NCERT MCQ Questions for Class 6 Maths Chapter 11 Algebra with Answers. MCQ Questions for Class 6 Maths with Answers were prepared based on the latest exam pattern. We have provided Knowing Our Numbers Class 6 Maths MCQs Questions with Answers to help students understand the concept very well
MCQ
Question 1.
The rule, which gives the number of matchsticks required to make the matchstick pattern L, is
(a) 2 n
(b) 3 n
(c) 4n
(d) 5 n.
Answer
Answer: (a)
Question 2.
The rule, which gives the number of matchsticks required to make the matchstick pattern C, is
(a) 2 n
(b) 3 n
(c) 4 n
(d) 5 n.
Answer
Answer: (b)
Question 3.
The rule, which gives the number of matchsticks required to make the matchstick pattern F, is
(a) 2 n
(b) 3 n
(c) 4 n
(d) 5 n.
Answer
Answer: (c)
Question 4.
The rule, which gives the number of matchsticks required to make the matchstick pattern U, is
(a) 2 n
(b) 3 n
(c) 4 n
(d) 5 n.
Answer
Answer: (b)
Question 5.
The rule, which gives the number of matchsticks required to make the matchstick pattern V, is
(a) 2 n
(b) 3 n
(c) 4 n
(d) 5 n.
Answer
Answer: (a)
Question 6.
The rule, which gives the number of matchsticks required to make the matchstick pattern A, is
(a) 2 n
(b) 3 n
(c) 4 n
(d) 5 n.
Answer
Answer: (b)
Question 7.
The rule, which gives the number of matchsticks required to make the matchstick pattern [], is
(a) 2 n
(b) 3 n
(c) 4 n
(d) 5 n
Answer
Answer: (c)
Question 8.
The rule, which gives the number of matchsticks required to make the matchstick pattern ≅, is
(a) 2 n
(b) 3 n
(c) 4 n
(d) 5 n.
Answer
Answer: (a)
Question 9.
The rule, which gives the number of matchsticks required to make the matchstick pattern E. is
(a) 2 n
(b) 3 n
(c) 4 n
(d) 5n.
Answer
Answer: (d)
Question 10.
The rule, which gives the number of matchsticks required to make the matchstick pattern A, is
(a) 3 n
(b) An
(c) 5 n
(d) 6 n.
Answer
Answer: (c)
Question 11.
The rule, which gives the number of matchsticks required to make the matchstick pattern A, is
(a) 3 n
(b) 4 n
(c) 5 n
(d) 6 n.
Answer
Answer: (a)
Question 12.
The rule, which gives the number of matchsticks required to make the matchstick pattern S, is
(a) 3 l
(b) 4 n
(c) 5 n
(d) 6 n.
Answer
Answer: (c)
Question 13.
The side of a square is l. Its perimeter is
(a) 3l
(b) 2l
(c) 4l
(d) 6l
Answer
Answer: (c)
Question 14.
14. The side of an equilateral triangle is l. Its perimeter is
(a) l
(b) 2l
(c) 3l
(d) 6l.
Answer
Answer: (c)
Question 15.
The side of a regular pentagon is l. Its perimeter is
(a) 3l
(b) 6l
(c) 4l
(d) 5l
Answer
Answer: (d)
Question 16.
The side of a regular hexagon is l. Its perimeter is
(a) l
(b) 2l
(c) 3l
(d) 6l.
Answer
Answer: (d)
Important Questions
Question 1.
Six less than a number equals to two. What is the number?
Solution:
Let the number be ‘x’.
According to condition, we have x – 6 = 2
By inspections, we have 8 – 6 = 2
∴ x = 8
Thus, the required number is 8.
Question 2.
Write an algebraic expression for each of the following:
(a) 3 subtracted from a number y.
(b) 5 is added to three times a number x.
Solution:
(a) The required expression is y – 3
(b) The required expression is 5 + 3x
Question 3.
Write an algebraic expression for the following expressions:
(a) The sum of a number x and 4 is doubled.
(b) One fourth of a number x is added to one third of the same number.
Solution:
(a) The required expression is 2 x (x + 4)
(b) The required expression is 14x + 13x
Question 4.
Think of a number x. Multiply it by 3 and add 5 to the product and subtract y subsequently. Find the resulting number.
Solution:
Required number is (3x + 5)
Now we have to subtract y from the result i.e., 3x + 5 – y
Question 5.
Here is a pattern of houses with matchsticks:
Write the general rule for this pattern.
Solution:
One house is made of 6 matchsticks i.e. 6 x 1
Two houses are made of 12 matchsticks i.e. 6 x 2
Three houses are made of 18 matchsticks i.e. 6 x 3
∴ Rule is 6n where n represents the number of houses.
Question 6.
If the side of an equilateral triangle is x, find its perimeter.
Solution:
We know that the three sides of an equilateral triangle are equal.
∴ x + x + x = 3x.
Thus, the required perimeter = 3x units.
Question 7.
If x = 3, find the value of the following:
(i) x + 5
(ii) 2x – 3
(iii) x – 7
(iv) x3 – 1
Solution:
Given that x = 3
(i)x + 5 = 3 + 5 = 8
(ii) 2x – 3 = 2 x 3 – 3 = 6 – 3 = 3
(iii) x – 7 = 3- 7 = -4
(iv) x3 – 1 = 33 -1 = 1 – 1 = 0
Question 8.
If x = 2, y = 3 and 2 = 5, find the value of;
(a) 2x + y + z
(b) 4x -y + z
(c) x – y + z
Solution:
(a) Given that: x – 2, y = 3 and z = 5
∴ 2x + y + 2 = 2 x 2 + 3 + 5
= 4 + 3 + 5 = 12
(b) 4x – y + z = 4 x 2 – 3 + 5
= 8 – 3 + 5 = 5 + 5 = 10
(c) x – y + z = 2 – 3 + 5 = -1 + 5 = 4
Question 9.
State which of the following are equations with a variable?
(a) 12 = x – 5
(b) 2x > 7
(c) x2 = 5
(d) 5 + 7 = 3 + 9
(e) 7 = (11 x 5) – (12 x 4)
Solution:
(a) 12 = x – 5 is an equation with a variable x.
(b) 2x > 7 is not an equation because it does not have ‘=’ sign.
(c) x2 = 5 is an equation with a variable x.
(d) 5 + 7 = 3 + 9 is not an equation because it has no variable.
(e) 7 = (11 x 5) – (12 x 4) is not an equation because it has no variable.
Question 10.
Think of a number, add 2 to it and then multiply the sum by 6, the result is 42.
Solution:
Let the number be x.
∴ Sum of x and 2 = x + 2
Now by multiplying the sum by 6, we get
6 × (x + 2) = 42
⇒ 6 × x + 6 × 2 = 42
⇒ 6x + 12 = 42
By inspection, we get
6 × 5 + 12 = 42
⇒ 30 + 12 = 42
∴ 42 = 42
So, the required number = 5
Algebra Class 6 Extra Questions Short Answer Type
Question 11.
The side of a regular hexagon is s cm. Find its perimeter.
Solution:
Each side of a regular hexagon = s
∴ its perimeter = s + s + s + s + s + s = 6s cm
Question 12.
If a = 3, b = 12 and c = 14, find the value of
Solution:
Question 13.
Complete the table and find the solution of the equation 19 – x = 13
Solution:
By inspection, we have
Thus, the required solution is 6.
Question 14.
If x = –12, y = 14 and z = 0, find the value of the given expressions
(a) 8z + 2x -y
(b) z – y + 3x
Solution:
Question 15.
Fill in the blanks:
(a) 5 added to -5 = ……….
(b) If x = 3, then 3x – 5 = ……….
(c) If x = 1 and y = 2, then 2x + 3y = ……….
(d) If 10x – 6 = 14, then x = ……….
(e) 4 less than a number x = ……….
Solution:
(a) 0
(b) 4
(c) 8
(d) 2
(e) x – 4
Algebra Class 6 Extra Questions Higher Order Thinking Skills (HOTS)
Question 16.
A starts his car from Delhi at 6.00 am to Amritsar. The uniform speed of his car is x km/h. At 12.00 noon, he finds that he is still 50 km away from Amritsar. Find the distance between Delhi and Amritsar.
Solution:
Time taken by A to reach Amritsar = 12.00 noon – 6.00 am = 6 hour.
The uniform speed of the car = x km/ hr
∴ Total distance covered by A = Time x speed = 6x km.
∴ Distance between Delhi and Amritsar = (6x + 50) km.
Question 17.
Anshika’s Score in Science is 15 more than the two-third of her score in Sanskrit. If she scores x marks in Sanskrit, find her score in Science.
Solution:
Anshika’s score in Sanskrit = x
∴ Her marks in Science = 23x +15
∴ Thus, Anshika’s score in Science = 23x + 15