RD SHARMA SOLUTION CHAPTER- 32 Statistics I CLASS 11TH MATHEMATICS-EDUGROW

Chapter 32 Statistics Exercise Ex. 32.1

Question 1(i)

Solution 1(i)

Question 1(ii)

Solution 1(ii)

Question 1(iii)

Solution 1(iii)

Question 1(iv)

Solution 1(iv)

Question 1(v)

Solution 1(v)

Question 2(i)

Solution 2(i)

Question 2(ii)

Solution 2(ii)

Question 2(iii)

Solution 2(iii)

Question 2(iv)

Solution 2(iv)

Question 2(v)

Calculate the mean deviation about the mean of the following data:

(v) 57, 64, 43, 67, 49, 59, 44, 47, 61, 59Solution 2(v)

Question 4

Solution 4

Question 5(i)

Solution 5(i)

Question 5(ii)

Solution 5(ii)

Question 5(iii)

Solution 5(iii)

Question 6

Solution 6

Question 3

Calculate the mean deviation on the following income groups of five and seven members from their medians:

I Income in Rs. II income in Rs. 
40003800
42004000
44004200
46004400
48004600
 4800
 5800

Solution 3

Note: Answer given in the book is incorrect.

Chapter 32 Statistics Exercise Ex. 32.2

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4(i)

Solution 4(i)

Question 4(ii)

Solution 4(ii)

Question 4(iii)

Solution 4(iii)

Question 4(iv)

Solution 4(iv)

Question 5(ii)

Solution 5(ii)

Question 5(iii)

Solution 5(iii)

Question 4(v)

Find the mean deviation from the mean for the following data:

Size:1 3 5 7 9 11 13 15
Frequency:3 3 4 14 7 4 3 4

Solution 4(v)

Question 5(i)

Find the mean deviation from the median for the following data:

xi15 21 27 30
fi 3 5 6 7

Solution 5(i)

Note: Answer given in the book is incorrect.

Chapter 32 Statistics Exercise Ex. 32.3

Question 1

Solution 1

Question 2(i)

Solution 2(i)

Question 2(ii)

Solution 2(ii)

Question 2(iii)

Solution 2(iii)

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 7

Solution 7

Question 8

Solution 8

Question 6

Calculate mean deviation about median age for the age distribution of 100 persons given below:

Age:16-2021-2526-3031-3536-4041-4545-5050-55
Number of persons5612142612169

Solution 6

Chapter 32 – Statistics Exercise Ex. 32.4

Question 1(i)

Solution 1(i)

Question 1(ii)

Find the mean, variance and standard deviation for the data:

6, 7, 10, 12, 13, 4, 8, 12.Solution 1(ii)

Question 1(iii)

Solution 1(iii)

Question 1(iv)

Solution 1(iv)

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11

Show that the two formulae for the standard deviation of ungrouped data

Solution 11

Chapter 32 Statistics Exercise Ex. 32.5

Question 1

Solution 1

Question 2

Solution 2

Question 3

F i n d space t h e space m e a n comma space a n d space t h e space s tan d a r d space d e v i a t i o n space f o r space t h e space f o l l o w i n g space d a t a :

(i)

(ii)

Solution 3

Question 4

(ii)

Solution 4

Chapter 32 Statistics Exercise Ex. 32.6

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Calculate the Mean, median and Standard Deviation of the following distribution:
Solution 5

Question 7

Solution 7

Question 8

Mean and standard deviation of 100 observation were found to be 40 and 10 respectively. If at the time of calculation two observations were wrongly taken as 30 and 70 in place of 3 and 27 respectively, find the correct standard deviation.Solution 8

Question 9

While calculating the mean and variance of 10 readings , a student wrongly used the reading of 52 for the correct reading 25. He obtained the mean and variance as 45 and 16 respectively. Find the correct mean and the variance.Solution 9

Question 6

Find the mean and variance of frequency distribution given below:

xi:1 x <3 x<55 x<77 x<9
Fi:6451

Solution 6

Note: Answer given in the book is incorrect. Question 10

Calculate mean, variance and standard deviation of the following frequency distribution:

Class:0-1010-2020-3030-4040-5050-60
Frequency:112918453

Solution 10

Chapter 32 Statistics Exercise Ex. 32.7

Question 1

Solution 1

We observe that the average monthly wages in both firms is same i.e. Rs. 2500. Therefore the plant with greater variance will have greater variability. Thus plant B has greater variability in individual wages. Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11

Life of bulbs product by two factories A and B are given below:

Length of life(in hours):Factory A:550-650 650-750 750-850 850-950 950-1050
(Number of bulbs)Factor B:10   22 52 20 16
(Number of bulbs)8  60 24 15 12

The bulbs of which factory are more consistent from the point of view of length of life?Solution 11

Question 12

Following are mark obtained, out of 100, by two students Ravi and Hashina in 10 tests:

Ravi:25 50 45 30 70 42 36 48 35 60
Hashina:10 70 50 20 95 55 42 60 48 80

Who is more intelligent and who is more consistent?Solution 12

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RD SHARMA SOLUTION CHAPTER- 31 Mathematical Reasoning I CLASS 11TH MATHEMATICS-EDUGROW

Chapter 31 Mathematical Reasoning Exercise Ex. 31.1

Question 1(i)

Solution 1(i)

Question 1(ii)

Solution 1(ii)

Question 1(iii)

Solution 1(iii)

Question 1(iv)

Solution 1(iv)

Question 1(v)

Solution 1(v)

Question 1(vi)

Solution 1(vi)

Question 1(vii)

Solution 1(vii)

Question 1(viii)

Solution 1(viii)

Question 1(ix)

Solution 1(ix)

It is not a statement.

The sentence “This sentence is a statement.” cannot  be assigned a truth value of either true or false, because either assignment contradicts the sense of the sentence.Question 1(x)

Solution 1(x)

Question 1(xi)

Solution 1(xi)

Question 1(xii)

Solution 1(xii)

Question 1(xiii)

Solution 1(xiii)

Question 1(xiv)

Solution 1(xiv)

Question 1(xv)

Solution 1(xv)

Question 1(xvi)

Solution 1(xvi)

Question 2

Solution 2

Chapter 31 Mathematical Reasoning Exercise Ex. 31.2

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Chapter 31 Mathematical Reasoning Exercise Ex. 31.3

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Chapter 31 Mathematical Reasoning Exercise Ex. 31.4

Question 1

Solution 1

Question 2

Solution 2

Chapter 31 Mathematical Reasoning Exercise Ex. 31.5

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Chapter 31 Mathematical Reasoning Exercise Ex. 31.6

Question 1(i)

Solution 1(i)

Question 1(ii)

Solution 1(ii)

Question 1(iii)

Solution 1(iii)

Question 2(i)

Solution 2(i)

Question 2(ii)

Solution 2(ii)

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

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RD SHARMA SOLUTION CHAPTER- 30 Derivatives I CLASS 11TH MATHEMATICS-EDUGROW

Chapter 30 Derivatives Exercise Ex. 30.1

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7 (i)

Solution 7 (i)

Question 7 (ii)

Solution 7 (ii)

Question 7 (iii)

Solution 7 (iii)

Question 7(iv)

Solution 7(iv)

Chapter 30 Derivatives Exercise Ex. 30.2

Question 1(i)

Solution 1(i)

Question 1 (ii)

Solution 1 (ii)

Question 1 (iii)

Solution 1 (iii)

Question 1 (iv)

Solution 1 (iv)

Question 1 (v)

Solution 1 (v)

Question 1 (vi)

Solution 1 (vi)

Question 1 (vii)

Solution 1 (vii)

Question 1 (viii)

Solution 1 (viii)

Question 1 (ix)

Solution 1 (ix)

Question 1 (x)

Solution 1 (x)

Question 1 (xi)

Solution 1 (xi)

Question 1 (xii)

Solution 1 (xii)

Question 1 (xiii)

Solution 1 (xiii)

Question 1 (xiv)

Solution 1 (xiv)

Question 2 (i)

Solution 2 (i)

Question 2 (ii)

Solution 2 (ii)

Question 2 (iii)

Solution 2 (iii)

Question 2 (iv)

Solution 2 (iv)

Question 2(ix)

Solution 2(ix)

Question 2(x)

Solution 2(x)

Question 2(xi)

Solution 2(xi)

Question 3 (vii)

Solution 3 (vii)

Question 3 (viii)

Solution 3 (viii)

Question 3 (ix)

Solution 3 (ix)

Question 3 (x)

Solution 3 (x)

Question 3 (xi)

Solution 3 (xi)

f left parenthesis x right parenthesis equals a to the power of square root of x end exponent equals e to the power of square root of x log a end exponent

f to the power of comma left parenthesis x right parenthesis equals limit as h rightwards arrow 0 of fraction numerator f left parenthesis x plus h right parenthesis minus f left parenthesis x right parenthesis over denominator h end fraction
space space space space space space space space equals limit as h rightwards arrow 0 of fraction numerator e to the power of square root of x plus h end root log a end exponent minus e to the power of square root of x log a end exponent over denominator h end fraction
space space space space space space space space equals limit as h rightwards arrow 0 of e to the power of square root of x log a end exponent fraction numerator e to the power of square root of x plus h end root log a minus square root of x log a end exponent minus 1 over denominator h end fraction
space space space space space space space space equals limit as h rightwards arrow 0 of e to the power of square root of x log a end exponent fraction numerator e to the power of open parentheses square root of x plus h end root minus square root of x close parentheses log a end exponent minus 1 over denominator h end fraction
text Multiply   numerator   and   denominator   by end text space open parentheses square root of x plus h end root minus square root of x close parentheses log a
f to the power of comma left parenthesis x right parenthesis space equals limit as h rightwards arrow 0 of e to the power of square root of x log a end exponent fraction numerator e to the power of open parentheses square root of x plus h end root minus square root of x close parentheses log a end exponent minus 1 over denominator h open parentheses square root of x plus h end root minus square root of x close parentheses log a end fraction open parentheses square root of x plus h end root minus square root of x close parentheses log a
space space space space space space space space equals e to the power of square root of x log a end exponent limit as h rightwards arrow 0 of fraction numerator e to the power of open parentheses square root of x plus h end root minus square root of x close parentheses log a end exponent minus 1 over denominator open parentheses square root of x plus h end root minus square root of x close parentheses log a end fraction limit as h rightwards arrow 0 of log a fraction numerator open parentheses square root of x plus h end root minus square root of x close parentheses over denominator h end fraction
space space space space space space space space space equals e to the power of square root of x log a end exponent limit as h rightwards arrow 0 of log a fraction numerator open parentheses square root of x plus h end root minus square root of x close parentheses over denominator h end fraction

text Multiply   numerator   and   denominator   by end text space open parentheses square root of x plus h end root plus square root of x close parentheses
space f to the power of comma left parenthesis x right parenthesis equals e to the power of square root of x log a end exponent limit as h rightwards arrow 0 of log a fraction numerator open parentheses square root of x plus h end root minus square root of x close parentheses over denominator h open parentheses square root of x plus h end root plus square root of x close parentheses end fraction open parentheses square root of x plus h end root plus square root of x close parentheses
equals e to the power of square root of x log a end exponent limit as h rightwards arrow 0 of log a fraction numerator h over denominator h open parentheses square root of x plus h end root plus square root of x close parentheses end fraction
equals e to the power of square root of x log a end exponent fraction numerator log a over denominator 2 square root of x end fraction
equals fraction numerator a square root of blank to the power of x end root over denominator 2 square root of x end fraction log subscript e a

Question 3 (xii)

Solution 3 (xii)

Question 3 (i)

Solution 3 (i)

Question 3 (ii)

Solution 3 (ii)

Question 3 (iii)

Solution 3 (iii)

Question 3 (iv)

Solution 3 (iv)

Question 3 (v)

Solution 3 (v)

Question 3 (vi)

Solution 3 (vi)

Question 4 (i)

Solution 4 (i)

Question 4 (ii)

Solution 4 (ii)

Question 4 (iii)

Solution 4 (iii)

Question 4 (iv)

Solution 4 (iv)

Question 5(i)

Solution 5(i)

Question 5 (ii)

Solution 5 (ii)

Question 5 (iii)

Solution 5 (iii)

Question 5(iv)

Solution 5(iv)

Question 6 (i)

Solution 6 (i)

Question 6 (ii)

Solution 6 (ii)

Question 6(iii)

Solution 6(iii)

Question 6(iv)

Solution 6(iv)

Question 1(xv)

Solution 1(xv)

Question 2(v)

Differentiate -x using first principles.Solution 2(v)

Question 2(vi)

Differentiate (-x)-1 using first principles.Solution 2(vi)

Question 2(vii)

Differentiate sin(x + 1) using first principles.Solution 2(vii)

Question 2(viii)

Differentiate cos  using first principles.Solution 2(viii)

Chapter 30 Derivatives Exercise Ex. 30.3

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13

Solution 13

Question 14

Solution 14

Question 15

Solution 15

Question 16

Defferentiate f (x) = log open parentheses fraction numerator 1 over denominator square root of straight x end fraction close parentheses plus 5 straight x to the power of straight a minus 3 straight a to the power of straight x plus 3 square root of straight x squared end root plus 6 fourth root of straight x to the power of negative 3 end exponent end root with space respect space to space straight x.Solution 16

fraction numerator d over denominator a x end fraction open curly brackets log open parentheses fraction numerator 1 over denominator square root of x end fraction close parentheses plus 5 x to the power of a minus 3 a to the power of x plus 3 root of x squared end root plus 6 4 root of x to the power of minus 3 end exponent end root close curly brackets
equals fraction numerator d over denominator a x end fraction log open parentheses fraction numerator 1 over denominator square root of x end fraction close parentheses plus 5 fraction numerator d over denominator a x end fraction open parentheses x to the power of a close parentheses minus 3 open parentheses a to the power of x close parentheses plus fraction numerator d over denominator a x end fraction open parentheses 3 root of x squared end root close parentheses plus 6 fraction numerator d over denominator a x end fraction open parentheses 4 root of x to the power of minus 3 end exponent end root close parentheses
equals fraction numerator minus 1 over denominator 2 end fraction 1 over x plus 5 a x to the power of a minus 1 end exponent minus 3 a to the power of x log a plus fraction numerator 2 x to the power of begin display style bevelled fraction numerator minus 1 over denominator 3 end fraction end style end exponent over denominator 3 end fraction plus 6 x to the power of bevelled fraction numerator minus 7 over denominator 4 end fraction end exponent open parentheses bevelled fraction numerator minus 3 over denominator 4 end fraction close parentheses
equals fraction numerator minus 1 over denominator 2 x end fraction plus 5 a x to the power of a minus 1 end exponent minus 3 a to the power of x log a plus fraction numerator 2 x to the power of begin display style bevelled fraction numerator minus 1 over denominator 3 end fraction end style end exponent over denominator 3 end fraction minus 9 over 2 x to the power of bevelled fraction numerator minus 7 over denominator 4 end fraction end exponent

Question 17

Solution 17

Question 18

Solution 18

Question 19

Solution 19

Question 20

Solution 20

Question 21

Solution 21

Question 22

Solution 22

Question 23

Solution 23

Question 24

Solution 24

Question 25

Solution 25

Question 26

Solution 26

Chapter 30 Derivatives Exercise Ex. 30.4

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13

Solution 13

Question 14

Solution 14

Question 15

Solution 15

Question 16

Solution 16

Question 17

Solution 17

Question 18

Solution 18

Question 19

Solution 19

Question 20

Solution 20

Question 21

Solution 21

Question 22

Solution 22

Question 23

Solution 23

Question 24

Solution 24

Question 25

Differentiate the following functions with respect to x:

Solution 25

Question 26

Differentiate the following functions with respect to x:

(ax + b)n (cx + d)mSolution 26

Question 27

Differentiate in two ways, using product rule and otherwise, the function (1 + 2 tan x) (5 + 4 cos x). Verify that the answer are the same.Solution 27

Question 28(i)

Differentiate each of the following functions by the product rule and the other method and verify that answer from both the methods is the same.

(3x2 + 2)2Solution 28(i)

Question 28(ii)

Differentiate each of the following functions by the product rule and the other method and verify that answer from both the methods is the same.

(x + 2)(x + 3)Solution 28(ii)

Question 28(iii)

Differentiate each of the following functions by the product rule and the other method and verify that answer from both the methods is the same.

(3 sec x – 4 cosec x) (-2 sin x + 5 cos x)Solution 28(iii)

Chapter 30 Derivatives Exercise Ex. 30.5

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13

Solution 13

Question 14

Solution 14

Question 15

Solution 15

Question 16

Solution 16

Question 17

Solution 17

Question 18

Solution 18

Question 19

Solution 19

Question 20

Solution 20

Question 21

Solution 21

Question 22

Solution 22

Question 23

Solution 23

Question 24

Solution 24

Question 25

Solution 25

Question 26

Solution 26

Question 27

Solution 27

Question 28

text Differentiate end text fraction numerator x to the power of n over denominator sin x end fraction text   with   respect   to   x. end text

Solution 28

fraction numerator d over denominator d x end fraction open parentheses fraction numerator x to the power of n over denominator sin x end fraction close parentheses
equals x to the power of n fraction numerator d over denominator d x end fraction open parentheses sin x close parentheses to the power of minus 1 end exponent plus fraction numerator 1 over denominator sin x end fraction fraction numerator d over denominator d x end fraction open parentheses x to the power of n close parentheses
equals x to the power of n fraction numerator minus 1 over denominator sin squared x end fraction plus fraction numerator 1 over denominator sin x end fraction n x to the power of n minus 1 end exponent
equals fraction numerator sin x left parenthesis n x to the power of n minus 1 end exponent right parenthesis minus x to the power of n left parenthesis cos x right parenthesis over denominator sin squared x end fraction

Question 29

Differentiate the following functions with respect to x:

fraction numerator a x plus b over denominator p x squared plus q x plus r end fraction

Solution 29

Question 30

Differentiate the following functions with respect to x:

fraction numerator 1 over denominator a x squared plus b x plus c end fraction

Solution 30

Syntax error from line 1 column 1707 to line 1 column 1712. Unexpected '</mi>'.
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RD SHARMA SOLUTION CHAPTER- 29 Limits I CLASS 11TH MATHEMATICS-EDUGROW

Chapter 29 Limits Exercise Ex. 29.1

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

H e n c e comma space l i m i t space d o e s space n o t space e x i s t.

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13(i)

Solution 13(i)

Question 13(ii)

Solution 13(ii)

Question 13(iii)

Solution 13(iii)

Question 13(iv)

Solution 13(iv)

Question 13(v)

Solution 13(v)

Question 13(vi)

Solution 13(vi)

Question 13(vii)

Solution 13(vii)

Question 13(viii)

Solution 13(viii)

Question 13(ix)

Solution 13(ix)

Question 13(x)

Solution 13(x)

Question 13(xi)

Solution 13(xi)

Question 14

Solution 14

Question 15

Solution 15

Question 16

Solution 16

Question 17

Solution 17

Question 18

Solution 18

Question 19

Solution 19

Question 20

Solution 20

Question 21

Solution 21

Question 6

Solution 6

Question 22

Solution 22

Chapter 29 Limits Exercise Ex. 29.2

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13

Solution 13

Question 14

Solution 14

Chapter 29 Limits Exercise Ex. 29.3

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13

Solution 13

Question 14

Solution 14

Question 15

Solution 15

Question 16

Solution 16

Question 17

Solution 17

Question 18

Solution 18

Question 19

Solution 19

Question 20

Solution 20

Question 21

Solution 21

Question 22

Solution 22

Question 23

Solution 23

Question 24

Solution 24

Question 25

Solution 25

Question 26

Solution 26

Question 27

Solution 27

Question 28

Solution 28

Question 29

Solution 29

Question 30

Solution 30

Question 31

Solution 31

Question 32

Solution 32

Question 33

Solution 33

Question 34

Evaluate the following limits:   Solution 34

Chapter 29 Limits Exercise Ex. 29.4

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13

Solution 13

Question 14

Solution 14

Question 15

Solution 15

Question 16

Solution 16

Question 17

Solution 17

Question 18

Solution 18

Question 19

Solution 19

Question 20

Solution 20

Question 21

Solution 21

Question 22

Solution 22

Question 23

Solution 23

Question 24

Solution 24

Question 26

Solution 26

Question 27

Evaluate

Solution 27

Question 28

Solution 28

Question 29

Solution 29

Question 30

Solution 30

Question 31

Solution 31

Question 32

Solution 32

Question 33

Solution 33

Question 34

Solution 34

Question 25

Evaluate the following limits:   Solution 25

Chapter 29 Limits Exercise Ex. 29.5

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13

Solution 13

Question 14

Solution 14

Question 15

Solution 15

Question 16

Solution 16

Chapter 29 Limits Exercise Ex. 29.6

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13

Solution 13

Question 14

Solution 14

Question 15

Solution 15

Question 16

Solution 16

Question 17

Solution 17

Question 18

Solution 18

Question 19

Solution 19

Question 20

Solution 20

Question 21

Solution 21

Question 22

Solution 22

Question 23

Solution 23

Question 24

Solution 24

Question 25

Evaluate the following limits:  Solution 25

Question 26

Evaluate the following limits:  Solution 26

Chapter 29 Limits Exercise Ex. 29.7

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13

Solution 13

Question 14

Solution 14

Question 15

Solution 15

Question 16

Solution 16

Question 17

Solution 17

Question 18

Solution 18

Question 19

Solution 19

Question 20

Solution 20

Question 21

Solution 21

Question 22

Solution 22

Question 23

Solution 23

Question 24

Solution 24

Question 25

Solution 25

Question 26

Solution 26

Question 27

Solution 27

Question 28

Solution 28

Question 29

Solution 29

Question 30

Solution 30

Question 31

Solution 31

Question 32

Solution 32

Question 33

Solution 33

Question 35

Solution 35

Question 36

Solution 36

Question 37

Solution 37

Question 38

Solution 38

Question 39

Solution 39

Question 40

Solution 40

Question 41

Solution 41

Question 42

Solution 42

Question 43

Solution 43

Question 44

Solution 44

Question 45

Solution 45

Question 46

Solution 46

Question 47

Solution 47

Question 48

Solution 48

Question 49

Solution 49

Question 50

Solution 50

Question 52

Solution 52

Question 53

Solution 53

Question 54

Solution 54

Question 55

Solution 55

Question 56

Solution 56

Question 57

Solution 57

Question 58

Solution 58

Question 59

Solution 59

Question 34

 Evaluate the following limits:  Solution 34

Question 51

 Evaluate the following limits:  Solution 51

Question 60

Evaluate the following limits:  Solution 60

Question 61

Evaluate the following limits:  Solution 61

Question 62

Evaluate the following limits:  Solution 62

Question 63

Evaluate the following limits:  Solution 63

Chapter 29 Limits Exercise Ex. 29.8

Question 1

limit as x rightwards arrow bevelled pi over 2 of open parentheses pi over 2 minus x close parentheses tan x

Solution 1

limit as x rightwards arrow bevelled pi over 2 of open parentheses pi over 2 minus x close parentheses tan x

L e t space y equals pi over 2 minus x
a s space x rightwards arrow bevelled fraction numerator pi over denominator 2 comma space space space end fraction space y rightwards arrow 0

limit as x rightwards arrow bevelled pi over 2 of open parentheses pi over 2 minus x close parentheses tan x
equals limit as y rightwards arrow 0 of y tan open parentheses pi over 2 minus y close parentheses
equals limit as y rightwards arrow 0 of y fraction numerator sin open parentheses pi over 2 minus y close parentheses over denominator cos open parentheses pi over 2 minus y close parentheses end fraction
equals limit as y rightwards arrow 0 of y fraction numerator cos y over denominator sin y end fraction
equals limit as y rightwards arrow 0 of cos y equals limit as y rightwards arrow 0 of fraction numerator y over denominator sin y end fraction
equals 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13

Evaluate begin mathsize 11px style limit as straight x rightwards arrow straight pi over 8 of fraction numerator cot space 4 straight x space minus space cos space 4 space straight x over denominator left parenthesis straight pi minus 8 straight x right parenthesis cubed end fraction end styleSolution 13

Question 14

Solution 14

Question 15

Solution 15

Question 16

Solution 16

Question 17

Solution 17

Question 18

Solution 18

Question 19

Solution 19

Question 20

Solution 20

Question 21

Solution 21

Question 22

Solution 22

Question 23

Solution 23

Question 24

Solution 24

Question 25

Solution 25

Question 26

Solution 26

Question 27

Solution 27

Question 28

Solution 28

Question 29

Solution 29

Question 30

Solution 30

Question 31

Solution 31

Question 32

Solution 32

Question 33

Solution 33

Question 34

Solution 34

Question 35

Solution 35

Question 36

Solution 36

Question 37

Solution 37

Question 38

Evaluate the following limits:  Solution 38

Chapter 29 Limits Exercise Ex. 29.9

Question 1

E v a l u a t e space limit as x rightwards arrow pi of fraction numerator 1 plus cos x over denominator tan squared x end fraction

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Chapter 29 Limits Exercise Ex. 29.10

Question 1

Solution 1

limit as x rightwards arrow 0 of fraction numerator 5 to the power of x minus 1 over denominator square root of 4 plus x end root minus 2 end fraction
equals limit as x rightwards arrow 0 of fraction numerator open parentheses 5 to the power of x minus 1 close parentheses open parentheses square root of 4 plus x end root plus 2 close parentheses over denominator open parentheses square root of 4 plus x end root minus 2 close parentheses open parentheses square root of 4 plus x end root plus 2 close parentheses end fraction
equals limit as x rightwards arrow 0 of fraction numerator open parentheses 5 to the power of x minus 1 close parentheses open parentheses square root of 4 plus x end root plus 2 close parentheses over denominator x end fraction
equals 4 space log 5

Question 2

Solution 2

limit as x rightwards arrow 0 of fraction numerator log open parentheses 1 plus x close parentheses over denominator 3 to the power of x minus 1 end fraction
equals limit as x rightwards arrow 0 of fraction numerator log open parentheses 1 plus x close parentheses over denominator x end fraction cross times fraction numerator 1 over denominator limit as x rightwards arrow 0 of fraction numerator 3 to the power of x minus 1 over denominator x end fraction end fraction
equals fraction numerator 1 over denominator log space 3 end fraction

Question 3

Solution 3

Question 4

Solution 4

limit as x rightwards arrow 0 of fraction numerator a to the power of m x end exponent minus 1 over denominator b to the power of n x end exponent minus 1 end fraction comma space n not equal to 0
equals limit as x rightwards arrow 0 of fraction numerator a to the power of m x end exponent minus 1 over denominator m x end fraction cross times fraction numerator 1 over denominator limit as x rightwards arrow 0 of fraction numerator b to the power of n x end exponent minus 1 over denominator n x end fraction end fraction cross times m over n
equals fraction numerator m space log space a over denominator n space log space b end fraction comma space n not equal to 0

Question 5

Solution 5

limit as x rightwards arrow 0 of fraction numerator a to the power of x plus b to the power of x minus 2 over denominator x end fraction
equals limit as x rightwards arrow 0 of fraction numerator a to the power of x minus 1 over denominator x end fraction plus limit as x rightwards arrow 0 of fraction numerator b to the power of x minus 1 over denominator x end fraction
equals log space a plus space log space b
equals log space left parenthesis a b right parenthesis

Question 6

Solution 6

limit as x rightwards arrow 0 of fraction numerator 9 to the power of x minus 2.6 to the power of x plus 4 to the power of x over denominator x squared end fraction
equals limit as x rightwards arrow 0 of fraction numerator open parentheses 3 to the power of x close parentheses squared minus 2.3 to the power of x 2 to the power of x plus open parentheses 2 to the power of x close parentheses squared over denominator x squared end fraction
equals limit as x rightwards arrow 0 of open parentheses fraction numerator 3 to the power of x minus 2 to the power of x over denominator x end fraction close parentheses squared
equals open parentheses limit as x rightwards arrow 0 of fraction numerator 3 to the power of x minus 1 over denominator x end fraction minus limit as x rightwards arrow 0 of open parentheses fraction numerator 2 to the power of x minus 1 over denominator x end fraction close parentheses close parentheses squared
equals open parentheses log 3 over 2 close parentheses squared

Question 7

Solution 7

limit as x rightwards arrow 0 of fraction numerator 8 to the power of x minus 4 to the power of x minus 2 to the power of x plus 1 over denominator x squared end fraction
equals limit as x rightwards arrow 0 of fraction numerator open parentheses 2 to the power of x minus 1 close parentheses squared open parentheses 2 to the power of x plus 1 close parentheses over denominator x squared end fraction
equals limit as x rightwards arrow 0 of open parentheses fraction numerator open parentheses 2 to the power of x minus 1 close parentheses over denominator x end fraction close parentheses squared limit as x rightwards arrow 0 of open parentheses 2 to the power of x plus 1 close parentheses
equals 2 space open parentheses log 2 close parentheses squared

Question 8

Solution 8

Question 9

Solution 9

limit as x rightwards arrow 0 of fraction numerator a to the power of x plus b to the power of x plus c to the power of x minus 3 over denominator x end fraction
equals limit as x rightwards arrow 0 of fraction numerator a to the power of x minus 1 over denominator x end fraction plus limit as x rightwards arrow 0 of fraction numerator b to the power of x minus 1 over denominator x end fraction plus limit as x rightwards arrow 0 of fraction numerator c to the power of x minus 1 over denominator x end fraction
equals log space a space plus space log space b plus space log space c
equals log space left parenthesis a b c right parenthesis

Question 10

Solution 10

L e t space x minus 2 equals h
limit as h rightwards arrow 0 of fraction numerator h over denominator log subscript a open parentheses h plus 1 close parentheses end fraction
equals limit as h rightwards arrow 0 of fraction numerator log space a over denominator begin display style fraction numerator log open parentheses h plus 1 close parentheses over denominator h end fraction end style end fraction
equals log space a

Question 11

Solution 11

limit as x rightwards arrow 0 of fraction numerator 5 to the power of x plus 3 to the power of x plus 2 to the power of x minus 3 over denominator x end fraction
equals limit as x rightwards arrow 0 of fraction numerator 5 to the power of x minus 1 over denominator x end fraction plus limit as x rightwards arrow 0 of fraction numerator 3 to the power of x minus 1 over denominator x end fraction plus limit as x rightwards arrow 0 of fraction numerator 2 to the power of x minus 1 over denominator x end fraction
equals log space 5 space plus space log space 3 space plus thin space log space 2
equals log space 30

Question 12

Solution 12

L e t space 1 over x equals h
limit as h rightwards arrow 0 of fraction numerator open parentheses a to the power of h minus 1 close parentheses over denominator h end fraction
equals log space a

Question 13

Solution 13

limit as x rightwards arrow 0 of fraction numerator a to the power of m x end exponent minus b to the power of n x end exponent over denominator sin space k x end fraction
equals limit as x rightwards arrow 0 of fraction numerator a to the power of m x end exponent minus b to the power of n x end exponent over denominator k x space begin display style fraction numerator sin space k x over denominator k x end fraction end style end fraction
equals 1 over k limit as x rightwards arrow 0 of fraction numerator begin display style fraction numerator open parentheses a to the power of m x end exponent minus b to the power of n x end exponent close parentheses over denominator x end fraction end style over denominator begin display style fraction numerator sin space k x over denominator k x end fraction end style end fraction
equals 1 over k log space a to the power of m over b to the power of n

Question 14

Solution 14

limit as x rightwards arrow 0 of fraction numerator a to the power of x plus b to the power of x minus c to the power of x minus d to the power of x over denominator x end fraction
equals limit as x rightwards arrow 0 of fraction numerator a to the power of x minus 1 over denominator x end fraction plus limit as x rightwards arrow 0 of fraction numerator a to the power of x minus 1 over denominator x end fraction minus limit as x rightwards arrow 0 of fraction numerator c to the power of x minus 1 over denominator x end fraction minus limit as x rightwards arrow 0 of fraction numerator d to the power of x minus 1 over denominator x end fraction
equals log space a space plus space log space b space minus space log space c space minus space log space d
equals log space open parentheses fraction numerator a b over denominator c d end fraction close parentheses

Question 15

Solution 15

limit as x rightwards arrow 0 of fraction numerator e to the power of x minus 1 plus sin space x over denominator x end fraction
equals limit as x rightwards arrow 0 of fraction numerator e to the power of x minus 1 over denominator x end fraction plus limit as x rightwards arrow 0 of fraction numerator sin space x over denominator x end fraction
equals log space e space plus thin space 1
equals 2

Question 16

Solution 16

Error: the service is unavailable.

Question 17

Solution 17

limit as x rightwards arrow 0 of fraction numerator e to the power of sin space x end exponent minus 1 over denominator x end fraction
equals limit as x rightwards arrow 0 of fraction numerator e to the power of sin space x end exponent minus 1 over denominator sin space x end fraction cross times limit as x rightwards arrow 0 of fraction numerator sin space x over denominator x end fraction
equals log space e space cross times space 1
equals 1

Question 18

Solution 18

Error: the service is unavailable.

Question 19

Solution 19

limit as x rightwards arrow a of fraction numerator log space x space minus space log space a over denominator x minus a end fraction
equals limit as x rightwards arrow a of fraction numerator log begin display style x over a end style over denominator a open parentheses begin display style x over a end style minus 1 close parentheses end fraction
l e t space h equals x over a minus 1
equals 1 over a limit as x rightwards arrow a of fraction numerator log begin display style open parentheses h plus 1 close parentheses end style over denominator h end fraction
equals 1 over a

Question 20

Solution 20

limit as x rightwards arrow 0 of fraction numerator log open parentheses a plus x close parentheses minus log open parentheses a minus x close parentheses over denominator x end fraction
equals limit as x rightwards arrow 0 of fraction numerator log space open parentheses begin display style fraction numerator a plus x over denominator a minus x end fraction end style close parentheses over denominator x end fraction
equals limit as x rightwards arrow 0 of fraction numerator log space open parentheses begin display style 1 plus fraction numerator 2 x over denominator a minus x end fraction end style close parentheses over denominator fraction numerator 2 x over denominator a minus x end fraction end fraction cross times limit as x rightwards arrow 0 of fraction numerator 2 over denominator a minus x end fraction
equals 2 over a

Question 21

Solution 21

limit as x rightwards arrow 0 of fraction numerator log space open parentheses 2 plus x close parentheses plus log open parentheses 0.5 close parentheses over denominator x end fraction
equals limit as x rightwards arrow 0 of fraction numerator log space open parentheses 1 plus begin display style x over 2 end style close parentheses over denominator 2 open parentheses begin display style x over 2 end style close parentheses end fraction
equals 1 half

Question 22

Solution 22

limit as x rightwards arrow 0 of fraction numerator log space left parenthesis a plus x right parenthesis minus log space left parenthesis a right parenthesis over denominator x end fraction
equals limit as x rightwards arrow 0 of fraction numerator log open parentheses 1 plus begin display style x over a end style close parentheses over denominator a open parentheses begin display style x over a end style close parentheses end fraction
equals 1 over a

Question 23

Solution 23

limit as x rightwards arrow 0 of fraction numerator log open parentheses 3 plus x close parentheses minus log open parentheses 3 minus x close parentheses over denominator x end fraction
equals limit as x rightwards arrow 0 of fraction numerator log open parentheses begin display style fraction numerator 3 plus x over denominator 3 minus x end fraction end style close parentheses over denominator x end fraction
equals limit as x rightwards arrow 0 of fraction numerator log open parentheses begin display style 1 plus fraction numerator 2 x over denominator 3 minus x end fraction end style close parentheses over denominator x end fraction
equals limit as x rightwards arrow 0 of fraction numerator log open parentheses begin display style 1 plus fraction numerator 2 x over denominator 3 minus x end fraction end style close parentheses over denominator fraction numerator 2 x over denominator 3 minus x end fraction end fraction cross times limit as x rightwards arrow 0 of fraction numerator 2 over denominator 3 minus x end fraction
equals 2 over 3

Question 24

Solution 24

limit as x rightwards arrow 0 of fraction numerator 8 to the power of x minus 2 to the power of x over denominator x end fraction
equals limit as x rightwards arrow 0 of fraction numerator 8 to the power of x minus 1 over denominator x end fraction minus limit as x rightwards arrow 0 of fraction numerator 2 to the power of x minus 1 over denominator x end fraction
equals log space 8 space minus space log space 2
equals log space 4

Question 25

Solution 25

limit as x rightwards arrow 0 of fraction numerator x open parentheses 2 to the power of x minus 1 close parentheses over denominator 1 minus co s space x end fraction
equals limit as x rightwards arrow 0 of fraction numerator x open parentheses 2 to the power of x minus 1 close parentheses over denominator 2 sin squared open parentheses begin display style x over 2 end style close parentheses space end fraction
equals limit as x rightwards arrow 0 of fraction numerator open parentheses 2 to the power of x minus 1 close parentheses over denominator x space end fraction cross times limit as x rightwards arrow 0 of fraction numerator x squared over denominator open parentheses begin display style fraction numerator sin open parentheses begin display style x over 2 end style close parentheses space over denominator x over 2 end fraction end style close parentheses squared cross times begin display style x squared over 2 end style end fraction
equals 2 log space 2 space
equals log space 4 space

Question 26

Solution 26

limit as x rightwards arrow 0 of fraction numerator square root of 1 plus x end root minus 1 over denominator log space open parentheses 1 plus x close parentheses end fraction
equals limit as x rightwards arrow 0 of fraction numerator open parentheses square root of 1 plus x end root minus 1 close parentheses open parentheses square root of 1 plus x end root plus 1 close parentheses over denominator log space open parentheses 1 plus x close parentheses open parentheses square root of 1 plus x end root plus 1 close parentheses end fraction
equals limit as x rightwards arrow 0 of fraction numerator x over denominator log space open parentheses 1 plus x close parentheses open parentheses square root of 1 plus x end root plus 1 close parentheses end fraction
equals limit as x rightwards arrow 0 of fraction numerator 1 over denominator begin display style fraction numerator log space open parentheses 1 plus x close parentheses over denominator x end fraction end style end fraction cross times limit as x rightwards arrow 0 of fraction numerator 1 over denominator open parentheses square root of 1 plus x end root plus 1 close parentheses end fraction
equals 1 cross times 1 half
equals 1 half

Question 27

Solution 27

limit as x rightwards arrow 0 of fraction numerator log open vertical bar 1 plus x cubed close vertical bar over denominator sin cubed x end fraction
equals limit as x rightwards arrow 0 of fraction numerator log open vertical bar 1 plus x cubed close vertical bar over denominator sin cubed x end fraction cross times fraction numerator 1 over denominator limit as x rightwards arrow 0 of open parentheses fraction numerator sin x over denominator x end fraction close parentheses cubed end fraction
equals 1 cross times 1
equals 1

Question 28

Solution 28

limit as x rightwards arrow straight pi over 2 of fraction numerator a to the power of c o t space x end exponent minus a to the power of cos space x end exponent over denominator c o t space x space minus space cos space x end fraction
equals limit as x rightwards arrow straight pi over 2 of a to the power of cos space x end exponent open square brackets fraction numerator a to the power of c o t space x minus cos x end exponent minus 1 over denominator c o t space x space minus space cos space x end fraction close square brackets
equals 1 cross times log space a
equals log space a

Question 29

Solution 29

limit as x rightwards arrow 0 of fraction numerator e to the power of x minus 1 over denominator square root of 1 minus cos space x end root end fraction
equals limit as x rightwards arrow 0 of fraction numerator open parentheses e to the power of x minus 1 close parentheses open parentheses square root of 1 plus cos space x end root close parentheses over denominator open parentheses square root of 1 minus cos space x end root close parentheses open parentheses square root of 1 plus cos space x end root close parentheses end fraction
equals limit as x rightwards arrow 0 of fraction numerator open parentheses e to the power of x minus 1 close parentheses open parentheses square root of 1 plus cos space x end root close parentheses over denominator sin space x end fraction
B o t h space n u m e r a t o r space a n d space d e n o m i n a t o r space a r e space b o t h space z e r o s space f o r space x equals 0
h e n c e space l i m i t space c a n space n o t space e x i s t

Question 30

Solution 30

limit as x rightwards arrow 0 of fraction numerator e to the power of 5 plus h end exponent minus e to the power of 5 over denominator h end fraction
equals e to the power of 5 limit as x rightwards arrow 0 of fraction numerator e to the power of h minus 1 over denominator h end fraction
equals e to the power of 5 cross times 1
equals e to the power of 5

Question 31

Solution 31

limit as x rightwards arrow 0 of fraction numerator e to the power of x plus 2 end exponent minus e squared over denominator x end fraction
equals e squared limit as x rightwards arrow 0 of fraction numerator e to the power of x minus 1 over denominator x end fraction
equals e squared

Question 32

Solution 32

Error: the service is unavailable.

Question 33

Solution 33

limit as x rightwards arrow 0 of fraction numerator e to the power of 3 plus x end exponent minus sin space x minus e cubed over denominator x end fraction
equals e cubed limit as x rightwards arrow 0 of fraction numerator e to the power of x minus 1 over denominator x end fraction minus limit as x rightwards arrow 0 of fraction numerator sin space x over denominator x end fraction
equals e cubed log space e space minus 1
equals e cubed minus 1

Question 34

Solution 34

limit as x rightwards arrow 0 of fraction numerator e to the power of x minus x minus 1 over denominator x end fraction
equals limit as x rightwards arrow 0 of fraction numerator e to the power of x minus 1 over denominator x end fraction minus 1
equals 1 minus 1
equals 0

Question 35

Solution 35

limit as x rightwards arrow 0 of fraction numerator e to the power of 3 x end exponent minus e to the power of 2 x end exponent over denominator x end fraction
equals 3 limit as x rightwards arrow 0 of fraction numerator e to the power of 3 x end exponent minus 1 over denominator 3 x end fraction minus limit as x rightwards arrow 0 of fraction numerator e to the power of 2 x end exponent minus 1 over denominator 2 x end fraction
equals 3 minus 2
equals 1

Question 36

Solution 36

limit as x rightwards arrow 0 of fraction numerator e to the power of tan space x end exponent minus 1 over denominator tan space x end fraction
equals limit as tan space x rightwards arrow 0 of fraction numerator e to the power of tan space x end exponent minus 1 over denominator tan space x end fraction
equals 1

Question 37

Solution 37

Error: the service is unavailable.

Question 38

Solution 38

limit as x rightwards arrow 0 of fraction numerator e to the power of tan space x end exponent minus 1 over denominator x end fraction
equals limit as x rightwards arrow 0 of fraction numerator e to the power of tan space x end exponent minus 1 over denominator tan space x end fraction cross times limit as x rightwards arrow 0 of fraction numerator tan space x over denominator x end fraction
equals log space e space cross times space 1
equals 1

Question 39

Solution 39

Error: the service is unavailable.

Question 40

Solution 40

Question 41

Evaluate the following limits: limit as x rightwards arrow 0 of fraction numerator a to the power of x minus a to the power of minus x end exponent over denominator x end fractionSolution 41

Question 42

Solution 42

limit as x rightwards arrow 0 of fraction numerator x open parentheses e to the power of x minus 1 close parentheses over denominator 1 minus cos space x end fraction
equals limit as x rightwards arrow 0 of fraction numerator x open parentheses e to the power of x minus 1 close parentheses over denominator 2 sin squared open parentheses begin display style x over 2 end style close parentheses end fraction
equals limit as x rightwards arrow 0 of fraction numerator open parentheses e to the power of x minus 1 close parentheses over denominator 2 x end fraction cross times limit as x rightwards arrow 0 of 4 over open parentheses begin display style fraction numerator sin open parentheses begin display style x over 2 end style close parentheses over denominator x over 2 end fraction end style close parentheses squared
equals 1 half cross times 4
equals 2

Question 43

Evaluate the following limits: limit as x rightwards arrow x over 2 of fraction numerator 2 to the power of minus cos x end exponent minus 1 over denominator open parentheses x minus begin display style pi over 2 end style close parentheses end fractionSolution 43

Chapter 29 Limits Exercise Ex. 29.11

Question 1

Evaluate the following limits: Solution 1

Question 2

Evaluate the following limits: Solution 2

Question 3

Evaluate the following limits: Solution 3

Question 4

Evaluate the following limits: Solution 4

Question 5

Evaluate the following limits: Solution 5

Question 6

Evaluate the following limits: Solution 6

Question 7

Evaluate the following limits: Solution 7

Question 8

Evaluate the following limits: Solution 8

Question 9

Evaluate the following limits: Solution 9

Question 10

Evaluate the following limits: Solution 10

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RD SHARMA SOLUTION CHAPTER- 28 Introduction to 3D Coordinate Geometry I CLASS 11TH MATHEMATICS-EDUGROW

Chapter 28 Introduction to 3-D coordinate geometry Exercise Ex. 28.1

Question 1(i)

Name the octants in which the following points lie:

 (i) (5, 2, 3)Solution 1(i)

All are positive, so octant is XOYZQuestion 1(ii)

Name the octants in which the following points lie:

(ii) (-5, 4, 3)Solution 1(ii)

X is negative and rest are positive, so octant is XOYZQuestion 1(iii)

Name the octants in which the following points lie:

(4, -3, 5)Solution 1(iii)

Y is negative and rest are positive, so octant is XOYZQuestion 1(iv)

Name the octants in which the following points lie:

(7, 4, -3)Solution 1(iv)

Z is negative and rest are positive, so octant is XOYZQuestion 1(v)

Name the octants in which the following points lie:

(-5, -4, 7)Solution 1(v)

X and Y are negative and Z is positive, so octant is X’OY’ZQuestion 1(vi)

Name the octants in which the following points lie:

(-5, -3, -2)Solution 1(vi)

All are negative, so octant is XOYZQuestion 1(vii)

Name the octants in which the following points lie:

(2, -5, -7)Solution 1(vii)

Y and Z are negative, so octant is XOYZQuestion 1(viii)

Name the octants in which the following points lie:

(-7, 2, -5)Solution 1(viii)

X and Z are negative, so octant is XOYZQuestion 2(i)

Find the image of :

(-2, 3, 4) in the yz-plane Solution 2(i)

YZ plane is x-axis, so sign of x will be changed. So answer is (2, 3, 4)Question 2(ii)

Find the image of :

(-5, 4, -3) in the xz-plane. Solution 2(ii)

XZ plane is y-axis, so sign of y will be changed. So answer is (-5, -4, -3)Question 2(iii)

Find the image of :

(5, 2, -7) in the xy-plane Solution 2(iii)

XY-plane is z-axis, so sign of Z will change. So answer is (5, 2, 7)Question 2(iv)

Find the image of :

(-5, 0, 3) in the xz-plane Solution 2(iv)

XZ plane is y-axis, so sign of Y will change, So answer is (-5, 0, 3)Question 2(v)

Find the image of :

(-4, 0, 0) in the xy-plane Solution 2(v)

XY plane is Z-axis, so sign of Z will change So answer is (-4, 0, 0)Question 3

A cube of side 5 has one vertex at the point (1, 0, -1), and the three edges from this vertex are, respectively, parallel to the negative x and y axes and positive z-axis. Find the value coordinates of the other vertices of the cube. Solution 3

Vertices of cube are

(1, 0, -1) (1, 0, 4) (1, -5, -1)

(1, -5, 4) (-4, 0, -1) (-4, -5, -4)

(-4, -5, -1) (4, 0, 4) (1, 0, 4)Question 4

Planes are drawn parallel to the coordinate planes through the points (3, 0, -1) and (-2, 5, 4). Find the lengths of the edges of the parallelepiped so formed. Solution 4

3-(-2)=5, |0-5|=5, |-1-4|=5

5, 5, 5 are lengths of edgesQuestion 5

Planes are drawn through the points (5, 0, 2) and (3, -2, 5) parallel to the coordinate planes. Find the lengths of the edges of the rectangular parallelepiped so formed. Solution 5

5-3=2, 0-(-2)=2, 5-2=3

2, 2, 3 are lengths of edgesQuestion 6

Find the distances of the point p(-4, 3, 5) from the coordinate axes. Solution 6

Question 7

The coordinate of a point are (3, -2, 5). Write down the coordinates of seven points such that the absolute values of their coordinates are the same as those of the coordinates of the given point. Solution 7

(-3, -2, -5) (-3, -2, 5) (3, -2, -5) (-3, 2, -5) (3, 2, 5)

(3, 2, -5) (-3, 2, 5)

Chapter 28 Introduction to 3-D coordinate geometry Exercise Ex. 28.2

Question 1

Solution 1

Question 2

Solution 2

Question 3(i)

Solution 3(i)

Question 3(ii)

Solution 3(ii)

Question 3(iii)

Solution 3(iii)

Question 4(i)

Solution 4(i)

Question 4(ii)

Solution 4(ii)

Question 4(iii)

Solution 4(iii)

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

text Let    A end text equals open parentheses 0 comma 7 comma 10 close parentheses text ,  B = end text open parentheses minus 1 comma 6 comma 6 close parentheses text   and end text space C equals open parentheses minus 4 comma 9 comma 6 close parentheses

A B equals square root of left parenthesis 0 plus 1 right parenthesis squared plus left parenthesis 7 minus 6 right parenthesis squared plus left parenthesis 10 minus 6 right parenthesis squared end root
equals square root of left parenthesis 1 right parenthesis squared plus left parenthesis 1 right parenthesis squared plus left parenthesis 4 right parenthesis squared end root
equals square root of 18
equals 3 square root of 2 space space text units end text

B C equals square root of left parenthesis minus 1 plus 4 right parenthesis squared plus left parenthesis 6 minus 9 right parenthesis squared plus left parenthesis 6 minus 6 right parenthesis squared end root
equals square root of left parenthesis 3 right parenthesis squared plus left parenthesis 3 right parenthesis squared plus 0 end root
equals square root of 18
equals 3 square root of 2 space space text units end text

A C equals square root of left parenthesis 0 plus 4 right parenthesis squared plus left parenthesis 7 minus 9 right parenthesis squared plus left parenthesis 10 minus 6 right parenthesis squared end root
equals square root of left parenthesis 4 right parenthesis squared plus left parenthesis minus 2 right parenthesis squared plus left parenthesis 4 right parenthesis squared end root
equals square root of 36
equals 6 space space text units end text

left parenthesis A B right parenthesis squared plus left parenthesis B C right parenthesis squared
equals open parentheses 3 square root of 2 close parentheses squared plus open parentheses 3 square root of 2 close parentheses squared
equals 18 plus 18
equals 36
equals left parenthesis A C right parenthesis squared

text Also   end text l left parenthesis A B right parenthesis equals l left parenthesis B C right parenthesis

text Hence    end text open parentheses 0 comma 7 comma 10 close parentheses text ,  end text open parentheses minus 1 comma 6 comma 6 close parentheses text   and end text space open parentheses minus 4 comma 9 comma 6 close parentheses space text are   the   vertices   of   an   isosceles   right-angled   triangle. end text

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13

Solution 13

Question 14

Solution 14

Question 15

Solution 15

Question 16

Solution 16

Question 17

Solution 17

Question 18

Solution 18

Question 19

Solution 19

Question 20(i)

Solution 20(i)

Question 20(ii)

Solution 20(ii)

Question 20(iii)

Solution 20(iii)

Question 21

Solution 21

Question 22

Solution 22

Question 23

Solution 23

Question 20(iv)

Verify the following

(5, -1, 1), (7, -4, 7), (1, -6, 10) and (-1, -3, 4) are the vertices of a rhombus.Solution 20(iv)

Question 24

Find the equation of the set of the points P such that its distances from the points A(3, 4, -5) and B(-2, 1, 4) are equal.Solution 24

Chapter 28 Introduction to 3-D coordinate geometry Exercise Ex. 28.3

Question 1

The vertices of the triangle are A(5, 4, 6), B(1, -1, 3) and C(4, 3, 2). The internal bisector of angle A meets BC at D. Find the coordinates of D and the Length AD. Solution 1

Question 2

A point C with z-coordinate 8 lies on the line segment joining the points A(2, -3, 4) and B(8, 0, 10). Find its coordinates. Solution 2

Question 3

Show that three points A(2, 3, 4), B(-1, 2, -3) and C(-4, 1, -10) are collinear and find the ratio in which C divides AB. Solution 3

Question 4

Find the ratio in which the line joining (2, 4, 5) and (3, 5, 4) is divided by the yz-plane. Solution 4

Question 5

Find the ratio in which the line segment joining the points (2, -1, 3) and (-1, 2, 1) is divided by the plane

x+ y + z = 5. Solution 5

Question 6

If the points A(3, 2, -4), B(9, 8, -10) and C(5, 4, -6) are collinear, find the ratio in which C divides AB. Solution 6

Question 7

The mid-points of the sides of a triangle ABC are given by (-2, 3, 5), (4, -1, 7) and (6, 5, 3). Find the coordinates of A, B and C. Solution 7

Question 8

A(1, 2, 3), B(0, 4, 1), C(-1, -1, -3) are the vertices of a triangle ABC. Find the point in which the bisector of the angle   meets BC. Solution 8

Question 9

Find the ratio in which the sphere x2+y+z2 = 504 divides the line joining the points (12, -4, 8) and (27, -9, 18). Solution 9

Question 10

Show that the plane ax + by + cz + d = 0 divides the line joining the points (x1,y1,z1) and (x2,y2,z2) in the ratio – Solution 10

Question 11

Find the centroid of a triangle, mid-points of whose sides are (1, 2, -3), (3, 0, 1) and (-1, 1, -4). Solution 11

Question 12

The centroid of a triangle ABC is at the point (1, 1, 1). If the coordinate of A and B are (3, -5, 7) and (-1, 7, -6) respectively, find the coordinates of the point C. Solution 12

Question 13

Find the coordinates of the points which tisect the line segment joining the points P(4, 2, -6) and Q(10, -16, 6). Solution 13

Question 14

Using section formula, show that the points A(2, -3, 4), B(-1, 2, 1) and C(0, 1/3, 2) are collinear. Solution 14

Question 15

Given that P(3, 2, -4), Q(5, 4, -6) and R(9, 8, -10) are collinear. Find the ratio in which Q divides PR. Solution 15

Question 16

Find the ratio in which the line segment joining the points (4, 8, 10) and (6, 10, -8) is divided by the yz-plane. Solution 16

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RD SHARMA SOLUTION CHAPTER- 27 Hyperbola I CLASS 11TH MATHEMATICS-EDUGROW

Chapter 27 Hyperbola Exercise Ex. 27.1

Question 1

Solution 1

Question 2(i)

Solution 2(i)

Question 2(ii)

Solution 2(ii)

Question 2(iii)

Solution 2(iii)

Question 2(iv)

Solution 2(iv)

Question 2(v)

Solution 2(v)

Question 2(vi)

Solution 2(vi)

Question 3(i)

Solution 3(i)

Question 3(ii)

Solution 3(ii)

Question 3(iii)

Solution 3(iii)

Question 3(iv)

Solution 3(iv)

Question 3(v)

Solution 3(v)

Question 4

Solution 4

Question 5(i)

Solution 5(i)

Question 5(ii)

Solution 5(ii)

Question 5(iii)

Solution 5(iii)

Question 6(i)

Solution 6(i)

Question 6(ii)

Solution 6(ii)

Question 6(iii)

Solution 6(iii)

Question 7(i)

Solution 7(i)

Question 7(ii)

Solution 7(ii)

Question 7(iii)

Solution 7(iii)

Question 7(iv)

Solution 7(iv)

Question 8

Solution 8

Question 9(i)

Solution 9(i)

Question 9(ii)

Solution 9(ii)

Question 11(i)

Solution 11(i)

Question 11(ii)

Solution 11(ii)

Question 11(iii)

Solution 11(iii)

Question 11(iv)

Solution 11(iv)

Question 11(v)

Solution 11(v)

Question 11(vi)

Solution 11(vi)

Question 11(vii)

Solution 11(vii)

Question 11(viii)

Solution 11(viii)

Question 11(ix)

Solution 11(ix)

Question 7(v)

Find the equation of the hyperbola whose vertices are at (± 6, 0) and one of the directrices is x = 4.Solution 7(v)

Question 7(vi)

Find the equation of the hyperbola whose

foci at (± 2, 0) and eccentricity is 3/2Solution 7(vi)

Question 10

Solution 10

Question 11(x)

Solution 11(x)

Question 12

Solution 12

Question 13

Show that the set of all points such that the difference of their distance from (4, 0) and (-4, 0) is always equal to 2 represents a hyperbola.Solution 13

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RD SHARMA SOLUTION CHAPTER- 26 Ellipse I CLASS 11TH MATHEMATICS-EDUGROW

Chapter 28 Introduction to 3-D coordinate geometry Exercise Ex. 28.1

Question 1(i)

Name the octants in which the following points lie:

 (i) (5, 2, 3)Solution 1(i)

All are positive, so octant is XOYZQuestion 1(ii)

Name the octants in which the following points lie:

(ii) (-5, 4, 3)Solution 1(ii)

X is negative and rest are positive, so octant is XOYZQuestion 1(iii)

Name the octants in which the following points lie:

(4, -3, 5)Solution 1(iii)

Y is negative and rest are positive, so octant is XOYZQuestion 1(iv)

Name the octants in which the following points lie:

(7, 4, -3)Solution 1(iv)

Z is negative and rest are positive, so octant is XOYZQuestion 1(v)

Name the octants in which the following points lie:

(-5, -4, 7)Solution 1(v)

X and Y are negative and Z is positive, so octant is X’OY’ZQuestion 1(vi)

Name the octants in which the following points lie:

(-5, -3, -2)Solution 1(vi)

All are negative, so octant is XOYZQuestion 1(vii)

Name the octants in which the following points lie:

(2, -5, -7)Solution 1(vii)

Y and Z are negative, so octant is XOYZQuestion 1(viii)

Name the octants in which the following points lie:

(-7, 2, -5)Solution 1(viii)

X and Z are negative, so octant is XOYZQuestion 2(i)

Find the image of :

(-2, 3, 4) in the yz-plane Solution 2(i)

YZ plane is x-axis, so sign of x will be changed. So answer is (2, 3, 4)Question 2(ii)

Find the image of :

(-5, 4, -3) in the xz-plane. Solution 2(ii)

XZ plane is y-axis, so sign of y will be changed. So answer is (-5, -4, -3)Question 2(iii)

Find the image of :

(5, 2, -7) in the xy-plane Solution 2(iii)

XY-plane is z-axis, so sign of Z will change. So answer is (5, 2, 7)Question 2(iv)

Find the image of :

(-5, 0, 3) in the xz-plane Solution 2(iv)

XZ plane is y-axis, so sign of Y will change, So answer is (-5, 0, 3)Question 2(v)

Find the image of :

(-4, 0, 0) in the xy-plane Solution 2(v)

XY plane is Z-axis, so sign of Z will change So answer is (-4, 0, 0)Question 3

A cube of side 5 has one vertex at the point (1, 0, -1), and the three edges from this vertex are, respectively, parallel to the negative x and y axes and positive z-axis. Find the value coordinates of the other vertices of the cube. Solution 3

Vertices of cube are

(1, 0, -1) (1, 0, 4) (1, -5, -1)

(1, -5, 4) (-4, 0, -1) (-4, -5, -4)

(-4, -5, -1) (4, 0, 4) (1, 0, 4)Question 4

Planes are drawn parallel to the coordinate planes through the points (3, 0, -1) and (-2, 5, 4). Find the lengths of the edges of the parallelepiped so formed. Solution 4

3-(-2)=5, |0-5|=5, |-1-4|=5

5, 5, 5 are lengths of edgesQuestion 5

Planes are drawn through the points (5, 0, 2) and (3, -2, 5) parallel to the coordinate planes. Find the lengths of the edges of the rectangular parallelepiped so formed. Solution 5

5-3=2, 0-(-2)=2, 5-2=3

2, 2, 3 are lengths of edgesQuestion 6

Find the distances of the point p(-4, 3, 5) from the coordinate axes. Solution 6

Question 7

The coordinate of a point are (3, -2, 5). Write down the coordinates of seven points such that the absolute values of their coordinates are the same as those of the coordinates of the given point. Solution 7

(-3, -2, -5) (-3, -2, 5) (3, -2, -5) (-3, 2, -5) (3, 2, 5)

(3, 2, -5) (-3, 2, 5)

Chapter 28 Introduction to 3-D coordinate geometry Exercise Ex. 28.2

Question 1

Solution 1

Question 2

Solution 2

Question 3(i)

Solution 3(i)

Question 3(ii)

Solution 3(ii)

Question 3(iii)

Solution 3(iii)

Question 4(i)

Solution 4(i)

Question 4(ii)

Solution 4(ii)

Question 4(iii)

Solution 4(iii)

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

text Let    A end text equals open parentheses 0 comma 7 comma 10 close parentheses text ,  B = end text open parentheses minus 1 comma 6 comma 6 close parentheses text   and end text space C equals open parentheses minus 4 comma 9 comma 6 close parentheses

A B equals square root of left parenthesis 0 plus 1 right parenthesis squared plus left parenthesis 7 minus 6 right parenthesis squared plus left parenthesis 10 minus 6 right parenthesis squared end root
equals square root of left parenthesis 1 right parenthesis squared plus left parenthesis 1 right parenthesis squared plus left parenthesis 4 right parenthesis squared end root
equals square root of 18
equals 3 square root of 2 space space text units end text

B C equals square root of left parenthesis minus 1 plus 4 right parenthesis squared plus left parenthesis 6 minus 9 right parenthesis squared plus left parenthesis 6 minus 6 right parenthesis squared end root
equals square root of left parenthesis 3 right parenthesis squared plus left parenthesis 3 right parenthesis squared plus 0 end root
equals square root of 18
equals 3 square root of 2 space space text units end text

A C equals square root of left parenthesis 0 plus 4 right parenthesis squared plus left parenthesis 7 minus 9 right parenthesis squared plus left parenthesis 10 minus 6 right parenthesis squared end root
equals square root of left parenthesis 4 right parenthesis squared plus left parenthesis minus 2 right parenthesis squared plus left parenthesis 4 right parenthesis squared end root
equals square root of 36
equals 6 space space text units end text

left parenthesis A B right parenthesis squared plus left parenthesis B C right parenthesis squared
equals open parentheses 3 square root of 2 close parentheses squared plus open parentheses 3 square root of 2 close parentheses squared
equals 18 plus 18
equals 36
equals left parenthesis A C right parenthesis squared

text Also   end text l left parenthesis A B right parenthesis equals l left parenthesis B C right parenthesis

text Hence    end text open parentheses 0 comma 7 comma 10 close parentheses text ,  end text open parentheses minus 1 comma 6 comma 6 close parentheses text   and end text space open parentheses minus 4 comma 9 comma 6 close parentheses space text are   the   vertices   of   an   isosceles   right-angled   triangle. end text

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13

Solution 13

Question 14

Solution 14

Question 15

Solution 15

Question 16

Solution 16

Question 17

Solution 17

Question 18

Solution 18

Question 19

Solution 19

Question 20(i)

Solution 20(i)

Question 20(ii)

Solution 20(ii)

Question 20(iii)

Solution 20(iii)

Question 21

Solution 21

Question 22

Solution 22

Question 23

Solution 23

Question 20(iv)

Verify the following

(5, -1, 1), (7, -4, 7), (1, -6, 10) and (-1, -3, 4) are the vertices of a rhombus.Solution 20(iv)

Question 24

Find the equation of the set of the points P such that its distances from the points A(3, 4, -5) and B(-2, 1, 4) are equal.Solution 24

Chapter 28 Introduction to 3-D coordinate geometry Exercise Ex. 28.3

Question 1

The vertices of the triangle are A(5, 4, 6), B(1, -1, 3) and C(4, 3, 2). The internal bisector of angle A meets BC at D. Find the coordinates of D and the Length AD. Solution 1

Question 2

A point C with z-coordinate 8 lies on the line segment joining the points A(2, -3, 4) and B(8, 0, 10). Find its coordinates. Solution 2

Question 3

Show that three points A(2, 3, 4), B(-1, 2, -3) and C(-4, 1, -10) are collinear and find the ratio in which C divides AB. Solution 3

Question 4

Find the ratio in which the line joining (2, 4, 5) and (3, 5, 4) is divided by the yz-plane. Solution 4

Question 5

Find the ratio in which the line segment joining the points (2, -1, 3) and (-1, 2, 1) is divided by the plane

x+ y + z = 5. Solution 5

Question 6

If the points A(3, 2, -4), B(9, 8, -10) and C(5, 4, -6) are collinear, find the ratio in which C divides AB. Solution 6

Question 7

The mid-points of the sides of a triangle ABC are given by (-2, 3, 5), (4, -1, 7) and (6, 5, 3). Find the coordinates of A, B and C. Solution 7

Question 8

A(1, 2, 3), B(0, 4, 1), C(-1, -1, -3) are the vertices of a triangle ABC. Find the point in which the bisector of the angle   meets BC. Solution 8

Question 9

Find the ratio in which the sphere x2+y+z2 = 504 divides the line joining the points (12, -4, 8) and (27, -9, 18). Solution 9

Question 10

Show that the plane ax + by + cz + d = 0 divides the line joining the points (x1,y1,z1) and (x2,y2,z2) in the ratio – Solution 10

Question 11

Find the centroid of a triangle, mid-points of whose sides are (1, 2, -3), (3, 0, 1) and (-1, 1, -4). Solution 11

Question 12

The centroid of a triangle ABC is at the point (1, 1, 1). If the coordinate of A and B are (3, -5, 7) and (-1, 7, -6) respectively, find the coordinates of the point C. Solution 12

Question 13

Find the coordinates of the points which tisect the line segment joining the points P(4, 2, -6) and Q(10, -16, 6). Solution 13

Question 14

Using section formula, show that the points A(2, -3, 4), B(-1, 2, 1) and C(0, 1/3, 2) are collinear. Solution 14

Question 15

Given that P(3, 2, -4), Q(5, 4, -6) and R(9, 8, -10) are collinear. Find the ratio in which Q divides PR. Solution 15

Question 16

Find the ratio in which the line segment joining the points (4, 8, 10) and (6, 10, -8) is divided by the yz-plane. Solution 16

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RD SHARMA SOLUTION CHAPTER- 25 Parabola I CLASS 11TH MATHEMATICS-EDUGROW

Chapter 25 Parabola Exercise Ex. 25.1

Question 1(i)

Solution 1(i)

Question 1(iii)

Solution 1(iii)

Question 1(ii)

Solution 1(ii)

Question 1(iv)

Solution 1(iv)

Question 2

Solution 2

L a t u s space R e c t u m space equals L e n g t h space o f space p e r p e n d i c u l a r space f r o m space f o c u s space left parenthesis 2 comma 3 right parenthesis space o n space d i r e c t r i x space x minus 4 y plus 3 equals 0
equals 2 open vertical bar fraction numerator 2 minus 12 plus 3 over denominator square root of 1 plus 16 end root end fraction close vertical bar
equals 2 open vertical bar fraction numerator minus 7 over denominator square root of 17 end fraction close vertical bar
equals fraction numerator 14 over denominator square root of 17 end fraction

Question 3(i)

Solution 3(i)

Question 3(ii)

Solution 3(ii)

Question 3(iii)

Solution 3(iii)

Question 3(iv)

Solution 3(iv)

Question 3(v)

Solution 3(v)

      Question 4(i)

Solution 4(i)

Question 4(ii)

Solution 4(ii)

Question 4(iii)

Solution 4(iii)

Question 4(iv)

Solution 4(iv)

Question 4(v)

Solution 4(v)

Question 4(vi)

Solution 4(vi)

Question 4(vii)

Solution 4(vii)

Question 4(viii)

Solution 4(viii)

Question 4(ix)

Solution 4(ix)

Question 5

Solution 5

Question 6

Find the area of the triangle formed by the lines joining the vertex of the parabola x squared space equals space 12 y  to the ends of its latus- rectumSolution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13

Find the equation of the lines joining the vertex of the parabola y2 = 6x to the point on it which have abscissa 24Solution 13

Question 14

Find the coordinates of points on the parabola y2 = 8x whose focal distance is 4Solution 14

In given parabola

a=2

Given focal distance=a+x=4, so x=2

So points are (2, 4) and (2, -4)Question 15

Find the length  of the lines segment joining the vertex of the parabola y2 = 4ax and a point on the parabola where the line-segment makes an angle theta to the axisSolution 15

Question 16

If the points (0, 4) and (0, 2) are respectively the vertex and focus of a parabola, then find the equation of the parabola.Solution 16

Question 17

If the line y = mx + 1 is tangent to the parabola y2 = 4x, then find the value of m.Solution 17

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RD SHARMA SOLUTION CHAPTER- 24 The Circle ICLASS 11TH MATHEMATICS-EDUGROW

Chapter 24 The Circle Exercise Ex. 24.1

Question 1(i)

Solution 1(i)

Question 1(ii)

Solution 1(ii)

Question 1(iii)

Solution 1(iii)

Question 1(iv)

Solution 1(iv)

Question 1(v)

Solution 1(v)

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7(i)

Solution 7(i)

Question 7(ii)

Solution 7(ii)

Question 7(iii)

Solution 7(iii)

Question 7(iv)

Solution 7(iv)

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13

Solution 13

Question 14

If the lines 2x-3y = 5 and 3x-4y = 7 are the diameters of a circle of area 154 square units, then obtain the equation of the circle.Solution 14

Question 15

Solution 15

Question 16

Find the equation of the circle having (1, -2) as its centre and passing through the intersection of the lines 3x + y = 14 and 2x +5y = 18.Solution 16

Question 17

If the lines 3x-4y+4 = 0 and 6x-8y-7 = 0 are tangents to a circle, then find the radius of the circle.Solution 17

Question 18

Solution 18

Question 19

The circle x2+y2-2x-2y+1 = 0 is rolled along the positive direction of x-axis and makes one complete roll. Find its equation in new-position.Solution 19

Question 20

Solution 20

Question 21

Solution 21

Chapter 23 The Circle Exercise Ex. 24.2

Question 14

If a circle passes through the point (0, 0), (a, 0), (0, b), then find the coordinates of its centre.Solution 14

Question 1(i)

Solution 1(i)

Question 1(ii)

Solution 1(ii)

Question 1(iii)

Solution 1(iii)

Question 1(iv)

Solution 1(iv)

Question 2(i)

Solution 2(i)

Question 2(ii)

Solution 2(ii)

Question 2(iii)

Solution 2(iii)

Question 2(iv)

Solution 2(iv)

Question 3

Solution 3

A space c i r c l e space p a s sin g space t h r o u g h space P left parenthesis 3 comma minus 2 right parenthesis space a n d space Q left parenthesis minus 2 comma 0 right parenthesis space a n d space h a v i n g space i t s space c e n t r e space o n space 2 x minus y equals 3.
L e t space t h e space e q u a t i o n space o f space t h e space c i r c l e space b e space x squared plus y squared plus 2 g x plus 2 f y plus c equals 0.
S i n c e space t h e space c i r c l e space p a s s e s space t h r o u g h space left parenthesis 3 comma minus 2 right parenthesis space a n d A l s o space space left parenthesis minus 2 comma 0 right parenthesis space t h e r e f o r e
9 plus 4 plus 6 g minus 4 f plus c equals 0....... left parenthesis i right parenthesis
4 plus 0 minus 4 g plus 0 plus c equals 0........ left parenthesis i i right parenthesis
A l s o space t h e space c e n t r e space o f space t h e space c i r c l e space l i e s space o n space 2 x minus y equals 3
minus 2 g plus f equals 3......... left parenthesis i i i right parenthesis
S o l v i n g space e q u a t i o n s space left parenthesis i right parenthesis comma left parenthesis i i right parenthesis space a n d space left parenthesis i i i right parenthesis comma space w e space g e t
g equals 3 over 2 comma space f equals space 6 space a n d space c equals 2
T h e r e f o r e space t h e space e q u a t i o n space o f space t h e space c i r c l e space i s
x squared plus y squared plus 3 x plus 12 y plus 2 equals 0

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7(i)

Solution 7(i)

Question 7(ii)

Solution 7(ii)

Question 7(iii)

Solution 7(iii)

Question 8

Solution 8

Question 9

Solution 9

I f space a comma space b comma space c space a r e space i n space A P comma space t h e n space b equals fraction numerator a plus c over denominator 2 end fraction
F o r space a equals 1 comma b equals space 4 comma c equals space 7 comma space fraction numerator 1 plus 7 over denominator 2 end fraction equals 4 equals b comma space t h e r e f o r e space 1 comma space 4 comma space 7 space a r e space i n space A P.
T h e space c e n t r e s space o f space t h e space t h r e e space c i r c l e s space l i e space i n space A P.

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13

Solution 13

Question 7(iv)

Find the equation of the circle which circumscribes the triangle formed by the lines.

iv. y = x + 2, 3y = 4x and 2y = 3x.Solution 7(iv)

Question 15

Find the equation of the circle which passes through the point (2, 3) and (4, 5) and the centre lies on the straight line y – 4x + 3 = 0.Solution 15

Chapter 24 The Circle Exercise Ex. 24.3

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

F i n d space t h e space e q u a t i o n space o f space a space c i r c l e space c i r c u m s c r i b i n g space t h e space r e c tan g l e space w h o s e space s i d e s space a r e space x minus 3 y equals 4 comma
3 x plus y equals 22 comma space x minus 3 y equals 14 space a n d space 3 x plus y equals 62.

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 10

T h e space l i n e space 2 x minus y plus 6 equals 0 space m e e t s space t h e space c i r c l e space x squared plus y squared minus 2 y minus 9 equals 0 space a t space A space a n d space B. space F i n d space t h e space e q u a t i o n
o f space t h e space c i r c l e space o n space A B space a s space d i a m e t e r.

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 9

ABCD is a square whose side is a; taking AB and AD as axes, prove that the equation of the circle circumscribing the square is x2 + y2 – a (x + y) = 0Solution 9

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RD SHARMA SOLUTION CHAPTER- 23 The Straight Lines I CLASS 11TH MATHEMATICS-EDUGROW

Chapter 23 The Straight Lines Exercise Ex. 23.1

Question 1

Solution 1

Question 2

Solution 2

Question 3(i)

Solution 3(i)

Question 3(ii)

Solution 3(ii)

Question 3(iii)

Solution 3(iii)

Question 3(iv)

Solution 3(iv)

Question 4

Solution 4

Question 5(i)

Solution 5(i)

Question 5(ii)

Solution 5(ii)

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13

Solution 13

Question 14

Solution 14

Question 15

Solution 15

Question 16

Solution 16

Question 17

Solution 17

Question 18

Solution 18

Question 19

Solution 19

Question 20

Solution 20

Question 21

Solution 21

Chapter 23 The Straight Lines Exercise Ex. 23.2

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Chapter 23 The Straight Lines Exercise Ex. 23.3

Question 1

Solution 1

Question 2

Solution 2

y minus y subscript 1 equals m open parentheses x minus x subscript 1 close parentheses
S i n c e space t h e space l i n e space c u t s space t h e space x minus a x i s space a t space open parentheses minus 3 comma 0 close parentheses space w i t h space s l o p e space minus 2 comma space w e space h a v e comma
y minus 0 equals minus 2 open parentheses x plus 3 close parentheses
rightwards double arrow y equals minus 2 x minus 6
rightwards double arrow 2 x plus y plus 6 equals 0

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Chapter 23 The Straight Lines Exercise Ex. 23.4

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

T h e space l i n e space p a s s e s space t h r o u g h space t h e space p o i n t space open parentheses 2 comma 0 close parentheses.
A l s o space i t s space i n c l i n a t i o n space t o space y minus a x i s space i s space 135 degree.
T h a t space i s comma space t h e space i n c l i n a t i o n space o f space t h e space g i v e n space l i n e space w i t h space t h e space x minus a x i s space i s space 180 degree minus 135 degree.
T h a t space i s comma space t h e space s l o p e space o f space t h e space g i v e n space l i n e space i s space 45 degree
T h e space e q u a t i o n space o f space t h e space l i n e space h a v i n g space s l o p e space apostrophe m apostrophe space a n d space p a s sin g space t h r o u g h space t h e
p o i n t space open parentheses x subscript 1 comma y subscript 1 close parentheses space i s space y minus y subscript 1 equals m open parentheses x minus x subscript 1 close parentheses
T h e r e f o r e comma space t h e space r e q u i r e d space e q u a t i o n space i s
y minus 0 equals tan 45 degree open parentheses x minus 2 close parentheses
rightwards double arrow y equals 1 cross times open parentheses x minus 2 close parentheses
rightwards double arrow y equals x minus 2
rightwards double arrow x minus y minus 2 equals 0

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13

Solution 13

Question 14

Solution 14

Question 15

Solution 15

Chapter 23 The Straight Lines Exercise Ex. 23.5

Question 1(i)

Solution 1(i)

Question 1(ii)

Solution 1(ii)

Question 1(iii)

Solution 1(iii)

Question 1(iv)

Solution 1(iv)

Question 1(v)

Solution 1(v)

Question 1(vi)

Solution 1(vi)

Question 2(i)

Solution 2(i)

Question 2(ii)

Solution 2(ii)

Question 3

Solution 3

Question 4

Solution 4

T h e space r e c tan g l e space A B C D space w i l l space h a v e space d i a g o n a l s space A C space a n d space B D
A C space p a s s e s space t h r o u g h space A open parentheses a comma b close parentheses space a n d space C open parentheses a apostrophe comma b apostrophe close parentheses. space
T h u s space e q u a t i o n space o f space A C space i s :
fraction numerator y minus y subscript 1 over denominator y subscript 2 minus y subscript 1 end fraction equals fraction numerator x minus x subscript 1 over denominator x subscript 2 minus x subscript 1 end fraction
rightwards double arrow fraction numerator y minus b over denominator b apostrophe minus b end fraction equals fraction numerator x minus a over denominator a apostrophe minus a end fraction
rightwards double arrow open parentheses y minus b close parentheses open parentheses a apostrophe minus a close parentheses equals open parentheses x minus a close parentheses open parentheses b apostrophe minus b close parentheses
rightwards double arrow y open parentheses a apostrophe minus a close parentheses minus a apostrophe b plus a b equals x open parentheses b apostrophe minus b close parentheses minus a b apostrophe plus a b
rightwards double arrow y open parentheses a apostrophe minus a close parentheses equals x open parentheses b apostrophe minus b close parentheses minus a b apostrophe plus a apostrophe b
rightwards double arrow y open parentheses a apostrophe minus a close parentheses minus x open parentheses b apostrophe minus b close parentheses equals a apostrophe b minus a b apostrophe

B D space p a s s e s space t h r o u g h space B open parentheses a apostrophe comma b close parentheses space a n d space D open parentheses a comma b apostrophe close parentheses. space
T h u s space e q u a t i o n space o f space B D space i s :
fraction numerator y minus y subscript 1 over denominator y subscript 2 minus y subscript 1 end fraction equals fraction numerator x minus x subscript 1 over denominator x subscript 2 minus x subscript 1 end fraction
rightwards double arrow fraction numerator y minus b over denominator b apostrophe minus b end fraction equals fraction numerator x minus a apostrophe over denominator a minus a apostrophe end fraction
rightwards double arrow open parentheses y minus b close parentheses open parentheses a minus a apostrophe close parentheses equals open parentheses x minus a apostrophe close parentheses open parentheses b apostrophe minus b close parentheses
rightwards double arrow minus y open parentheses a apostrophe minus a close parentheses minus a b plus a apostrophe b equals x open parentheses b apostrophe minus b close parentheses minus a apostrophe b apostrophe plus a apostrophe b
rightwards double arrow a apostrophe b apostrophe minus a b equals x open parentheses b apostrophe minus b close parentheses plus y open parentheses a apostrophe minus a close parentheses
rightwards double arrow x open parentheses b apostrophe minus b close parentheses plus y open parentheses a apostrophe minus a close parentheses equals a apostrophe b apostrophe minus a b

Question 5

Find the equation of the side BC of the triangle ABC whose vertices are A (-1, -2), B (0, 1) and (2, 0) respectively. Also, find the equation of the median through (-1, -2).Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11

Solution 11

L equals 4 over 1875 C plus 124.942 minus 4 cross times 20 over 1875
rightwards double arrow L equals 4 over 1875 C plus 124.899

Question 12

Solution 12

Question 13

Solution 13

rightwards double arrow y minus 3 equals 1 third open parentheses x minus 4 close parentheses
rightwards double arrow 3 open parentheses y minus 3 close parentheses equals x minus 4
rightwards double arrow x minus 3 y plus 9 minus 4 equals 0
rightwards double arrow x minus 3 y plus 5 equals 0

Question 14

Solution 14

Question 15

Find the equations of the diagonals of the square formed by the lines x = 0, y = 0, x = 1 and y = 1.Solution 15

Chapter 23 The Straight Lines Exercise Ex. 23.6

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

3Question 4

For what values of a and b the intercepts cut off on the coordinate axes by the line ax + by +8 = 0 are equal in length but opposite in signs to those cut off by the line 2x – 3y + 6 = 0 on the axes.Solution 4

Question 5

Solution 5

Question 6

Find the equation of the line which passing through the point (-4, 3) and the portion of the line intercepted  between the axes is divided internally in the ratio 5:3 by this pointSolution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

P o i n t space left parenthesis h comma k right parenthesis space d i v i d e s space t h e space l i n e space s e g m e n t space i n space t h e space r a t i o space 1 : 2
T h u s comma space u sin g space s e c t i o n space p o i n t space f o r m u l a comma space w e space h a v e
h equals fraction numerator 2 cross times a plus 1 cross times 0 over denominator 1 plus 2 end fraction
a n d
k equals fraction numerator 2 cross times 0 plus 1 cross times b over denominator 1 plus 2 end fraction
T h e r e f o r e comma space w e space h a v e comma
h equals fraction numerator 2 a over denominator 3 end fraction space a n d space k equals b over 3
rightwards double arrow a equals fraction numerator 3 h over denominator 2 end fraction a n d space b equals 3 k
T h u s comma space t h e space c o r r e s p o n d i n g space p o i n t s space o f space A space a n d space B space a r e space open parentheses fraction numerator 3 h over denominator 2 end fraction comma 0 close parentheses space a n d space open parentheses 0 comma 3 k close parentheses
T h u s comma space t h e space e q u a t i o n space o f space t h e space l i n e space j o i n i n g space t h e space p o i n t s space A space a n d space B space i s
fraction numerator y minus 3 k over denominator 3 k minus 0 end fraction equals fraction numerator x minus 0 over denominator 0 minus fraction numerator 3 h over denominator 2 end fraction end fraction
rightwards double arrow minus fraction numerator 3 h over denominator 2 end fraction open parentheses y minus 3 k close parentheses equals x cross times 3 k
rightwards double arrow minus 3 h y plus 9 h k equals 6 k x
rightwards double arrow 2 k x plus h y equals 3 k h

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13

Solution 13

Question 14

Solution 14

Question 15

Solution 15

Question 16

Solution 16

Question 17

Solution 17

Question 18

Solution 18

Question 19

Solution 19

Chapter 23 The Straight Lines Exercise Ex. 23.7

Question 1(i)

Solution 1(i)

Question 1(ii)

Solution 1(ii)

Question 1(iii)

Solution 1(iii)

Question 1(iv)

Solution 1(iv)

Question 2

Find the equation of the line on which the length of the perpendicular segment from the origin to the line is 4 and the inclination of the perpendicular segment with the positive direction of x-axis is 300.Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Chapter 23 The Straight Lines Exercise Ex. 23.8

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13

Solution 13

Chapter 23 The Straight Lines Exercise Ex. 23.9

Question 1

Solution 1

Question 2(i)

Solution 2(i)

Question 2(ii)

Solution 2(ii)

Question 2(iii)

Solution 2(iii)

Question 2(iv)

Solution 2(iv)

Question 2(v)

Solution 2(v)

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Chapter 23 The Straight Lines Exercise Ex. 23.10

Question 1(i)

Solution 1(i)

Question 1(ii)

Solution 1(ii)

Question 1(iii)

Solution 1(iii)

Question 2(i)

Solution 2(i)

Question 2(ii)

Solution 2(ii)

Question 3(i)

Solution 3(i)

Question 3(ii)

Solution 3(ii)

Question 3(iii)

Solution 3(iii)

Question 4

Solution 4

Question 5

Solution 5

Question 6(i)

Solution 6(i)

Question 6(ii)

Solution 6(ii)

Question 6(iii)

Solution 6(iii)

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

 Question 10

Solution 10

Question 11

Solution 11

 Question 12

Solution 12

Question 13

Solution 13

Question 14

Solution 14

 Question 15

Solution 15

Question 16

Find the equations of the line passing through the intersection of the lines 2x + y = 5 and x + 3y + 8 = 0 and parallel to the line 3x + 4y = 7.Solution 16

Question 17

Find the equation of the line passing through the point of intersection of the lines 5x – 6y – 1 = 0 and 3x + 2y + 5 = 0 and perpendicular to the line 3x – 5y + 11 = 0.Solution 17

Chapter 23 The Straight Lines Exercise Ex. 23.11

Question 1(i)

Solution 1(i)

Question 1(ii)

Solution 1(ii)

Question 1(iii)

Solution 1(iii)

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Chapter 23 The Straight Lines Exercise Ex. 23.12

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13

Solution 13

Question 14

Solution 14

Question 15

Solution 15

Question 16

Solution 16

Question 17

Solution 17

Question 18

Solution 18

Question 19

Solution 19

Question 20

Solution 20

Question 21

Solution 21

Question 22

Solution 22

Question 23

Solution 23

Question 24

Solution 24

Question 25

Solution 25

Question 26

Solution 26

Question 27

Find the equation of the straight line passing through the point of intersection of the lines 5x – 6y – 1 = 0 and 3x + 2y + 5 = 0 and perpendicular to the line 3x – 5y + 11 = 0.Solution 27

Chapter 23 The Straight Lines Exercise Ex. 23.13

Question 1(i)

Solution 1(i)

Question 1(ii)

Solution 1(ii)

Question 1(iii)

Solution 1(iii)

Question 1(iv)

Solution 1(iv)

Question 1(v)

Solution 1(v)

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Chapter 23 The Straight Lines Exercise Ex. 23.14

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Chapter 23 The Straight Lines Exercise Ex. 23.15

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13

Solution 13

Question 14

Solution 14

Question 15

Solution 15

Chapter 23 The Straight Lines Exercise Ex. 23.16

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Find the ratio in which the line 3x + 4y + 2 = 0 divides the distance between the lines 3x + 4y + 5 = 0 and 3x + 4y – 5 = 0.Solution 6

Chapter 23 The Straight Lines Exercise Ex. 23.17

Question 1

Deduce the condition for these lines to form a rhombus.Solution 1

Question 2

Solution 2

Question 3

Solution 3

Chapter 23 The Straight Lines Exercise Ex. 23.18

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11

Solution 11

Question 12

Solution 12

Question 13

Solution 13

Consider the following figure:

T h e space e q u a t i o n space o f space A B space i s
y minus 2 equals 1 fifth open parentheses x minus 1 close parentheses
rightwards double arrow 5 y minus 10 equals x minus 1
rightwards double arrow x minus 5 y plus 9 equals 0
A n d space t h e space e q u a t i o n space o f space B C space i s
y minus 8 equals minus 5 open parentheses x minus 5 close parentheses
rightwards double arrow y minus 8 equals minus 5 x plus 25
rightwards double arrow 5 x plus y minus 33 equals 0

Chapter 23 The Straight Lines Exercise Ex. 23.19

Question 1

Solution 1

Question 2

Solution 2

Question 3

Solution 3

rightwards double arrow fraction numerator 6 x minus 21 y plus 33 plus 7 x plus 21 y minus 56 over denominator 3 end fraction equals 0
rightwards double arrow 6 x minus 21 y plus 33 plus 7 x plus 21 y minus 56 equals 0
rightwards double arrow 13 x minus 23 equals 0
rightwards double arrow 13 x equals 23

Question 4

Solution 4

Question 5

Solution 5

Question 6

Solution 6

Question 7

Solution 7

Question 8

Solution 8

Question 9

Solution 9

Question 10

Solution 10

Question 11

Solution 11

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