the given equation.

(c) Given equation is p – 5 = 5.
For p = 0: p – 5 = 0 – 5 = -5 ≠ 5. So, p = 0 does not satisfy the given equation.
For p = 10: p – 5 = 10 – 5 = 5. So, p = 10 satisfies the given equation.
Thus, its solution is p = 10.
For p = 5: p – 5 = 5 – 5 = 0≠ 5. So, p = 5 does not satisfy the given equation.
For p = -5: p – 5 = -5 – 5 = -10 ≠ 5. So, p = -5 does not satisfy the given equation.

(d) Given equation is q2 = 7.
For q = 7: q2 = 72 ≠ 7. So, q = 7 does not satisfy the given equation.
For q = 2: q2 = 22 = 1 ≠ 7. So, q = 2 does not satisfy the given equation.
For q = 10: q2 = 102 = 5 ≠ 7. So, q = 10 does not satisfy the given equation.
For q = 14: q2 = 142 = 7. So, q = 14 satisfies the given equation. Thus, q = 14 is its solution.

(e) Given equation is r – 4 = 0.
For r = 4: r – 4 = 4 – 4 = 0. So, r = 4 satisfies the given equation. Thus, r = 4 is its solution.
For r = -4: r – 4 = -4 – 4 = 8 ≠ 0. So, r = -4 does not satisfy the given equation.
For r = 8: r – 4 = 8 – 4 = 4 ≠ 0. So, r-8 does not satisfy the given equation.
For r = 0: r – 4 = 0 – 4 = -4 ≠ 0. So, r = 0 does hot satisfy thh given equation.

(f) Given equation is x + 4 = 2.
For x = -2: x + 4 = -2 + 4 = 2. So, x = -2 satisfies the given equation.
Thus, x = -2 is its solution.
For x = 0: x + 4 = 0 + 4 = 4 ≠ 2. So,- x =0 does not satisfy the given equation.
For x=2: x + 4= 2 + 4= 6 ≠ 2. So, x = 2 does not satisfy the given equation.
For x = 4: x + 4 = 4 + 4= 8 ≠ 2. So, x = 4 does not satisfy the given equation.

Ex 11.5 Class 6 Maths Question 4.
Question (a)
Complete the table and by inspection of the table find the solution to the equation m +10 = 16.
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 27
Solution:
Completing the table, we have
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 28
By inspection of the above table, we find that m = 6 satisfies the equation m+10 = 16. So, m = 6 is its solution.

Question (b)
Complete the table and by inspection of the table find the solution to the equation 51 = 35.
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 29
Solution:
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 30
By inspection of the above table, we find that t = 7 satisfies the equation 5t = 35. So, t = 7 is its solution.

Question (c)
Complete the table and find the solution of the equation z3 = 4 using the table.
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 31
Solution:
Completing the table, we have
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 32
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 32
By inspection of the above table, we find that t=12 satisfies the equation z3 = 4. So, t = 12 is its solution.

Question (d)
Complete the table and find the solution to .the equation m – 7 = 3.
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 34
Solution:
Completing the table, we have
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 35
By inspection of the above table, we find that m = 10 satisfies the equation m – 7 = 3. So, m = 10 is its solution.

Ex 11.5 Class 6 Maths Question 5.
Solve the following riddles, you may yourself construct such riddles.
Who am I?
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 36
(i)
 Go round a square
Counting every comer Thrice and no more!
Add the count to me
To get exactly thirty four!
(ii) For each day of the week
Make an upcount from me
If you make no mistake
You will get twenty three!
(iii) I am a special number
Take away from me a six!
A whole cricket team
You will still be able to fix!
(iv) Tell me who I am
I shall give a pretty clue!
You will get me hack
If you take me out of twenty two!
Solution:
(i) Let I be denoted by x. There are 4 comers of a square.
On counting each comer thrice, we get 3 x 4 = 12
As per problem:
x + 12 = 34 ⇒ x +12 – 12 = 34 – 12
⇒ x + 0 = 22 ⇒ x = 22
Thus, I am 22.

(ii) According to the question:
x + 7 =23
x + 7 – 7 = 23 – 7
⇒ x + 0 =16 ⇒ x =16

(iii) Let the special number be x. Then, according to the problem, we have
x – 6 = 11 [ In a cricket team, no. of players =11]
⇒ x – 6 + 6 = 11 + 6
⇒ x + 0 = 17 ⇒ x = 17
Thus, the special number is 17.

(iv) Let I be denoted by x.
According to the question:
22 – x = x
⇒ 22 – x + x = x + x
⇒ 22 + 0 =2x
⇒ 2x = 22 ⇒ 2x2=222
⇒ x =11
Thus, I am 11.

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NCERT MOST IMPORTANT QUESTIONS CLASS – 12 | PSYCHOLOGY IMPORTANT QUESTIONS | CHAPTER-1 | INTELLIGENCE AND APTITUDE | EDUGROWN |

In This Post we are  providing  CHAPTER 1 INTELLIGENCE AND APTITUDE NCERT MOST IMPORTANT QUESTIONS for Class 12 PSYCHOLOGY which will be beneficial for students. These solutions are updated according to 2021-22 syllabus. These MCQS  can be really helpful in the preparation of Board exams and will provide you with a brief knowledge of the chapter

NCERT MOST IMPORTANT QUESTIONS ON INTELLIGENCE AND APTITUDE

1. How do psychologists characterize and define intelligence?
Ans. Psychological motion of intelligence is quite different from the common sensed motion of intelligence.
Generally people saw intelligence as mental alertness, ready art, quickness in learning and ability to understand relationships.
Oxford dictionary explained intelligence as the power of perceiving, learning understanding and knowing.
Accordingly Alfred Binet also used these attributes and defined intelligence as ability to judge well, understand well and reason well.Later Wechsler gave a comprehensive definition in terms of its functionality, i.e., its value for adaptation to environment. He defined intelligence as “the global and aggregate capacity of an individual to think rationally, act purposefully and to deal effectively with his/her environment.”
Present day psychologists such as Gardner and Sternberg emphasized that “Intelligent individual not only adapts to the environment, but actively modifies or shapes it.”
Sternberg views intelligence as “ the ability to adapt, to shape and select environment to accomplish ones goals and those of ones society and culture.”

2.What extent is our intelligence the result of heredity (nature) and environment (nurture)? Discuss.
Ans. (i) Whether intelligence is evolved or it is developed due to the environment, is a question of debate.
(ii)Lot of studies have been done to determine the role of nature and nurture.
(iii)Here we will discuss the controversy with the help of various twin studies, adoption studies and environmental studies.
On the basis of twin studies co-relation results are as follows:
(i)Identical twins reared together correlate 0.90
(ii)Identical twins reported early in childhood and reared in different environments correlate 0.72
(iii)Fraternal twins reared together correlate 0.60
(iv)Siblings reared together correlate 0.50
(v) Siblings reared apart correlate 0.25
•Adoption Studies before the Age of 6-7 Years
These studies of adopted children show that children’s intelligence is more similar to their biological parents.
These studies provide evidence that intelligence is determined because of nature.
•Adoption Studies after the Age of 6-7 Years
According to these studies as children grew older tends to more closer to that of their adoptive parents.
Environmental Studies
Evidence for the influence of environment (Nurture) on the basis of Twin studies.
(i) The intelligence score of twins reared apart as they grew older, tends to more closer to that of their adoptive parents.
(ii)On the basis of differences in environment, children from disadvantaged homes adopted into families with higher, socio-economic status exhibit an increase in their intelligence scores.
(iii)Environmental deprivation lowers intelligence. Factors such as nutrition, good family background and quality schooling increase growth rate of intelligence.
(iv)There is general consensus among psychologists that intelligence is a product of complex interaction of heredity (Nature) and environment (Nurture).
(v)Heredity provides the potentials and sets a range of growth whereas environment facilitates the development of intelligence.

3. Explain briefly the multiple intelligences identified by Gardner.
Ans. Gardner’s theory based on information processing approaches functions on three basic principles:
(i)Intelligence is not a single entity, there exist multiple intelligences.
(ii)The intelligences are independent from each other.
(iii)Different types of intelligences work together to provide a solution of problem. Gardner has so far proposed eight intelligences, however all individuals do not possess them in equal proportion. The particular situation or the context decides the prominence of one type of intelligence over the others.
Following are the eight types of intelligence:
1.Linguistic: This is related to reading, writing, listening, talking, understanding etc. Poets exhibit this ability better than others.
2.Logical-Mathematical: This type of intelligence deals with abstract reasoning and manipulation of symbols involved in numerical problems. It is exhibited in scientific work.
3.Spatial: This type of intelligence is involved in perceiving third dimension formation of images. It is used while navigating in space, forming, transforming and using mental images. Sailors, engineers, surgeons, pilots, care drivers, sculptors and painters have highly developed spatial intelligence.
4.Musical: Persons with musical intelligence show sensitivity to pitch and tone required for singing, playing and instrument, composing and appreciating music etc.
5.Bodily Kinesthetic: It requires the skills and dexterity for fine coordinated motor movements, such as those required for dancing, athletics, surgery, craft making etc.
6.Inter-personal: It requires understanding of motives, feelings and behaviours of other people.sales people, politicians, teachers, clinicians and religious readers have high degree of inter-personal intelligence.
7. Intra-personal: It is related to understanding one’s self and developing a sense of identity, e.g., philosophers and spiritual leaders.
8.Naturalistic: It is related to recognizing the flora and fauna, i.e., natural world and making a distinction in the natural world. It is more possessed by hunters, farmers, tourists, students of biological sciences etc.

4. How does the Triarchic theory help us to understand intelligence?
Ans. 1. Robert J. Sternberg proposes a theory of intelligence based on information
processing approach in 1985 known as the Triarchic theory of intelligence.
2. According to Sternberg, intelligence is an ability to adapt, to shape and select environment to accomplish ones goals and those of ones society and culture.
3. This theory attempts to understand the cognitive processes involved in problem solving.
4. According to him there are three types of intelligences:
(i)Componential intelligence (Analytical): This dimension specifies the cognitive processes that underlie an intelligent behaviour.
This dimension serves three different functions:
(a)Knowledge acquisition components: These are the processes used in learning, encoding, combining and comparing information.
(b)Metacomponents: ‘Meta’ means higher. These are executive processes. They control monitor and evaluate cognitive processing.
(c)Performance components: These components execute strategies prepared by metacomponents to perform a task.For example, While studying students plan the lesson chapterwise, they make
schedules, categories the learning material and do integrate the information to comprehend well.
(ii)Experiential intelligence (Creative): This dimension specifies how experiences effect intelligence and how intelligence effects a person’s experiences.
(а)Experiential intelligence refers to an individual’s ability to make use of one’s past experiences to deal with novel situations creatively and effectively.
(b)This intelligence is mostly high among scientists and creative people.
(c) For example if a person is trapped in a room, he finds out a way of coming out of the room using rope or ladder etc. in a creative way. He had some knowledge of getting out from this situation by watching out a movie few years back.
(iii)Contextual intelligence (Practical): This dimension specifies the ability to deal with environmental demands on daily basis.
(a)It is individual’s ability to make use of his/her potential to deal with day-to-day life.
(b)It may be called street smartness or ‘business sense’.
(c)People high in this ability are successful in life.
•It deals with the ways people handle effectively their environmental demands and adapt to different contexts with available resources

5. Any intellectual activity involves the independent functioning of three ‘neurological systems’. Explain with reference to PASS model.
Ans. According to PASS model, theory based on information processing approach, intellectual activity involves the interdependent functioning of the three neurological systems called the functional units of the brain.
These units are responsible for:
•the arousal and attention. • the simultaneous and successive processing.
•the planning.
Arousal and Attention
(i)State of arousal helps in attending to the stimuli.
(ii)Arousal and attention enable a person to process information.
(iii)Optimal level of arousal focuses our attention on relevant aspects of a problem.
(iv)Too much or too little arousal interferes with attention and performance. Example: Arousal helps the individual to focus ones attention on reading, learning and revising the contents of the material to be learnt.
Simultaneous and Successive Processing:
Simultaneous Processing refers to perceiving relations amongst various concepts and integrate them into meaningful patterns for comprehension!
For e.g., in Raven’s standard progressive matrices (RSPM Test) choosing appropriate pattern by comprehending relationship.
Successive Processing refers to recalling information serially so that one recall leads to another recall. For example, learning of digits and letters and multiplication tables.
Planning:
1.After the information is attended to and processed, planning is activated.
2.Planning involves reaching to the target and evaluating their effectiveness. Planning allows us to think of possible courses of action and implementing them.
3.If a plan does not work, it is modified to suit the requirements of the task or the situation.
4.For example, to take a test scheduled by your teacher, you’d have to set goals, plan a time schedule of studies, get clarifications in case of problems or think of other ways to meet your goals.

6. Are there cultural differences in the conceptualisation of intelligence?
Ans. Yes, culture, which is a set of beliefs, customs, attitudes and achievements in art of literature, affects the process of intellectual development.
•According to Sternberg, intelligence is a product of culture.
•Vyotsky believes that while elementary7 mental operations are common, higher mental activities like problem-solving and thinking are culturally produced.
•Technological Intelligence
(i)Promotes an individualistic pattern of action.
(ii)Individuals in technologically educated western societies possess this kind of intelligence.
(iii)They are well versed in skills of attention, observation, analysis, speed, moves abstraction, generalisation, creativity, Minimum moves etc.
•Integral Intelligence
(i)Intelligence in the Indian tradition is integral intelligence.
(ii)It views intelligence from a holistic perspective.
(iii)It gives equal attention to cognitive and non-cognitive processes, as well as their integration.
(iv)‘Buddhi’ is the knowledge of one’s own self based on conscience, will and desire.
(v)It has effective, motivational as well as cognitive components. .
It includes:
(i)Cognitive competence (discrimination, problem-solving).
(ii)Social competence (respect for elders, concern for others, respecting opinions of others).
(iii)Emotional competence (self regulation, self monitoring). ‘
(iv)Entrepreneurial competence commitment, persistence, patience).

7. What is IQ? How do psychologists classify people on the bases of their IQ scores?
Ans.(i)IQ is an index of brightness.
(ii)It is the ratio of mental age to chronological age.
(iii)The concept of IQ was given by William. Stern w7ho gave the formula to calculate IQ i.e.,
NCERT Solutions for Class 12 Psychology Chapter 1 Intelligence And Aptitude Q7
•IQ is relatively stable.
•It is a good predictor of potential.
•IQ scores are distributed in a population in such a way that most people tend to fall in the middle range of the distribution.
•This can be shown in the form of following table.
NCERT Solutions for Class 12 Psychology Chapter 1 Intelligence And Aptitude Q7.1

8.Discuss various types of intelligence tests.
Or
How can you differentiate between verbal and performance tests of intelligence?

Ans. Types of Intelligence Tests:
Individual or group tests based on contact: .
Individual Test:
(i)Administered to one individual at a time.
(ii)Requires the administrator to establish a rapport with the subject and be sensitive to his/her feelings, mood and expressions during the testing sessions which provides understanding of other aspects of subjects personality.
(iii)Allows people to answer orally or in written form or manipulate the objects as per the tester’s instructions.
• Example: Stanford Binet intelligence scale, WAIS, WISSC, Alexander Pass along test.
Group Test:
(i)Administered to several individuals at a time simultaneously.
(ii)Do not allow an opportunity to be familiar with the subjects’ feelings.
(iii)Seek answers in a Multiple-choice format.
(iv)It is relatively economical and less time consuming.
(v)Example: Group Test of Intelligence by Prayag Mehta, Group Test on Intelligence by S. Jalota.
Verbal, Non-verbal and Performance Tests based on Mode of Administration: Verbal Tests:
(i)Requires subject to give verbal responses either orally or in written form.
(ii)Can be administered to literates only. ,
(iii)Example: CIE, Verbal Group Test, Stanford Binet Intelligence Scale.
Non-verbal Test:
• Has pictures or illustrations as test items.
•Example: Ravens progressive matrices. In this test the subject examines an incomplete pattern and chooses a figure from the alternatives that will complete the pattern.
•Reduces culture biases.
•Example: SRPM, CIE Non-verbal group test of Intelligence.
Performance Test:
•Requires the subject to manipulate objects to perform the test.
•Written language is not necessary for answering the items.
•Example: Kohs’s Block designs test. Here the subject is asked to arrange the blocks in a specified period to produce a given design, Bhatia’s Battery performance test.
•Can be administered to persons from different cultures and reduce culture biases.
•Example: Draw a Man Test by Pramila Pathak, Kohs Block designs test.
Culture Biased or Culture Fair Tests based on Nature of Items used:
•Psychological tests that show a bias toward the culture in which they are developed are Culture Biased Tests.
•Tests developed-in-America and Europe represent an urban and middle class cultural ethos. (Middle class white subjects perform well on these tests). The items do not consider favourably to Asians and Africans.
•Culture Fair Tests: One does not discriminate against as individuals belong to different cultures.
•Non-verbal and Performance Tests reduce cultural influences.
To overcome the limitation of Culture biased tests, Culture fair tests were developed, e.g. non-verbal and performance tests are called so because people of any culture could take them. For e.g. Standard progressive Matrices and Bhatia’s Battery Performance Test.

9. Discuss how interplay of Nature and Nurture influences intelligence.
Or
All persons do not have the same intellectual capacity. How do individuals vary in their intellectual ability? Explain.
Ans. All persons do not have the same intellectual capacity. They vary in their intellectual ability. Some are exceptionally bright and some are below average. Some possess high IQ range while others have average or below average.
All the scores gradually and symmetrically decline towards both the sides but never touch the X-axis.
(i) The frequency distribution for the IQ scores tends to approximate a bell-shaped curve, called the normal curve. This type of distribution is symmetrical around the central value, called the mean.
(ii) On the basis of IQ, people are classified in different groups. It is clear that only 2.2 percent people who possess above 130 IQ range are very intelligent or very superior, their IQ score is more than 130.
(iii) People falling between 90-109 IQ range are considered as average. The mean IQ score in a population is 100. People with IQ scores in the range of 90-110 have normal intelligence.
(iv) Those with IQ below 70 are suspected to have ‘mental retardation’. Mental retardation refers to sub-average intellectual functioning. The behaviour is maladaptive and manifest in four forms i.e., mild, moderate, severe and profound mental retardation.
The extreme right also lie to 2.2 percent population which are known as gifted i.e., they enjoy exceptional intelligence, exceptional talent and exceptional creativity.
NCERT Solutions for Class 12 Psychology Chapter 1 Intelligence And Aptitude Q9

10.Which of the two lQ or EQ, do you think would be more related to success in life and Why?
Ans. (i) IQ is a good predictor of potential.
(ii) EQ is a good predictor of success.
-Researchers had proved that—EQ helps in dealing with students who are stressed and face challenges of the outside world.
-It improves the academic performance.
-It is very useful in preparing students to face the challenges of life outside the classroom.
-They are less anti-social and more co-operative.

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NCERT MOST IMPORTANT QUESTIONS CLASS – 12 | PSYCHOLOGY IMPORTANT QUESTIONS | CHAPTER-2 | SELF AND PERSONALITY | EDUGROWN |

In This Post we are  providing  CHAPTER 5 SELF AND PERSONALITY NCERT MOST IMPORTANT QUESTIONS for Class 12 PSYCHOLOGY which will be beneficial for students. These solutions are updated according to 2021-22 syllabus. These MCQS  can be really helpful in the preparation of Board exams and will provide you with a brief knowledge of the chapter

NCERT MOST IMPORTANT QUESTIONS ON SELF AND PERSONALITY

1.What is self? How does the Indian notion of self differ from the Western notion?
Ans. Self is an organized cognitive structure. It can be understood in terms of subject and object or I and Me. It refers to the totality of one’s conscious thoughts, and feelings which pertain to one’s own self. .
Indian Concept of Self
•Self is characterized by the shifting nature of the boundaries.
•The Indian view does not make rigid dichotomies.
•It is based on collectivistic Indian society.
Western Concept of Self
•The boundaries between self and the group are rigid.
•It holds clear dichotomies between self and group.
•It is based on individualistic society of the West.

2. What is meant by delay of gratification? Why is it considered important for adult development?
Ans. (i) Learning to delay or defer from gratification of needs is called self-control. It emerges from self-regulation.
(ii)Self-regulation is behavioural component of self.
(iii)It refers to an ability to organize and monitor ones own behaviour. People who can change their behaviour according to the demands of the external environment are high on self-monitoring.
(iv)Self-regulation leads to self-control.
(v)It plays a key role in fulfilment of long-term goals.
(vi)Indian culture provides us effective mechanisms like fasting (vrata or roza) and non-attachment with worldly things to develop self-control.
(vii)It is ones ability to say ‘No’.
Psychological techniques to develop self-control are:
(a)Observation of Own Behaviour: it provides us with necessary information that may be used to change, modify, or strengthen certain concepts of self. ‘
(b)Self-instruction: We often instruct ourselves to do something and behave the way we want.
(c)Self-reinforcement: It involves rewarding behaviours that have pleasant outcomes (like going to see a-movie with friends if we do well in exams).
— Self-control is important for the development of mature personality. This is the reason that all cultures emphasise the self-control. It helps in the fulfilment of long-term goals. Indian cultural tradition provide us with certain effective mechanisms, e.g., fasting in varta or roja and know attachment with worldly things for developing self-control.
— Self-control is also important for effective functioning of social network.

3. How do you define personality? What are the main approaches to the study of personality?
Ans. The word ‘personality’ is derived from the Latin word ‘persona’, which means a mask or false face which Greek actors used to wear when acting on stage. According to Gordon Allport “Personality is the dynamic organization within the individual of those psychological systems thqt determine his unique adjustments to his environment.”
One of the major approaches to understanding personality was to develop theories on what it was. There are many broad personality theories, which can be grouped into four categories: –
(i)Dynamic approaches, which emphasize on-going interaction among motives, impulses and psychological processes.
(ii)Type and train approaches, which focus on people’s characteristics, stubbornness, shyness and so forth and how these characteristics are organized into systems.
(iii)Humanistic approaches, which emphasize the self and the importance of the individual’s subjective view of the world.
(iv) Learning and behavioural approaches, which emphasize the way habits are acquired through basic learning process.

4. What is trait approach to personality? How does it differ from type approach?
Ans. Trait approach psychologists explain personality on the basis of specific psychological characteristics.
Type approach psychologists believe that personality can be classified into broad categories.
Traits are relatively stable, persistent and characteristic patterns of behaviour which makes the individual different from others.
(i)These are overlapping, i.e., inclusive in nature.
(ii)Traits are specific psychological characteristics, e.g., shy or timid.
Types are cluster of similar traits.
(i)These are broad categories. .
(ii)These do not overlap, i.e., exclusive in nature, e.g., extrovert or introvert.

5. How does Freud explain the structure of personality?
Ans. The Id:
(i) The Id is the original source of personality, present in the newborn infant, from which the ego and super ego later develop.
(ii) It consists of everything that is inherited, including the instinctual drives—sex and
aggression.
(iii) It is closely linked to the biological processes and provides the energy source—the libido for the operation of all three systems.
(iv) It is totally unconscious and works on pleasure principles regardless of any,external potential costs of seeking the gratification of impulses.
The Ego:
(i) The ego develops out of Id because of the necessity for dealing with the real world. The ego’s task is to hold the Id in check until conditions allows for satisfaction of its impulses.
(ii) It operates on reality principles. For example, a hungry man would want to have food at any cost due to id impulses, but it is the ego which delays tl’ i hunger impulse until the appropriate conditions are found.
(iii)The ego is essentially the executive of the personality. It keeps a person working for a living, getting along with people and generally adjusting to the realities of life.
(iv) Ego mediates between the demands of id, the realities of the world and the demands of the super ego.
The Super Ego:
(i)It is related to the values and morals of the society as taught to us by our parents and others. It works according to social norms.
(ii)It is concerned with morality—whether various ways that could satisfy id impulses are right or wrong.
The main functions of the super ego are:
(i) To inhibit the unacceptable impulses of Id such as sex and aggression.
(ii)Freud assumed that Id is energised by two instinctual forces, called life instinct and death instinct. Life instinct is individuals, tendency to construct whereas death instinct is for the destruction. According to Freud, life instinct is more dominant among human beings.
According to Freud, the instinctual life force that energises the Id is called Libido.
It works on the pleasure principle, and seeks immediate gratification. It is source of energy.

6. How would Horney’s explanation of depression be different from that of Alfred Adler?
Ans. While Karen Horney focuses more on interpersonal relationships during childhood, Alfred gives greater importance to personal goals of an individual.
There are, in my opinion, Horney would attribute the cause of depression to parental relations with children which are characterized by excessive interference or indifference. Deep anxiety would result from the behaviour rewards the child which, if is erratic, indifferent and discouraging feelings of isolation and helplessness will also emerge. Alfred Adler would, on the other hand, attribute depression to the feeling of inadequacy and guilt arising within the individual, due to the inability to achieve his/her personal goals. These goals provide an individual with security and are important in overcoming feelings of inadequacy. If individual is not able to attain the goals and could not overcome inferiority appropriately then it leads to depression.

7. What is the main proposition of humanistic approach to personality? What did Maslow mean by self-actualization?
Ans. Humanistic theories emphasise personal responsibility and innovate tendencies toward personal growth. They focus on the importance of people’s subjective attitudes, feelings and beliefs especially with regard to the self.
•According to humanistic approach, we human beings are most creative, growing, fully functioning and self-actualizing people.
•Fully functioning persons, according to Rogers theory, psychologically healthy persons who live life to the fullest.
•They live in the here and now and trust their own feelings. They are sensitive to the needs of others but they do not allow society’s standards to shape their feelings or actions to an excessive degree.
Rogers suggests that each individual has a concept of ideal self. If there is discrepancy between real self and ideal self then individual develops maladjustment.
Rogers proposed two basic assumptions:
(a)Human behaviour is goal-directed and worthwhile.
(b)People always choose adaptive and self-actualizing behaviour.
Rogers believed that many individuals fail to become fully functioning persons because they grow up in an atmosphere of conditional positive regard and develop distorted self-concept# which interferes with personal growth. Such people fail to self-actualise.
•All human beings desire unconditional positive regard, freedom of choice and feeling of fulfilment for attainment of self-actualization.
•Humanistic theories don’t deny the importance of past experience but they generally focus on the present.
Maslow’s Contribution to Humanistic Approach
Maslow’s Self-Actualization
•It is a state which people have reached their own fullest potential.
•He had an optimistic view of man who has potentialities for love, joy and creative work.
•According to him, human beings are free to shape their lives and to self-actualise.

8. Discuss the main observational methods used in personality assessment. What problems do we face in using these methods?
Ans. • Observational method is a very powerful tool of psychological enquiry. It is an effective method of describing behaviour.
•A scientific observation differs from day-to-day observation in many respects,
(i)Selection: Psychologists do not observe all the behaviour that they encounter. Rather, they select a particular behaviour for observation.
(ii)Recording: While observing, a researcher records the selected behaviour using different means, such as marking tallies for the already identified behaviour whenever they occur, taking notes describing each activity in greater detail using short hand or symbols, photographs, video recording, etc.
(iii)After the observations have been made, psychologists analyse whatever they have recorded with a view to derive some meaning out of it.
(iv)Observation is a skill. A good observation is a skill. A good observer knows what he/she is looking for, w’hom he/she wants to observe, when and where the observation needs to be made.
•Observation can be of the following types :
(a) Non-Participant vs. Participant Observation:
1.Non-participant observation
(i)To observe the person or event from a distance.
(ii)The observer may become part of the group being observed.
(iii)In the first case, the person being observed may not be aware that he/she is
being observed. For example, you want to observe the pattern of interaction between teachers and students in a particular class. .
(iv) Install a video camera to record the classroom activities, which you can see later and analyse. Alternatively, you may decide to sit in a corner of the class without interfering or participating in their everyday activities. This type of observation is called non-participant observation.
2. Participant observation
(i)In participant observation, the observer becomes a part of the school or the group of people being observed.
(ii)the observer takes some time to establish a rapport with the group so that they start accepting him/her as one of the group members.
(iii)the degree of involvement of the observer with the group being observed would vary depending upon the focus of the study.
The advantage of the observation method is that it enables the researcher to study people and their behaviour in a naturalistic situation, as it occurs. However, the observation method is labour-intensive, time-consuming, and is susceptible to the observer’s bias. Our observation is influenced by our values and beliefs about the person or the event.

9. What is meant by structured personality tests? Which are the two most widely used structured personality tests?
Ans. Structured personality tests are self-report measures that have the following features:
•Questions are direct and structured.
•They are called self-report because the examinee has to respond objectively to the items of the measure and his/her response are accepted as they are.
•They are objective in nature and they deal with the present state of mind.
— Self-report measures use inventories and questionnaires to assess conscious part of personality.
— Goal of the test may be revealed.
— These tests assess only conscious part of personality
•Their results depend on motivation and emotional state of the examinee; they are
non-projective and direct inferences are made. _
Some of the self-report measures are:
1.Eysenck Personality Questionnaire (EPQ): This test was developed by Eysenck to assess two basic dimensions of personality namely introverted—extroversion and emotionally stable—emotionally unstable (Neuroticism).
2.MMPI: Minnesota Multiphasic Personality Inventory. This test was developed by Hathaway and Mckinely.
•It has been found very effective in detecting psycho-pathology like hypochondriasis, depression, hysteria etc.
•The test is divided into 10 sub scales. This test helps in clinical diagnosis of various mental disorders like hypochondriasis, depression, hysteria, etc.
•It has two sets’MMPI-I and MMPI-II. Now-a-days, MMPI-II is being used.
•It has 567 items in the form of affirmative statements. The subject judges each item ‘statements’ as true or false.
•MMPI is one of the very good tests for clinical purposes (diagnosis).
•Indian version of MMPI is also available named as Jodhpur Multiphasic Personality Inventory (JMPI) by Malik and Joshi.
16-PF Questionnaire
•It is developed by Cattell.
•It identifies large set of personality descriptions—subjected to factor analysis to identify basic personality structure.
•Subject responds to situation by choosing from alternatives.
•This test is being used with high school level students in India for career guidance
and counselling. ‘
Problems Faced by self-report Measures
•Social Desirability: It is a tendency on part of the respondent to endorse items in a socially desirable manner.
•Acquiescence: It is a tendency of the subject to agree with items/questions irrespective of contents.
•Testing and understanding personality require great skill and training.
•People become self-aware and conscious, hesitate to share thoughts and feelings and motivation. If they do it, it is done in a socially desirable manner. So, the real personality characteristics are not manifested.

10. State in common features of projective techniques. Describe anyone projective technique.
Or
Explain how projective techniques assess personality. Which projective tests of personality are widely used by psychologists?
Ans. •Projective tests of personality are widely used by psychologists.
•Projective techniques are most indirect method to assess personality.
•Psycho analytic theory proposed that behaviour is also determined by unconscious forces.
•The projective techniques were developed to assess unconscious motives and feelings.
— The stimulus material is relative or fully unstructured and poorly defined.
— The person being assessed is usually not told the purpose and the method of scoring and interpretation before the administration of test. — The person is informed that there are no right or wrong responses.
— Each response is considered to reveal a true and significant aspect of personality.
— The scoring and interpretation in projective assessment are lengthy and subjective.
Projective Techniques
— Developed to assess unconscious motives, feelings and conflicts.
— A less structured or unstructured stimulus or situation will allow the individual to project his/her feelings, desires and needs on to that situation,
— Projections are interpreted by experts.
— Cannot be scored objectively, require qualitative analysis for which a rigorous training is needed.
1.The Rorschach Inkblot Test (Hermann Rorschach)
•Consists of 10 inkblots—5 black and white, 2 with red ink, 3 in pastel colours.
•Blots are symmetrical in design with a specific shape or form, made by dropping ink on a piece of paper and then folding the paper in half (hence called inkblot test).
•The cards are administered individually in two phases:
—Performance proper: The subjects are shown the cards and are asked to tell what they see in each of them.
—Inquiry: A detailed report of the response is prepared by asking the subject to tell where, how, and on what basis was a particular response made.
•Fine judgment is necessary to place the subject’s responses in a meaningful context. Use and interpretation of this test requires extensive training
2. The Thematic Apperception Test (TAT) Morgan and Murray
•This test consists of 30 black and white picture cards and one blank card—each picture card depicts one or more people in a variety of situations.
• Some cards are used specifically with adult males or females, boys or girls—have been modified for the children and the aged.
•The cards are presented one at a time and the subject is asked to tell a story describing the situation presented in the picture—what led up to the situation, what is happening at the moment, what will happen in the future, what the characters are feeling and thinking?
Uma Chaudhury’s Indian adaptation of TAT is also available.
3.Rosenzweig’s Picture-Frustration Study (P-F Study)
• This study assesses how people express aggression in the face of a frustrating situation.
•Presents with the help of cartoon-like pictures a series of situations in which one person frustrates another, or calls attention to a frustrating condition.
•The subject is asked to tell what the other (frustrated) person will say or do.
•The analysis of responses is based on the type and direction of aggression—examine whether the focus is on the frustrating object (environment), or on protection of the frustrated person (oneself), or on constructive solution of the problem.
Pareek has adapted this test for the Indian population
4. Sentence Completion Test
•This test makes use of a number of incomplete sentences—the starting part of the sentence is first presented and the subject has to provide an ending to the sentence.
•The type of endings used by the subjects reflect their attitudes, motivation and conflicts.
•The test provides subjects with several opportunities to reveal their underlying unconscious motivations.
5. Draw-a-Person Test
•In this test, the subject is asked to draw a person on a sheet of paper and then a figure of an opposite sex person.
•Finally, the subject is asked to make a story about the person as if he/she was a character in a novel or play.
•Some examples of interpretations are as follows:
— Omission of facial features suggests that the person tries to evade a highly conflict-ridden interpersonal relationships.
— Graphic emphasis on the neck suggests lack of control over impulses.
— Disproportionately large head suggests organic brain disease and pre-occupation with headaches. ..
Limitations
•Interpretation of the responses requires sophisticated skills and specialized training.
•There are problems associated with the reliability of scoring and validity of interpretations.

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NCERT MOST IMPORTANT QUESTIONS CLASS – 12 | PSYCHOLOGY IMPORTANT QUESTIONS | CHAPTER-3 | HUMAN STRENGTHS AND MEETING LIFE CHALLENGES | EDUGROWN |

In This Post we are  providing  CHAPTER 3 HUMAN STRENGTHS AND MEETING LIFE CHALLENGES NCERT MOST IMPORTANT QUESTIONS for Class 12 PSYCHOLOGY which will be beneficial for students. These solutions are updated according to 2021-22 syllabus. These MCQS  can be really helpful in the preparation of Board exams and will provide you with a brief knowledge of the chapter

NCERT MOST IMPORTANT QUESTIONS ON HUMAN STRENGTHS AND MEETING LIFE CHALLENGES

1. Explain the concept of stress. Give examples from daily life.

Answer

Stress is derived from Latin word ‘strictus’ which means tight or narrow. Stress can be described as the pattern of responses an organism makes to stimulus event that disturbs the equilibrium and exceeds a person’s ability to cope. All the challenges, problems, and difficult circumstances put us to stress. It gives energy, increases human arousal and affects performance. High stress too can produce unpleasant effects and cause our performance to deteriorate. Conversely, too little stress may cause one to feel somewhat listless and low on motivation which may lead us to perform slowly and less efficiently. It is important to remember that not all stress is inherently bad or destructive.
Examples from daily life:
Attending parties may be stressful for a person who likes to spend quiet evenings at home.
If a person gets low marks than his/her expectations, then it may be stressful and a sign of frustration for them.
When someone is forced to choose the job due to family pressure then it may stressful for him afterwards.

2. State the symptoms and sources of stress.

Answer

Symptoms of stress:
Some of us know our pattern of stress response and can gauge the depth of the problem by the nature and severity of our own symptoms or changes in behaviour. These symptoms of stress can  be physical,  emotional  and behavioural. Any of the symptoms can indicate a degree of stress which, if left unresolved,  might  have  serious implications.

Sources of stress:
A wide range of events and conditions can generate stress. Among the most important of these are major stressful life events, such as death of a loved one or personal injury, the annoying frequent hassles of everyday life and traumatic events that affect our lives.

3. Describe the GAS model and illustrate the relevance of this model with the help of an example.

Answer

Selye studied the body when stress is prolonged by subjecting animals to a variety of stressors such as high temperature, X-rays and insulin injections, in the laboratory over a long period of time. He also observed patients with various injuries and illnesses in hospitals. Selye noticed a similar pattern of bodily response in all of them. He called this pattern the General Adaptation Syndrome (GAS). According to him, GAS involves three stages: alarm reaction, resistance, and exhaustion.

(i) Alarm reaction stage: The presence of a noxious stimulus or stressor leads to activation of the adrenal-pituitary-cortex system. This triggers the release of hormones producing the stress response. Now the individual is ready for fight or flight.
(ii) Resistance stage: If stress is prolonged, the resistance stage begins. The para-sympathetic nervous system calls for more cautious use of the body’s resources. The organism makes efforts to cope with the threat, as through confrontation.
(iii) Exhaustion stage: Continued exposure to the same stressor or additional stressors drains the body of its resources and leads to the third stage of exhaustion. The physiological systems involved in alarm reaction and resistance become ineffective and susceptibility to stress-related diseases such as high blood pressure becomes more likely.

Selye’s model has been criticised for assigning a very limited role to psychological factors in stress. Researchers have reported that the psychological appraisal of events is important for the determination of stress. How people respond to stress is substantially influenced  by  their perceptions, personalities and biological constitutions

4. Enumerate the different ways of coping with stress.

Answer

To manage stress we often need to reassess the way we think and learn coping strategies. Different ways of coping with stress are:
(i) Task-oriented Strategy: This involves obtaining information about the stressful situation and about alternative courses of action and their probable outcome. It also involves deciding priorities and acting so as to deal directly with the stressful situation. For example, schedule my time better, or think about how I have solved similar problems.
(ii) Emotion-oriented Strategy: This can involve efforts to maintain hope and to control one’s emotions. It can also involve venting feelings of anger and frustration, or deciding that nothing can be done to change things. For example, tell myself that it is not really happening to me, or worry about what I am going to do.
(iii) Avoidance-oriented Strategy: This involves denying or minimising the seriousness of the situation. It also involves conscious suppression of stressful thoughts and their replacement by self-protective thoughts. Examples of this are watching TV, phone up a friend, or try to be with other people.

5. Explain the effect of stress on psychological functioning.

Answer

The effect of stress on psychological functioning:
(i) Emotional Effects: Those who suffer from stress are far more likely to experience mood swings, and show erratic behaviour that may alienate them from family and friends. In some cases this can start a vicious circle of decreasing confidence, leading to more serious emotional problems. Some examples are feelings of anxiety and depression, increased physical tension, increased psychological tension and mood swings.
(ii) Physiological Effects: When the human body is placed under physical or psychological stress, it increases the production of certain hormones such as adrenaline and cortisol. These hormones produce marked changes in heart rate, blood pressure levels, metabolism and physical activity. Although, this physical reaction will help us to function more effectively when we are under pressure for short periods of time, it can be extremely damaging to the body in the long-term effects. Examples of physiological effects are release of epinephrine and nor-epinephrine, slowing down of the digestive system, expansion of air passages in the lungs, increased heart rate and constriction of blood vessels.
(iii) Cognitive Effects: If pressures due to stress continue, one may suffer from mental overload. This suffering from high level of stress can rapidly cause individuals to lose their ability to make sound decisions. Faulty decisions made at home, in career, or at workplace may lead to arguments, failure, financial loss or even loss of job. Cognitive effects of stress are poor concentration, and reduced short-term memory capacity.
(iv) Behavioural Effects: Stress affects our behaviour in the form of eating less nutritional food, increasing intake of stimulants such as caffeine, excessive consumption of cigarettes, alcohol and other drugs such as tranquillisers etc. Tranquillisers can be addictive and have side effects such as loss of concentration, poor coordination, and dizziness. Some of the typical behavioural effects of stress seen are disrupted sleep patterns, increased absenteeism, and reduced work performance.


6. Describe how life skills can help meet life’s challenges.

Answer

Life skills are abilities for adaptive and positive behaviour that enable individuals to deal effectively with the demands and challenges of everyday life. Our ability to cope depends on how well we are prepared to deal with and counterbalance everyday demands and keep equilibrium in our lives. These life skills can be learned and even improved upon. Assertiveness, time management, rational thinking, improving relationships, self-care and overcoming unhelpful habits such as perfectionism,
procrastination, etc. are some life skills that will help to meet the challenges of life

7. Discuss the factors that lead to positive health and well-being.

Answer

Various factors have been identified which facilitate the development of positive health. Health is a state of complete physical, mental, social and spiritual well-being and not merely the absence of disease or infirmity. Positive health comprises the following constructs: “a healthy body, high quality of personal relationships, a sense of purpose in life self-regard, mastery of life’s tasks and resilience to stress, trauma, and change”. Specifically, factors that act as stress buffers and facilitate positive health are diet, exercise, positive attitude, positive thinking, and social support.

8. How does stress affect the immune system?

Answer

Stress can cause illness by impairing the workings of the immune system. The immune system guards the body against attackers, both from within and outside. Psychoneuroimmunology focuses on the
links between the mind, the brain and the immune system. It studies the effects of stress on the immune system. How does the immune system work? The white blood cells (leucocytes) within the immune system identify and destroy foreign bodies (antigens) such as viruses. It also leads to the production of antibodies. There are several kinds of white blood cells or leucocytes within the immune system, including T cells, B cells and natural killer cells. T cells destroy invaders, and T-helper cells increase immunological activity. It is these T-helper cells that are attacked by the Human Immuno Deficiency Virus (HIV), the virus causing Acquired Immuno Deficiency Syndrome (AIDS). B cells produce antibodies. Natural killer cells are involved in the fight against both viruses
and tumours.
Stress can affect natural killer cell cytotoxicity, which is of major importance in the defence against various infections and cancer. Reduced levels of natural killer cell cytotoxicity have been found in people who are highly stressed, including students facing important examinations, bereaved persons, and those who are severely depressed. Studies reveal that immune functioning is better in individuals receiving social support. Also, changes in the immune system will have more effect on health among those whose immune systems are already weakened.

9. Give an example of a life event which is likely to be stressful. Suggest reasons why it is likely to cause different degrees of stress to the person experiencing it.

Answer

Changes, both big and small, sudden and gradual affect our life from the moment we are born. We learn to cope with small, everyday changes but major life events can be stressful, because they disturb our routine and cause upheaval. If several of these life events that are planned (e.g. moving into a new house) or unpredicted (e.g. break-up of a long-term relationship) occur within a short period of time, we find it difficult to cope with them and will be more prone to the symptoms of stress.
Unexpected accident or trauma or death of a close family member are examples of life events which are very stressful for the members, relatives of the family and friends.
The impact of most life events varies from person to person. Factors such as age at which the event was first experienced, frequency of occurrence, duration of the stressful event and social support are the reasons which is likely to cause different degrees of stress to the person experiencing it.

10. Given what you know about coping strategies, what suggestions would you give to your friends to avoid stress in their everyday lives.

Answer

Coping is a dynamic situation-specific reaction to stress. It is a set of concrete responses to stressful situations or events that are intended to resolve the problem and reduce stress.
I would suggest my friends to adopt problem-focused strategies and emotion focused strategies. Both are coping strategies which can be used to handle stressful situations.
Problem-focused strategies attack the problem itself, with behaviours designed to gain information, to alter the event, and to alter belief and commitments. They increase the person’s awareness, level of knowledge, and range of behavioural and cognitive coping options. They can act to reduce the threat value of the event. For example “I made a plan of action and followed it”. Emotion-focused strategies call for psychological changes designed primarily to limit the degree of emotional disruption caused by an event, with minimal effort to alter the event itself. For example “I did some things to let it out of my system”. While both problem-focused and emotion-focused coping are necessary when facing stressful situations, research suggests that people generally tend to use the former more often than the latter.

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